I have a question:

let t(n)=sum( (binomial(n,j))^4, j=0..n )  , t(-1)=0, t(0)=1

and (n+1)^3 *t(n+1)=(2n+1)*(a*n^2+a*n+b)*t(n)+n*(c*n^2+d)*t(n-1)             (1)

I want to Print(a,b,c,d) so that t(n) satisfies the recurrence relation (1)  where a,b,c,d are integers and their ranges are from

-30 to 30.

Please help!

Could you tell me how to write the following surface integral in Maple, please?

(This question applies to the Win32 version of Maple 15.)

I've got a python wrapper for the OpenMaple interface, and I've managed to get most of the callback functions in the MCallBackVector structure passed in to StartMaple to work, but I've never (ever) seen the queryInterrupt callback called.

To investigate this, I modified the 'omexample.c' example (found in the <Maple install Dir>\samples\OpenMaple\cmaple directory installed with the product...

Hi,

when i tried to solve the following equation, i received ""Warning, solutions may have been lost"":

a := [1,1,1,2,2,3];

number of appearance of 1 is 3

number of appearance of 2 is 2

number of appearance of 3 is 1

any short code can count this

I have a question about the different possibilities for calling a little used function from a package. It seems that there are three ways to do that:

1) Load the package and use te short form of the call e.g.
> with(combinat);
>randperm(5);

2) just load the command e.g.

>with(combinat,randperm);
>randperm(5);

3) use the long form of the call e.g.

>combinat[randperm](5)

4) with the use command e.g.

Hello,

I have a .dat file with three colluns, namely E,  a and b and N rows. The objective is to compute a function of a, b and a given value K F(a,b,K).  I would like to write a maple code that read the element in the first colum, E. If  E is lower or equal to a given value K, than we compute a term of f(a,b,K). After check the N rows, F(a,b,K) = sum(f(a,b,K)). I am new to maple, so I can`t figure out how to write this function.

I have these two procedures which produce 2/3 parts of my snowflake. But HOW do I angle them to put them together? Or should I modify one to cover the entire snowflake? If so, how should I modify my procedure?

This produces an "up right" fractal of a shape basically like this:   __/\__

Koch:=proc(n::posint)    
  if (n=1) then return("F"); fi;
 ## now n>1
  return( cat( " ",Koch(n-1), "L", Koch(n-1...

Below is my code for solving a solution of three first order ODEs using the 4th-order Runge-Kutta method.

I have been able to successfully plot the solutions of each of the ODEs (x,y,z) against time t, however I am struggling to produce a plot in the three dimensional phase domain of x,y,z. Could anybody suggest what commands to use as everything I have tried (plot, plot3d, implicitplot3d etc) has produced an error. 

h:= 0.01:
N:= 200:
x:=Vector(N+1):

if given a permutation group

1 2 3

2 1 3

How to calculate the cycle factorization and type of permutation group f in polya counting in maple

with(Statistics):

F := ((1/6)*z+(1/3)*z^2)/(1+(1/6)*z+(1/3)*z^2);

Dist := subs(z=t,F);

RealDist := Distribution(CDF = unapply(Dist(t-1),t)); # using this Distribution for Maple DistributionX:=RandomVariable(RealDist); # Random Variable

Pgraph := DensityPlot(X, range = -1 .. 1);

A := Sample(X, 1):

when i look help example, it has a very high range 3500,

when i want to change the range to small , it run very long time at Sample function like endless

F := ((1/6)*z+(1/3)*z^2)/(1+(1/6)*z+(1/3)*z^2);

Dist := subs(z=t,F);

RealDist := Distribution(CDF = unapply(Dist(t-1),t));

X:=RandomVariable(RealDist);

CommonDensity := PDF(X,t);

F do not have D(t) but density have D(t) , what is D(t)?

i have this:

u:=[a=x,b=w];

p:=[1=4,3=2,5=2];

How can I write a procedure which produces following:

[u(a)=x,u(b)=w],[p(1)=4,p(3)=2,p(5)=2]

Problem is extracting and then using variable name inside the printing. regards

So, I have to minimize only one variable, but with totally insane constraints. For simplicity, I want to solve it only for n=4 and specific graph, so it will be a little bit easier than described below.

1n is a column of "1".
So, is it possible at all? I spent almost 5 hours, tried everything that is possible to google, but still can't run it. Here is what I've done(as 'D' is reserved, I used 'B' instead):