#30

llvll=3              u=<4,-4>

-Find the magnitude of the given vector and divide each of the components by that magnitude. That will produce a unit vector that is the same direction of the given vector. Since it wants the magnitude to be equal to 3, multiply each component by 3. Make sure the radicans are out of the denominator. The answer should be a vector in component form.

 

#48

llvll=3            u=3i+4j

I am trying to find the stationary ponts of f(x,y) 5*x^3-12*x-3*x*y+6*y^2-4;

so far, I have got

A:=diff(f,x)=0

B:=diff(f,y)=0

e1:=RootOf(A,x)

e2:=RootOg(B,x)

G:=solve([A,B],[x,y])

do I now need to use allvalues?

 

if so, I get

 

V:=allvalues(G). This gives me two values of x and y.  (one with a positive root and one with a negative root)

ie. v=[[x=c - sqrtb,y=4c - 4sqrtb],[x=c+sqrtb,y=4c+4sqrtb]]

r:=diff(f,x$2) =30x

s:=diff(f,x,y) = -3

I am trying to find the stationary ponts of f(x,y) 5*x^3-12*x-3*x*y+6*y^2-4;

so far, I have got

A:=diff(f,x)=0

B:=diff(f,y)=0

e1:=RootOf(A,x)

e2:=RootOg(B,x)

G:=solve([A,B],[x,y])

do I now need to use allvalues?

 

if so, I get

 

V:=allvalues(G). This gives me two values of x and y.  (one with a positive root and one with a negative root)

ie. v=[[x=c - sqrtb,y=4c - 4sqrtb],[x=c+sqrtb,y=4c+4sqrtb]]

r:=diff(f,x$2) =30x

s:=diff(f,x,y) = -3

hey there! I was woundering.. What is the command for an ordinary plot, to lable the points on the x-Axes at points, like π, 2π, 3π and so forth. It would be very usefull for plots of trigonometric functions. I didn't find the option in the Help page. What i found, is the option by right clicking on the plot - but it is greyed out most time, and i would like to know the command anyway, so it would allways plot right, when i re-execute the Maple document. cheers!

I need to solve this by using polar form.

(2-5*i)^12/(4+i)^11

I found polar in the help section and used it like this:

polar((2-5*I)^12/(4+I)^11);

Is that it or is there something else I need to do?

I am using Maple 12.01 and I am using dsolve to solve a second order ODE;  example :

eq:=diff(y(t),t,t)+sin(t)*diff(y(t),t)+y(t)^2-5*y(t)=0;

ic:=a->[D(y)(0)=0,y(0)=a]; # initial conditions.
 

I want to investigate the  values of z(t, y, y') when g(t, y,y') = 0. Here z might be y''' or cos(t y') and g  might be y(t)-4.

What I would like to do is create an Array whose nth entry is of the form [ tn, z(tn,y(tn), y'(tn)]  where tn is the nth value of t at which the condition g(t, y,y') = 0 is satisfied.

Hi all,

I am assuming this is a pretty easy thing to do. I am solving a system of differential equations, and then want to export my results to maple. I basically want the solution to the system for 40 time steps (counting by 5).

By hand this is

I want to compute Hankel transforms with Maple.

I have noticed that Maple uses a different Hankel transform than the one in e.g. Bracewell (p335).

Maple computes

Integral{f(t)*Jn(s*t)*sqrt(s*t)dt, t:0->inf},

while I want to compute

Integral{f(t)*Jn(s*t)*t dt, t:0->inf}.

How can I compute the Hankel transform below with Maple?

 

Anyone know how to install Atlas (differential geometry package)? The terse instructions included apply to Windows only. e.g., it says put some files in the 'lib' directory. There is no lib directory. Feeling cheated...

I start by running microsofts free SQL Server Express 2005 (Microsoft SQL Server Management Studio Express) where my

data base UK-100-1SQL is located.

 

I run the following code in Maple :

 

Please help me how can i find nth derivative of

1/(1+x^2)

when i do

diff(1/(1+x*x), `$`(x, n))

maple gives

diff(1/(1+x^2), `$`(x, n))

even if i do

value(%)

maple still gives the same answer.

thanks

I am creating 2-d plots and exporting them in .eps format using Maple 10.  I've figure out how to change the thickness of the lines in the plot, but the the axes and tickmarks are still too thin.  I tried

plot(x^2, x=-1..1, axis=[thickness=2]);

however this does not seem to work, although a similar expression does change the thickness of the grid lines:

plot(x^2, x=-1..1, axis=[gridlines=[thickness=2]]);

 

There has to be a simple solution to this, and any suggestions are appreciated, Thanks in advance

I am having a problem with my loop. It only gives me one result.

In this program when i enter the initial values [B,C] it works and gives me an approximation. It then askes me if i want to find another root when i press "Y", it asks for the new values but when i insert the new values it does not evaluate them. It returns the previous result.

Is it possible to display the value of each contour line when using contourplot to plot contour lines? And how? Thanks.  

Something like this: