vhha1972

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11 years, 20 days

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These are questions asked by vhha1972

Hi there,

I am trying to do a Fourier transform of the function

f(t) = 3*cos(2000*Pi*t)

I use Fourier transform definition to solve the following integral in Maple:

Int(3*cos(2000*Pi*t)*exp(-(I*2)*Pi*f*t), t = -infinity .. infinity)

I get the answer as "undefined".

The correct answer is:

(3/2)*delta(f+1000)+(3/2)*delta(f-1000)

Thanks!

Vhha

 

I am evaluating the following integral:

Int(5*exp(t)*exp(-2*j*pi*f*t), t = -infinity .. 0)+Int(5*exp(-t)*exp(-2*j*pi*f*t), t = 0 .. infinity)

Maple gives the answer:

limit((5*(exp(-2*Pi*f*j*t+t)-1))/(2*Pi*f*j-1), t = -infinity)+limit(-(5*(exp(-2*Pi*f*j*t-t)-1))/(2*Pi*f*j+1), t = infinity)

How do I solve for the limits?

The answer is:

10/[1+(2*Pi*f)^2]

 

Vhha

I am trying to evaluate the following INTEGRAL:

Int(2*e^(-(2/7)*j*Pi*n*t), t = 4 .. 5)

Maple gives me the following ANSWER:

-(7*(-e^(-(8/7)*j*Pi*n)+e^(-(10/7)*j*Pi*n)))/(j*Pi*n*ln(e))

Everything is correct but there is a ln(e) in the denominator of the answer. And we know that ln(e) = 1. 

Why does Maple not simplify this and get rid of the ln(e) from the answer?

 

 

 

 

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