As I have recently learned, the environment variable 'Digits' controls the working precision and is therefore crucial for avoiding significant impacts of round-off error effects on floating point computations.

Moreover I discovered, that even when I set Digits to say 20, Explore is not affected.

Is there a way to control the working precision of the floating-point computations carried out by the Explore option?

Maple carries out the following solving task without any problems:

restart;
with(Statistics):
X1 := RandomVariable(Geometric(q)):
s1:=solve({mu=Mean(X1)},{q});

Anyway, when I add common assumptions (0<q, q<1), then Maple will not carry out the task:

restart;
with(Statistics):
X1 := RandomVariable(Geometric(q)) assuming 0<q, q<1:
s1:=solve({mu=Mean(X1)},{q});

Why is that the case?

I made a program that spits out and alpha and beta at the end of each procedure. What I need to do is assign each alpha and beta a unique name. IE, when it runs the procedure 1, I need it to name them alpha1 and beta1, then for proc2, alpha 2 and beta2. For as many times it needs to run through this process because it may go through proc1 more than once.

It seems I can't find the resource I need, just that one little tidbit in the help files. Any help would be...

dsys := {1/2*diff(theta(t),`$`(t,2))*cos(phi(t))+5/4*diff(theta(t),`$`(t,2))+5/4*diff(phi(t),`$`(t,2))+1/2*sin(phi(t))*diff(theta(t),t)^2, -1/2*mu(t)*sin(phi(t))*diff(theta(t),`$`(t,2))-diff(phi(t),`$`(t,2))+1/2*mu(t)*cos(phi(t))*diff(theta(t),t)^2+5/4*diff(mu(t),`$`(t,2))-150000000000/(1+exp(27.0-15*sin(theta(t))-15*sin(theta(t)+phi(t))))^2*cos(theta(t)+phi(t))*exp(27.0-15*sin(theta(t))-15*sin(theta(t)+phi(t))), (-1-mu(t)*sin(phi(t)))*diff(theta(t),`$`(t,2))-1/2*mu(t...

Hello,

I am new to Maple and I am interested to know what programming language Maple is written in - I mean the maths part of Maple of course and not the interface which appears to be in Java.

Thanks in advance,

Julien.

What is the Problem? Do not use SingularValues (A, output = ['list'])?
Some care in handling this command?

Hello,

I am tying to compute the wronskian of a set of functions. I loaded the LinearAlgebra package and still Maple won't recognize the following command:

wronskian(x, x^2, x^3)

Can anyone please help?

Thanks in advance,

Julien.

Hello,

I am new to Maple and would like to know how to recall the last expression in maple. Say I write "x^2 +2", then press enter and I then want to recall "x^2 +2" without retyping it. How do I do that? (I think I am in math mode using "xmaple".)

Thanks in advance,

Julien.

When integrating 1/x as int(1/x,x) the answer is ln(x) while it should be ln(abs(x)). How does one fixes this mistake?

Consider the following expression:

sCARA4 := -ln(-(mu/sigma^2)^(mu^2/(mu-sigma^2))*(sigma^2/mu)^(mu^2/(mu-sigma^2))+(sigma^2/mu)^(mu^2/(mu-sigma^2))*((exp(phi)*sigma^2+mu-sigma^2)*exp(-phi)/sigma^2)^(mu^2/(mu-sigma^2))+1)/phi;

Now try to find out whether the first derivative to mu is positive for all positive mu, phi and sigma, except for some rare exceptions (e.g. sigma^2=mu).

diff(%,mu);

Since 'is' is not a satisfying option, I used 'Explore'...

hi

please help me to solve this error.

Error.pdf 

Hey everyone.  I'm having problems solving a set of complicated PDEs.  I found a question before that helped me a bit, but the answer was less than ideal.

Here is what I have so far.

pde := [-1/4*Gamma*(Gamma-2)/r^2*G(v,r)+1/r^3*j[v](v,r)*Gamma-1/r*diff(h[vv](v,r),r)-1/r^2*h[vv](v,r)+1/2*1/r^2*diff(j[v](v,r),r)*Gamma = 0, 1/4*f(r)*Gamma*(Gamma-2)*G(v,r)/r^2+1/r*f(r)*diff(h[vv](v,r),r)+1/r*diff(h[vv](v,r),v)-1/r^2*f(r)*diff(j[v](v,r),r)*Gamma-1/r^2*diff(j[v...

maple_error.doc

Hello,

I have a plane x+2*y+3*z = 0 and a point A(1,2,3).

From A there are 3 lines :

P := (1, 2, 3) P1 := (-1, -1, 0) L1 := P+t*(P1-P)

How to find the cutting points between L1 and the above plane?

How to find a cutting points between planes? 2 3 4 planes etc.

It is urgent, please help me!

How do you map b into a to get [[a1,a2,b1],[a3,a4,b2],[a5,a6,b3]]

a:=[[a1,a2],[a3,a4],[a5,a6]]
b:=[b1,b2,b3]