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Greetings. I have a question regarding the use of the Matrix Browser. I was experimenting with the Transpose function, trying to mimic the Matlab linear algebraic transpose. For a row Vector A, defined as: A=[0 1 2 3 4 5 6 7 ...] in Matlab A' will give me a column vector. 0 1 2 3 4 5 6 7 In Maple, ver. 11.02, using the Classic interface: >restart:with(LinearAlgebra): >A:=Vector[row]([0,1,2,3,4,5,6,7]); A := RTABLE(150962204,VECTOR([0, 1, 2, 3, 4, 5, 6, 7]),Vector[row]) >Transpose(A); RTABLE(151848540,MATRIX([[0], [1], [2], [3], [4], [5], [6], [7]]),Vector[column]) >A:=Vector[row]([0,1,2,3,4,5,6,7,8]); A := RTABLE(165031856,VECTOR([0, 1, 2, 3, 4, 5, 6, 7, 8]),Vector[row]) Now I right click on the output with 8 elements (0-7) and select Browse. I can see all the elements. If I add one more entry to A, and I repeat the above steps, the Browse output looks like a bunch of colored lines, similar to a spectrogram. Is this normal? When I tried it with the non-classic interface, it worked just fine, no colored lines, just the vector elements. While I am at it, I will ask another question. I am familiar with vector, Vector, matrix and Matrix and the difference between them, i.e table vs. rtable based systems. Expanding on the above example: >A:=Vector[row]([0,1,2,3,4,5,6,7,8,9,10,11,12]); A := RTABLE(165792172,anything,Vector[row],rectangular,Fortran_order,[],1,1 .. 13) Now I can view this using: >v1:=convert(A,vector); v1 := vector([0, 1, 2, 3, 4, 5, 6, 7, 8]) >v1; v1 Is there a better way to do this? Regards, Georgios Kokovidis Dräger Medical
algebra example convert interface linear

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