Maple Questions and Posts

These are Posts and Questions associated with the product, Maple

I have a function e^(-\lambda z \sqrt(x^2 + y^2)), is it possible to use Maple to find some sequence of derivatives wrt to x and y which could be applied to this function to get

(z/(1+2*sqrt(x^2 + y^2)*lambda))*e^(-\lambda z \sqrt(x^2 + y^2))

 

 

Any maple built-in function can find the possible numbers when modular a fixed number? 

For example, 

(x&^3+y) mod 124 = 123 mod 124

Find the possible values of x and y. 

for i from 1 to numelems(X) do    
    A := x:
    B := C;
end;

 

maple will print all statements even though I use the colon to try to suppress the first line. This just seems wrong. If I suppress the entire loop I have to use prints, and if I have a lot of statements I have to do it for every one even if I just want to supress 1.

It seems maple is suppose to suppress but it isn't.

One problem I come across far to often is that if maple get's bogged down in a computation or I screwed something up I can't always stop it. Sometimes the red ! is greyed out and I have to kill the mserver. When I do this I get the error that I need to save but save doenst' work and I can't do anything because the the kernel was killed. Maple doesn't seem to be able to properly recover... even though it does it most of the time when I click on the red !.

 

Is there any way around this?

 

I get tired of having to resize my plots constantly so I can get a nicer view.

 

setPlotSize:=proc(P,sz::[posint,posint])
  op(0,P)(remove(type,[op(P)],'specfunc(ROOT)')[],
          ROOT(BOUNDS_X(0),BOUNDS_Y(0),
               BOUNDS_WIDTH(sz[1]),BOUNDS_HEIGHT(sz[2])));
end proc:

 

This let's one set the size(mine is usually 1200x500) but I have to stick it in every plot.

 

Is there a way to override the plot functions to automatically do this for every plot or create a simple short option to scale it to the window size or some specific size?

 

I could probably make a simple function like RPF()

 

that I can wrap every plot but I'd like to avoid that step and just apply it to all plots by default(since 99% of the time I have to scale them.

 

 

 

Something really weird is going on when I build a MultiSet in two different ways, using the "+" operation.  The two constructions give the same MultiSet (since U=V), but in some mysterious way they are not really equal (since X=Y is false).  Does anyone know how to avoid this?  Should the "+" operator be avoided altogether?

There is more:  I tried saving the values of X and Y using the command:  save X, Y, "anomaly.m" 

When I tried reading it with the command:  read "anomaly.m"
I got the error message:  "Error, could not open `anomaly.m` for reading".

Thanks!
 

restart

 

U := MultiSet(3 = 1)+MultiSet(4 = 1)

module MultiSet () local instance, hash, generalized; option object; end module

(1)

V := MultiSet(3 = 1)+MultiSet(4 = 1)

module MultiSet () local instance, hash, generalized; option object; end module

(2)

evalb(U = V)

true

(3)

X := [2, 7, U]; Y := [2, 7, V]

[2, 7, module MultiSet () local instance, hash, generalized; option object; end module]

 

[2, 7, module MultiSet () local instance, hash, generalized; option object; end module]

(4)

evalb(X = Y)

false

(5)

seq(evalb(X[i] = Y[i]), i = 1 .. 3)

true, true, true

(6)

``


 

Download Anomaly.mw

Hi everyone:

How can I re-write the EQ with transformation       s=1+2*((tau-t)/T0)    ?

EQ:=int(f1(t-tau)*(Sum(y[k]*F[k](tau), k = 0 .. M)), tau = t-T0 .. t)

tnx...

Hi,

How can I force the command InsertContent(Worksheet(Group(Input( T )))) to display the variable eq as it appears in label (2) ?

(a screen capture of the output of InsertContent(Worksheet(Group(Input( T )))) is given after the Maple code)

restart:

interface(version)

`Standard Worksheet Interface, Maple 2015.2, Mac OS X, December 21 2015 Build ID 1097895`

(1)

with(DocumentTools):

with(DocumentTools[Layout]):

eq := piecewise(t < 1, sin(t), cos(t));

C := Cell( Textfield(style=TwoDimOutput,Equation(eq)) ):
T := Table(Column(), widthmode=percentage, width=40, Row(C)):
InsertContent(Worksheet(Group(Input( T )))):

eq := piecewise(t < 1, sin(t), cos(t))

(2)

 



Download Layout.mw

Hi!

There is a (relatively) known software code (written in C), called ." GKLS-generator" or "GKLS" to generate, according to certain user paramenters, optimization test functions. The code is available for free at the web

http://wwwinfo.deis.unical.it/%7Eyaro/GKLS.html

The download with the files of the GKLS is the following:  download

I would like to write this code in Maple. In the attached zip there is a PDF explaining how to build these functions. For now, I tried the follwoing Maple code GKLS_v4.mw

I think I'm doing something wrong, since the drawing generated by the attached Maple does not look much like the PDF in the attached zip (Fig. 1 of page 8).

Please, Can you help me with this?

Many thanks in advance for your comments.

 

 

I was trying to display a Physics[Vectors] vector name in a 3dplot with an up arrow
on it. I found that this old 2008 trick still works in MAPLE 2018.

 


 

restart;

with(plots):
with(Physics[Vectors]):

# Using MAPLE 2018.2

a:=arrow([-1,1,1],view=[-1.5..1.5,-1.5..1.5,-1.5..1.5]):

v_;
t:= textplot3d([-1.1,1.1,1,v_]):
display(a,t);

v_

 

 

# I found this on an old 2008 post
t:= textplot3d([-1.1,1.1,1,typeset(`#mover(mi(` || v ||  `),mo("→"))`)]):
display(a,t);

 


 

Download VectorTypeSetting.mw

Hello

I have problem with Maple that is not simplifying equation completly:

My simplified equation:

1/u * (z - F__n1*sin(alpha__n1)*a*b*c*d + F__n2*sin(alpha__n2)*a*b*c*d + F__n3*sin(alpha__n3)*a*b*c*d)

 

It`s sum of F__n1*sin(alpha__n1)*a*b*c*d for example 20 elements and only n is increasing so why maple will not move a,b,c,d ahead parenthesis ?

 

Application of MapleSim in Science and Engineering: a simulationbased approach

In this research work I show the methods of embedded components together with modeling and simulation carried out with Maple and MapleSim for the main areas of science and engineering (mathematics, physics, civil, mechanical etc); These two latest scientific softwares belonging to the company Maplesoft. Designed to be generated and used by teachers of education, as well as by university teachers and engineers; the results are highly optimal since the times saved in calculations are invested in analyzes and interpretations; among other benefits; in this way we can use our applications in the cloud since web technology supports Maple code with procedural and component syntax.

FAST_UNT_2020.pdf

kinematics_curvilinear_updated_2020.mw

Lenin AC

Ambassador of Maple

Hi User!

Hope you would be fine with everything. I have a vector "POL" of M dimension obatined for the following expression

restart; with(LinearAlgebra); nu := 1; M := 3;
for k while k <= M do
Poly[k] := simplify(sum(x^i*GAMMA(nu+1)/(factorial(i)*GAMMA(2*nu)), i = 0 .. k-1))
end do;
POL := `<,>`(seq(Poly[k], k = 1 .. M))

and I want to construct a matrix of M by M by collocating it on the points x=i/(M-1) for i=0,1,2,...,M-1 like the following way,

For M=3 I need

Matrix(3, 3, {(1, 1) = Poly[1](0), (1, 2) = Poly[1](1/2), (1, 3) = Poly[1](1), (2, 1) = Poly[2](0), (2, 2) = Poly[2](1/2), (2, 3) = Poly[2](1), (3, 1) = Poly[3](0), (3, 2) = Poly[3](1/2), (3, 3) = Poly[3](1)});

For M=4 I need

Matrix(4, 4, {(1, 1) = Poly[1](0), (1, 2) = Poly[1](1/3), (1, 3) = Poly[1](2/3), (1, 4) = Poly[1](1), (2, 1) = Poly[2](0), (2, 2) = Poly[2](1/3), (2, 3) = Poly[2](2/3), (2, 4) = Poly[2](1), (3, 1) = Poly[3](0), (3, 2) = Poly[3](1/3), (3, 3) = Poly[3](2/3), (3, 4) = Poly[3](1), (4, 1) = Poly[4](0), (4, 2) = Poly[4](1/3), (4, 3) = Poly[4](2/3), (4, 4) = Poly[4](1)})

 

and general form is like this

[[[Poly[1](0/(M-1)),Poly[1](1/(M-1)),Poly[1]((2)/(M-2)),...,Poly[1]((M-1)/(M-1))],[Poly[2](0/(M-1)),Poly[2]((1)/(M-1)),Poly[2]((2)/(M-1)),...,Poly[2]((M-1)/(M-1))],[Poly[3]((0)/(M-1)),Poly[3]((1)/(M-1)),Poly[3]((2)/(M-1)),...,Poly[3]((M-1)/(M-1))],[...,...,...,...,...],[Poly[M]((0)/(M-1)),Poly[M]((1)/(M-1)),Poly[M]((2)/(M-1)),...,Poly[M]((M-1)/(M-1))]]];

Another problem is I want to define a vector of M dimension using a function f(x)=sin(x) and two points a=1, b=2 like the following way,

Vec:=[[[a],[f((1)/(M-1))],[f((2)/(M-1))],[f((3)/(M-1))],[...],[f((M-1)/(M-1))],[b]]]
Please fix my problem. I'm waiting for your kind response.
Special request @acer @acer @Carl Love @Kitonum @Preben Alsholm

Dear Users!

Hope you would be fine with everything. I want the simpliest for of the following expression in two step:

diff(U(X, Y, Z, tau), tau)+U(X, Y, Z, tau)*(diff(U(X, Y, Z, tau), X))+V(X, Y, Z, tau)*(diff(U(X, Y, Z, tau), Y))+W(X, Y, Z, tau)*(diff(U(X, Y, Z, tau), Z))+u[delta]*lambda[1]*(diff(U(X, Y, Z, tau), tau, tau))/L[delta]+u[delta]*lambda[1]*(diff(U(X, Y, Z, tau), tau))*(diff(U(X, Y, Z, tau), X))/L[delta]+u[delta]*lambda[1]*U(X, Y, Z, tau)*(diff(U(X, Y, Z, tau), tau, X))/L[delta]+u[delta]*lambda[1]*(diff(V(X, Y, Z, tau), tau))*(diff(U(X, Y, Z, tau), Y))/L[delta]+u[delta]*lambda[1]*V(X, Y, Z, tau)*(diff(U(X, Y, Z, tau), tau, Y))/L[delta]+u[delta]*lambda[1]*(diff(W(X, Y, Z, tau), tau))*(diff(U(X, Y, Z, tau), Z))/L[delta]+u[delta]*lambda[1]*W(X, Y, Z, tau)*(diff(U(X, Y, Z, tau), tau, Z))/L[delta];
Step 1:
diff(U(X, Y, Z, tau), tau)+U(X, Y, Z, tau)*(diff(U(X, Y, Z, tau), X))+V(X, Y, Z, tau)*(diff(U(X, Y, Z, tau), Y))+W(X, Y, Z, tau)*(diff(U(X, Y, Z, tau), Z))+u[delta]*lambda[1]*(diff(diff(U(X, Y, Z, tau), tau)+U(X, Y, Z, tau)*(diff(U(X, Y, Z, tau), X))+V(X, Y, Z, tau)*(diff(U(X, Y, Z, tau), Y))+W(X, Y, Z, tau)*(diff(U(X, Y, Z, tau), Z)), tau))/L[delta];
Step 2: (final form I need)
(1+(u[delta] lambda[1])/(L[delta]) (&PartialD;)/(&PartialD;tau)) ((&PartialD;)/(&PartialD;tau) U(X,Y,Z,tau)+U(X,Y,Z,tau) ((&PartialD;)/(&PartialD;X) U(X,Y,Z,tau))+V(X,Y,Z,tau) ((&PartialD;)/(&PartialD;Y) U(X,Y,Z,tau))+W(X,Y,Z,tau) ((&PartialD;)/(&PartialD;Z) U(X,Y,Z,tau)));
I'm waiting for your response.
Special request:
@acer @Carl Love @Kitonum @Preben Alsholm

I'm fairly new to using Maple and am having a bit of a hard time calculating the following inner product. Firstly, I define the tensors (which to this end I'm not certain they are correctly defined), 

with(Physics):

Setup(mathematicalnotation=true)

Setup(coordinatesystems=spherical):

ds2 := - dt^2 + a(t)^2 /( 1-k*r^2)*dr^2 + a(t)^2*r^2*dtheta^2 + a(t)^2*r^2*sin(theta)^2*dphi^2;
Setup(coordinates = spherical, metric = ds2);

e[mu, `~nu`] = Matrix(4, {(1,1)= a(t)/sqrt(1-k*r^2), (2,2)=a(t)*r, (3,3)=a(t)*r*sin(theta), (4,4)=1}, fill=0); (15) 
Define((15))
f[`~mu`, nu] = Matrix(4, {(1,1)=sqrt(1-k*r^2)/(a(t)), (2,2)= 1/(a(t)*r), (3,3)=1/(a(t)*r*sin(theta)), (4,4)=1}, fill=0); (28)
Define((28))

Thus, I defined two mixed tensors e[mu, `~nu`] (one covariant and one contravariant index ) and f[`~mu`, nu] (one contravariant and one covariant index).

Then, I try to take the following inner product between the two mixed tensors and the Christoffel symbols of the second kind, namely,

e[nu, `~alpha`].f[`~sigma`, beta].Christoffel [`~nu`, sigma, mu];

where I used the Physics['.'] command . However, when I try taking this inner product, it returns unevaluated.

 

Did I define the mixed tensors incorrectly? Does it matter how you define the indices when you're gonna take the inner product? Because taking the inner product of simply e[mu, `~nu`].f[`~mu`, nu] also returns unevaluated. Also, I should mention that  e[mu, `~nu`] and f[`~mu`, nu] are inverses of each other, is there any way to define one and get the other, since, simply changing the way in which the indices are raised and lowered doesn't take the reciprocal of the components. 

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