restart:
with(LinearAlgebra):
A:=RandomMatrix(3,2, generator=1..3);

                               [1   1]
                               [       ]

> A:=Matrix([[1,2,2,3],[5,1,0,4],[6,7,3,4]]);
> V:=<6,5,9>;
                            

I want to add vector V as a new column [e.g. 3rd column] in matrix A, is there any function to do that simply? What abt to add as a row?

Hi!

I have the follwing problem. I have the matrix

B C F G 7    8    9  
0  1 2 3 21 22  23

And each input of the 1st line should result in the 2nd line. E.g. Input B, should result Output  0 or Input 8 should result 22. I mean the analog function in Excel: vlookup

Is that possible?

Thank you!

Johann

Good Evening,

Would anybody please tell me what I'm doing wrong in the attached Maple worksheet. My first problem is to sum a vector and divide by the nops(x) to determine the CG of a pile group.

My second problem is a For loop with units at the bottom of the page. Please Help.

Regards,

Moses

It took me a couple of days just to write the below Maplet code which loads a CSV file (time series organized in

columns where the first column is date/year etc and first row contain the names of the stocks)

and displays the stock names in a dropdownbox. Now I want to plot my selection from my dropdownbox

but now I have a new problem. When I include the "onchange = AC"

command in the drop1 command line in order to update my selection from the dropdownBox

I get an error message :

HI all,

Thanks in advance for having a look at this topic.

I have problems with finding the inverse function for this equation

(10088-10088*exp(-x))/(72*x+76)/((1-exp(-x))/x+10088/3/(72*x+76)-1)

A solution exists for the range that I am interested in x>0.5  However I can not get an output for the inverse function even when assuming x>1

I am not very experienced in Maple so perhaps I am doing a small thing wrong. Any help on this would be highly appreciated!

I want to retrieve data from google finance to do some analysis. Since the amount of data pieces are very huge. To aviod a huge amount of copy and past operations, I need to do it automatically in maple. So my question is how can I reduce the work in Maple as much as possible? I know google offers some APIs for retrieving data. Can I utilize that in Maple?

I want to get the length of a list. Is there any command available for that? For example, I want it return 2 for the list [8374, 32875], since it has two items.

I type in:

--------------------------------------------------------------------

RET := λbar*R :

RET[Sigma] := cos(RET)+RET*sin(RET):

C6[Sigma]+(C3[Sigma]*RET[Sigma])^2/(4*De);

--------------------------------------------------------------------

It displays fine on my GUI, but when I copy and paste it into a text editor I get:

RET := λbar*R :

RET[Sigma] := cos(RET)+RET*sin(RET):

C6[Sigma]+(C*3[Sigma]*RE*T[Sigma])^2/(4*De);

--------------------------------------------------------------------

M:=Matrix([[1,2,2],[3,2,0],[4,5,7],[8,3,5]]);

I want to pick the 2nd column (and/or row) from the above matrix and put the values into a vector, how can I do this?

results:

V1=[3,2,0]

V2=[2,2,5,3]

I want to build a list or vector out of 2 vectors containing values and 2 lists containing the order in the total list (or vecotr), I was wondering if there is a very simple way to do this instead of using loops?

NbNode:=6;
These are values:
U:=<1,2,2,3>;
UElim:=<0,5>;

And these are orders:
Elim:=[2,4];
ListEqn:=[seq( i, i=1..NbNode )]:
ListEqn:=subsop(seq(i=NULL, i in Elim), ListEqn);

The final result should be:

Utot=[1,0,2,5,2,3]

 

why doesn't "coeff" command work on this equation?

f=zin-z2(z3(z1(zin+I*z1*tan(beta1*d1))+I*z3*(tan(beta3*d3))(z1+I*zin*tan(beta1*d1)))
+I*z2*(tan(beta2*d2))(z3*(z1+I*zin*tan(beta1*d1))+I*z1(zin+I*z1*tan(beta1*d1))*tan(beta3*d3)))/(z2(z3(z1+I*zin*tan(beta1*d1))
+I*z1(zin+I*z1*tan(beta1*d1))*tan(beta3*d3))+I*z3(z1(zin+I*z1*tan(beta1*d1))+I*z3*(tan(beta3*d3))(z1+I*zin*tan(beta1*d1)))*tan(beta2*d2))

a0 := coeff(f, zin, 2);
b0 := coeff(f, zin, 1);
c0 := coeff(f, zin, 0);

restart:
A:=Vector(<2*u[1]+u[2],3*u[1]+u[3],5*u[2]-u[3]>);
U:=<1,2,3>;
for i to 3 do
A:=eval(A,u[i]=U[i]);
od;

How can I do this in a simpler and faster way? I will do this procedure for many times with larger vecotors and matrices.

TIA