nm

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These are questions asked by nm

Any idea why this sometimes happens? odeadvisor says ode is quadrature but when asking it to solve it using quadrature sometimes it works and sometimes not.

Am I doing something wrong?

22020

interface(version);

`Standard Worksheet Interface, Maple 2024.0, Windows 10, March 01 2024 Build ID 1794891`

Physics:-Version();

`The "Physics Updates" version in the MapleCloud is 1754 and is the same as the version installed in this computer, created 2024, June 3, 20:39 hours Pacific Time.`

restart;

18368

Example 1 that does not work

 

ode:=diff(y(x),x)=-1;
DEtools:-odeadvisor(ode);

diff(y(x), x) = -1

[_quadrature]

sol:=dsolve(ode,y(x),['quadrature']);

"sol := "

Example 2 that works

 

ode:=diff(y(x),x)=x;
DEtools:-odeadvisor(ode);

diff(y(x), x) = x

[_quadrature]

sol:=dsolve(ode,y(x),['quadrature']);

y(x) = (1/2)*x^2+c__1

 

 

Download sometimes_dsolve_works_on_quadrature_june_5_2024.mw

Any one could find why Maple 2024 gives Error, (in evalf/int) invalid arguments on this ode? Why is it even calling evalf in first place as this is all symbolic.

Also reported to Maplesof just in case.

25504

restart;

25504

interface(version);

`Standard Worksheet Interface, Maple 2024.0, Windows 10, March 01 2024 Build ID 1794891`

Physics:-Version();

`The "Physics Updates" version in the MapleCloud is 1752 and is the same as the version installed in this computer, created 2024, May 31, 18:17 hours Pacific Time.`

ode:=diff(y(x), x)^3 = (x - 2)^2;
ic:=y(2)=1;
Student:-ODEs:-ODESteps([ode,ic]);

(diff(y(x), x))^3 = (x-2)^2

y(2) = 1

Error, (in evalf/int) invalid arguments

dsolve([ode,ic])

y(x) = 1+(1/5)*(3*x-6)*RootOf(_Z^3-x^2+4*x-4)

DEtools:-odeadvisor(ode)

[_quadrature]

 

 

Download odetest_internal_error_evalf_int_june_3_2024.mw

I wanted to do 

map(X->odetest(X,ode) assuming x>0,[sol]) 

where sol are the solutions I wanted to test. The above does not work as is. After some trial and errors, I found this works

map(X->[odetest(X,ode) assuming x>0],[sol]) 

I am not sure why. But it works. Is this the above the correct way to add assuming to a command inside Map? Or is there a different way or better way to do this?

I want to stick to the map command as above and nothing else such as ~ or some other ones. I find map more clear to use for me.

Here is worksheet.

9592

restart;

9592

ode:=x = diff(y(x), x)*sqrt(1 + diff(y(x), x)^2);

x = (diff(y(x), x))*(1+(diff(y(x), x))^2)^(1/2)

sol:=dsolve(ode);
map(X->[odetest(X,ode) assuming x>0],[sol])

y(x) = ((1/32)*I)*2^(1/2)*(-(256/3)*Pi^(1/2)*2^(1/2)*x^3*cosh((3/2)*arcsinh(2*x))-8*Pi^(1/2)*2^(1/2)*(-(64/3)*x^4-(8/3)*x^2+2/3)*sinh((3/2)*arcsinh(2*x))/(4*x^2+1)^(1/2))/Pi^(1/2)+c__1, y(x) = -((1/32)*I)*2^(1/2)*(-(256/3)*Pi^(1/2)*2^(1/2)*x^3*cosh((3/2)*arcsinh(2*x))-8*Pi^(1/2)*2^(1/2)*(-(64/3)*x^4-(8/3)*x^2+2/3)*sinh((3/2)*arcsinh(2*x))/(4*x^2+1)^(1/2))/Pi^(1/2)+c__1, y(x) = Int(-(1/2)*(-2+2*(4*x^2+1)^(1/2))^(1/2), x)+c__1, y(x) = Int((1/2)*(-2+2*(4*x^2+1)^(1/2))^(1/2), x)+c__1

[[(1/2)*(2*x*(4*x^2+1)^(1/2)+(-8*x^2*cosh((3/2)*arcsinh(2*x))*(4*x^2+1)^(1/2)+16*x^3*sinh((3/2)*arcsinh(2*x))-cosh((3/2)*arcsinh(2*x))*(4*x^2+1)^(1/2)+4*sinh((3/2)*arcsinh(2*x))*x)*(-2+2*(4*x^2+1)^(1/2))^(1/2))/(4*x^2+1)^(1/2)], [-(1/2)*(-2*x*(4*x^2+1)^(1/2)+(-8*x^2*cosh((3/2)*arcsinh(2*x))*(4*x^2+1)^(1/2)+16*x^3*sinh((3/2)*arcsinh(2*x))-cosh((3/2)*arcsinh(2*x))*(4*x^2+1)^(1/2)+4*sinh((3/2)*arcsinh(2*x))*x)*(-2+2*(4*x^2+1)^(1/2))^(1/2))/(4*x^2+1)^(1/2)], [2*x], [0]]

for item in [sol] do
    odetest(item,ode) assuming x>0;
od;

(1/2)*(2*x*(4*x^2+1)^(1/2)+(-8*x^2*cosh((3/2)*arcsinh(2*x))*(4*x^2+1)^(1/2)+16*x^3*sinh((3/2)*arcsinh(2*x))-cosh((3/2)*arcsinh(2*x))*(4*x^2+1)^(1/2)+4*sinh((3/2)*arcsinh(2*x))*x)*(-2+2*(4*x^2+1)^(1/2))^(1/2))/(4*x^2+1)^(1/2)

-(1/2)*(-2*x*(4*x^2+1)^(1/2)+(-8*x^2*cosh((3/2)*arcsinh(2*x))*(4*x^2+1)^(1/2)+16*x^3*sinh((3/2)*arcsinh(2*x))-cosh((3/2)*arcsinh(2*x))*(4*x^2+1)^(1/2)+4*sinh((3/2)*arcsinh(2*x))*x)*(-2+2*(4*x^2+1)^(1/2))^(1/2))/(4*x^2+1)^(1/2)

2*x

0

 

 

Download how_to_use_map_with_assuming.mw

These  are good example(s)  why I think Maple's simplify needs to be improved. 

Example 1

Given an expression which is zero for nonnegative x, one would expect simplify to simplify it to zero when told that x is positive. 

But nothing I tried with simplify worked. combine  figured it out.

But why? Is this not the job of simplify? 

The expression is 

e:=x-1/4*(-2+2*(4*x^2+1)^(1/2))^(1/2)*(2+2*(4*x^2+1)^(1/2))^(1/2);

Here is worksheet

``

interface(version);

`Standard Worksheet Interface, Maple 2024.0, Windows 10, March 01 2024 Build ID 1794891`

restart;

28000

e:=x-1/4*(-2+2*(4*x^2+1)^(1/2))^(1/2)*(2+2*(4*x^2+1)^(1/2))^(1/2);

x-(1/4)*(-2+2*(4*x^2+1)^(1/2))^(1/2)*(2+2*(4*x^2+1)^(1/2))^(1/2)

coulditbe(e=0);

true

#we see it is zero for x>=0
plot(e,x=-3..3)

simplify(e) assuming x>=0;

x-(1/4)*(-2+2*(4*x^2+1)^(1/2))^(1/2)*(2+2*(4*x^2+1)^(1/2))^(1/2)

simplify(e,size) assuming x>=0;

x-(1/4)*(-2+2*(4*x^2+1)^(1/2))^(1/2)*(2+2*(4*x^2+1)^(1/2))^(1/2)

expand(e) assuming x>=0;

x-(1/4)*(-2+2*(4*x^2+1)^(1/2))^(1/2)*(2+2*(4*x^2+1)^(1/2))^(1/2)

simplify(e,sqrt) assuming x>=0;

x-(1/4)*(-2+2*(4*x^2+1)^(1/2))^(1/2)*(2+2*(4*x^2+1)^(1/2))^(1/2)

simplify(e,symbolic) assuming x>=0;

x-(1/4)*(-2+2*(4*x^2+1)^(1/2))^(1/2)*(2+2*(4*x^2+1)^(1/2))^(1/2)

combine(e) assuming x>=0;

0


Compare some other software on this same problem

It should be as simple as the above in Maple.

A user should not have to try 100 different commands in Maple to find which works.

simplify should have done it in first place. What Am I overlooking here?

Maple 2024

Download why_simplify_do_not_work_example.mw

EXAMPLE 2

In this example the expression is zero for x<0. Here nothing worked for me. This is challenge for Maple experts here to find the command to simplify this to zero. 

I know it is zero for x<0.

e := -1/2*(-2*x*sqrt(4*x^2 + 1) + (16*x^3*sinh(3/2*arcsinh(2*x)) - 8*x^2*cosh(3/2*arcsinh(2*x))*sqrt(4*x^2 + 1) + 4*sinh(3/2*arcsinh(2*x))*x - cosh(3/2*arcsinh(2*x))*sqrt(4*x^2 + 1))*sqrt(-2 + 2*sqrt(4*x^2 + 1)))/sqrt(4*x^2 + 1)


 

24064

interface(version);

`Standard Worksheet Interface, Maple 2024.0, Windows 10, March 01 2024 Build ID 1794891`

Physics:-Version();

`The "Physics Updates" version in the MapleCloud is 1752 and is the same as the version installed in this computer, created 2024, May 31, 18:17 hours Pacific Time.`

e:=-1/2*(-2*x*sqrt(4*x^2 + 1) + (16*x^3*sinh(3/2*arcsinh(2*x)) - 8*x^2*cosh(3/2*arcsinh(2*x))*sqrt(4*x^2 + 1) + 4*sinh(3/2*arcsinh(2*x))*x - cosh(3/2*arcsinh(2*x))*sqrt(4*x^2 + 1))*sqrt(-2 + 2*sqrt(4*x^2 + 1)))/sqrt(4*x^2 + 1);

-(1/2)*(-2*x*(4*x^2+1)^(1/2)+(16*x^3*sinh((3/2)*arcsinh(2*x))-8*x^2*cosh((3/2)*arcsinh(2*x))*(4*x^2+1)^(1/2)+4*sinh((3/2)*arcsinh(2*x))*x-cosh((3/2)*arcsinh(2*x))*(4*x^2+1)^(1/2))*(-2+2*(4*x^2+1)^(1/2))^(1/2))/(4*x^2+1)^(1/2)

plot(e,x=-10..3);

coulditbe(e=0)

true

simplify(e) assuming x<0;

-8*((cosh((3/2)*arcsinh(2*x))*(-(1/2)*x^2-1/16)*(4*x^2+1)^(1/2)+sinh((3/2)*arcsinh(2*x))*x*(x^2+1/4))*(-2+2*(4*x^2+1)^(1/2))^(1/2)-(1/8)*x*(4*x^2+1)^(1/2))/(4*x^2+1)^(1/2)

simplify(e,symbolic) assuming x<0;

-8*((cosh((3/2)*arcsinh(2*x))*(-(1/2)*x^2-1/16)*(4*x^2+1)^(1/2)+sinh((3/2)*arcsinh(2*x))*x*(x^2+1/4))*(-2+2*(4*x^2+1)^(1/2))^(1/2)-(1/8)*x*(4*x^2+1)^(1/2))/(4*x^2+1)^(1/2)

combine(e) assuming x<0;

-(1/2)*(-2*x*(4*x^2+1)^(1/2)+(16*x^3*sinh((3/2)*arcsinh(2*x))-8*x^2*cosh((3/2)*arcsinh(2*x))*(4*x^2+1)^(1/2)+4*sinh((3/2)*arcsinh(2*x))*x-cosh((3/2)*arcsinh(2*x))*(4*x^2+1)^(1/2))*(-2+2*(4*x^2+1)^(1/2))^(1/2))/(4*x^2+1)^(1/2)

simplify(e,arctrig) assuming x<0;

-8*((cosh((3/2)*arcsinh(2*x))*(-(1/2)*x^2-1/16)*(4*x^2+1)^(1/2)+sinh((3/2)*arcsinh(2*x))*x*(x^2+1/4))*(-2+2*(4*x^2+1)^(1/2))^(1/2)-(1/8)*x*(4*x^2+1)^(1/2))/(4*x^2+1)^(1/2)

simplify(e,sqrt) assuming x<0;

-8*((cosh((3/2)*arcsinh(2*x))*(-(1/2)*x^2-1/16)*(4*x^2+1)^(1/2)+sinh((3/2)*arcsinh(2*x))*x*(x^2+1/4))*(-2+2*(4*x^2+1)^(1/2))^(1/2)-(1/8)*x*(4*x^2+1)^(1/2))/(4*x^2+1)^(1/2)

simplify(normal(e),sqrt) assuming x<0;

-8*((cosh((3/2)*arcsinh(2*x))*(-(1/2)*x^2-1/16)*(4*x^2+1)^(1/2)+sinh((3/2)*arcsinh(2*x))*x*(x^2+1/4))*(-2+2*(4*x^2+1)^(1/2))^(1/2)-(1/8)*x*(4*x^2+1)^(1/2))/(4*x^2+1)^(1/2)

simplify(normal(e, expanded)) assuming x<0;

-8*((cosh((3/2)*arcsinh(2*x))*(-(1/2)*x^2-1/16)*(4*x^2+1)^(1/2)+sinh((3/2)*arcsinh(2*x))*x*(x^2+1/4))*(-2+2*(4*x^2+1)^(1/2))^(1/2)-(1/8)*x*(4*x^2+1)^(1/2))/(4*x^2+1)^(1/2)

simplify(radnormal(e)) assuming x<0;

(1/8)*((4*x^2+(4*x^2+1)^(1/2)+1)*(-2+2*(4*x^2+1)^(1/2))-64*x*((1/2)*cosh((3/2)*arcsinh(2*x))*(-1/8-x^2)*(4*x^2+1)^(1/2)+sinh((3/2)*arcsinh(2*x))*x*(x^2+1/4))*(-2+2*(4*x^2+1)^(1/2))^(1/2))/((4*x^2+1)^(1/2)*x)

simplify(evala(e)) assuming x<0;

-8*((cosh((3/2)*arcsinh(2*x))*(-(1/2)*x^2-1/16)*(4*x^2+1)^(1/2)+sinh((3/2)*arcsinh(2*x))*x*(x^2+1/4))*(-2+2*(4*x^2+1)^(1/2))^(1/2)-(1/8)*x*(4*x^2+1)^(1/2))/(4*x^2+1)^(1/2)

 


Using some other software gives

I'd like to find command to do the same in Maple. i.e. simplify it to zero. What else to try?

 

Download why_simplify_do_not_work_example_2.mw

I think I found another problem with odetest.  When solution is implicit, it fails to verify the solution against the ode when adding the IC. (not everytime, but in some cases).

But it does verify the solution against the ode when IC is not given. I give 3 examples.  Also at bottom is worksheet of all of this.

Example 1

restart;

ode:=diff(y(x), x) = sin(y(x));
ic:=y(0)=Pi/2;
mysol:=ln(tan(y(x)/2))=x;

It says solution satisfies the ode itself OK

odetest(mysol,ode);

gives 0

But adding IC now gives

odetest(mysol,[ode,ic]);

Which I am having hard time reading. Is it now saying the solution does not satisfy the ode or the IC? Both are supposed to be zero.

Are these not supposed to be in same order given? so it looks like if we go left to right, it is saying the solution do not satisfy the ode now but it does satisfy the IC. Right?

But before it said the solution satisfies the ode.

Also, we can see the IC is satisfied. Let do it by hand

eval(mysol,[y(x)=Pi/2,x=0])

              0 = 0

So why does it say solution satisfies the ode first, then when adding the IC, now it changed its mind?

Also, solving for y(x) from the implicit solution, now it verifies it OK  with the IC also:

ode:=diff(y(x), x) = sin(y(x));
ic:=y(0)=Pi/2;
mysol:=ln(tan(y(x)/2))=x;
mysol_explicit:=solve(mysol,y(x));
odetest(y(x)=mysol_explicit,[ode,ic])

          [0, 0]

You see. Same solution. But different result from odetest depending if it is implicit or explicit.

Is this supposed to happen or is this a bug in odetest I should report? odetest is supposed to handle both explicit and implicit solutions. I know my solutions are correct. I just use odetest for verification. I also plotted my solution against maple's solutions and they are exact match. 

Example 2

ode:=diff(y(x),x)=1+y(x)^2;
mysol:=arctan(y(x))=x;
ic:=y(0)=0;
odetest(mysol,ode);
odetest(mysol,[ode,ic]);

Gives 0 for the first call to odetest but gives [diff(y(x), x) - 1 - y(x)^2, 0] for the second call.

Changing the solution to explicit. now it verifies it

mysol_explicit:=solve(mysol,y(x));
odetest(y(x)=mysol_explicit,[ode,ic]);

Now it gives [0,0]

Example 3

ode:=diff(y(x), x) - 2*y(x) = 2*sqrt(y(x));
ic:=y(0)=1;
mysol:=ln(sqrt(y(x))+1)=x+ln(2);
odetest(mysol,ode);
odetest(mysol,[ode,ic]) assuming positive;

Gives for the first call but  [diff(y(x), x) - 2*y(x) - 2*sqrt(y(x)), 0] but when using explicit it now verifies OK

mysol_explicit:=solve(mysol,y(x));
odetest(y(x)=mysol_explicit,[ode,ic]) assuming positive;

           [0, 0]

Maple 2024 on windows 10

23112

interface(version);

`Standard Worksheet Interface, Maple 2024.0, Windows 10, March 01 2024 Build ID 1794891`

Physics:-Version();

`The "Physics Updates" version in the MapleCloud is 1751 and is the same as the version installed in this computer, created 2024, May 31, 18:17 hours Pacific Time.`

Example 1

 

restart;

18420

ode:=diff(y(x), x) = sin(y(x));
ic:=y(0)=Pi/2;
mysol:=ln(tan(y(x)/2))=x;
odetest(mysol,ode);

diff(y(x), x) = sin(y(x))

y(0) = (1/2)*Pi

ln(tan((1/2)*y(x))) = x

0

odetest(mysol,[ode,ic]);

[diff(y(x), x)-sin(y(x)), 0]

mysol:=ln(tan(y(x)/2))=x;
mysol_explicit:=solve(mysol,y(x));
odetest(y(x)=mysol_explicit,[ode,ic]);

ln(tan((1/2)*y(x))) = x

2*arctan(exp(x))

[0, 0]

Example 2

 

ode:=diff(y(x),x)=1+y(x)^2;
mysol:=arctan(y(x))=x;
ic:=y(0)=0;
odetest(mysol,ode);

diff(y(x), x) = 1+y(x)^2

arctan(y(x)) = x

y(0) = 0

0

odetest(mysol,[ode,ic]);

[diff(y(x), x)-1-y(x)^2, 0]

mysol_explicit:=solve(mysol,y(x));
odetest(y(x)=mysol_explicit,[ode,ic]);

tan(x)

[0, 0]

Example 3

 

ode:=diff(y(x), x) - 2*y(x) = 2*sqrt(y(x));
ic:=y(0)=1;
mysol:=ln(sqrt(y(x))+1)=x+ln(2);
odetest(mysol,ode);

diff(y(x), x)-2*y(x) = 2*y(x)^(1/2)

y(0) = 1

ln(y(x)^(1/2)+1) = x+ln(2)

0

odetest(mysol,[ode,ic]) assuming positive;

[diff(y(x), x)-2*y(x)-2*y(x)^(1/2), 0]

mysol_explicit:=solve(mysol,y(x));
odetest(y(x)=mysol_explicit,[ode,ic]) assuming positive;

(2*exp(x)-1)^2

[0, 0]

 

 

Download odetest_implicit_problem_june_2_2024.mw

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