how I can write a program code for newmark method.

in this method time has 3 order derivation

I have made a table and did a programme to do calculations inside.

While converting into a pdf, i found that the table cells being continuous overlaps on pages. I now want to trim the table or split the table to convenient size. Any suggestion.

How do I convert a 7 x 3 table into a 4 x 3 and 3x3 table? Reducing font size does not alter the row and cell size. Is there a way to alter the columnwidth and row height in maple?

Thanks for suggestion.

Why does this happen

interface(Typesetting)
                                         

interface(Typesetting=standard)
                                                      

interface(Typesetting)
                                            

a²

I've looked up previous answers to this but __ double underscore only works in math input, and ctrl + shift + ^ or ctrl + shift + _ does not seem to work. I'm using Maple 18, windows computer.

I'm using a maple doc to do a homework assignment that is mostly text with only a few equations and math sections. I need to draw a table of material properties in, and when I create a table all the cells default to math inputs. Because of this if I try to evaluate the entire document I get tons of blue evaluation numbers in the table that I don't want, since all the mateial properties show up as math. I can set each cell to text one by one but there are like 30 cells and it's tedious. How do I set the entire table so that each cell is a text cell?

Hi!

Let F(z) (with z complex) a given function. I want to compute F^n(z0), i.e. the composition of F with itself n-times, where z0 is a given point (complex).

Is correct the following procedure to compute F^k(z0)?

App := proc (k, z0) local z1, z2, j; z1 := z0; z2 := NULL; for j to k do z2 := F(z1); z1 := z2 end do; return z2 end proc

Many thanks in advance for your comments.

Hi

Consider the piecewise function

f:=x->piecewise(x≤0,−3,0<x≤1,x^2,1<x,-x)

can Maple solve the inequation  in R:   f(x)> a

where "a" is a given number in R

Of course the results depend on parameter a

Many thanks for your help

Hello!! Please help me,I need to solve a system of linear algebraic equations by running, and I solved the built-in command solve

restart;
with(plots):
f:=unapply(-x^2+1,x);
mu[1]:=unapply(1/(t^2+1),t);
mu[2]:=unapply(1/(t-5),t); 
g:=unapply(t^3-7*x,[t,x]);
l:=2; T:=3;
n:=10: m:=n: 
h:=evalf(l/n); 
tau:=evalf(T/m);
for k from 0 to n do 
x[k]:=h*k:
end do: 
for j from 0 to m do 
t[j]:=tau*j: 
end do:
ss:=evalf({seq(seq((y[k,j+1]-y[k,j])/tau=(y[k-1,j]-2*y[k,j]+y[k+1,j])/h^2+g(t[j],x[k]),k=1..n-1),j=0..m-1),seq(y[0,j]=mu[1](t[j]),j=1..m),seq(y[k,0]=f(x[k]),k=0..n),seq(y[n,j]=mu[2](t[j]),j=1..m)});
#s:=evalf(solve(ss,{seq(seq(y[k,j],k=0..n),j=0..m)}));

 We know the following facts: 

The SequenceGraph command returns a graph with the specified degree sequence given as input, if such a graph exists. It raises an exception otherwise. 
 But  If I  want to get more graphs  that satisfy this condition of degree sequence ? (If graphs are not many ,I want get all graphs better)
what should I do.?
For example: DrawGraph(SequenceGraph([3, 2, 2, 1, 1, 1]));  It returns the first graph below, but it is obvious that the second graph also fits the condition.

squenceGraph.mw

Download MltxPLOTS.mw

Hello Dear,

I have the following equation

 This equation is satisfied if the coefficients are zero.

So I need an order in Maple to write that

Good evening!!! I have a task to implement the task of Cauchy by the method of Milne, wrote the code, but did not understand it until the end, help to understand? what's wrong?
First calculate four "initial" values by the method of Runge-Kutta methods, then use the method of Milne, the Fact that two times running, perhaps extra?

restart;
with(plots):
a:=0; b:=1; eps:=evalf(10^(-3)):
f:=unapply(2*x*(x^2+y),x,y);
G:=simplify(dsolve({diff(y(x),x)=f(x,y(x)),y(a)=1}));                    
N:=15: h:=(b-a)/N:
for i from 0 to N do 
x[i]:=a+i*h: 
end do:
y[0]:=1;
s[0]:=1;
for i from 0 to 2 do 
t[1]:=evalf(h*f(x[i],y[i])):
t[2]:=evalf(h*f(x[i]+h/2,y[i]+t[1]/2)): 
t[3]:=evalf(h*f(x[i]+h/2,y[i]+t[2]/2)):
t[4]:=evalf(h*f(x[i]+h,y[i]+t[3])):
y[i+1]:=evalf(y[i]+(t[1]+2*t[2]+2*t[3]+t[4])/6):
q[1]:=evalf(h*f(x[i],s[i])):
q[2]:=evalf(h*f(x[i]+h/2,s[i]+q[1]/2)): 
q[3]:=evalf(h*f(x[i]+h/2,s[i]+q[2]/2)):
q[4]:=evalf(h*f(x[i]+h,s[i]+q[3])):
s[i+1]:=evalf(s[i]+(q[1]+2*q[2]+2*q[3]+q[4])/6):
end do;
for i from 3 to N-1 do 
y[i+1]:=evalf(y[i-3]+((4*h)/3)*(2*f(x[i],y[i])-f(x[i-1],y[i-1])+2*f(x[i-2],y[i-2]))):
s[i+1]:=evalf(s[i-1]+(h/3)*(f(x[i+1],y[i+1])+4*f(x[i],s[i])+f(x[i-1],s[i-1]))):
d[i+1]:=abs(y[i+1]-s[i+1])/29:
if abs(d[i+1]) < eps then y[i]:=y[i]:
else y[i]:=s[i];
end if: end do;
s1:=plot(rhs(G),x=a..b,color=yellow):
s2:=pointplot({seq([x[k],y[k]],k=0..N)}): 
display(s1,s2);

So I have this expression

f:=(coth(x)^(1/3)-tanh(x)^(1/3))*(coth(x)^(2/3)+tanh(x)^(2/3)+1)

which Maple can not simplify?

I need to do it like this

`assuming`([expand(simplify(add(`~`[simplify]([op(combine(expand((coth(x)^(1/3)-tanh(x)^(1/3))*(coth(x)^(2/3)+tanh(x)^(2/3)+1))))]))))], [x > 1])

Is this actually true or what is happening here?

Hi

I have a first oder PDE, I use pdsolve I obtained a solution depend on function F

condition_unique_solution.mw

My question: The boundary condition  f(x,y) = 1 is supplied on the line y = k x, where k is a constant. For which k
does there exist a unique solution for f(x, y)?

Many thanks for your help

Hi there

I'm an old user of Maple, but I've never been able to plot functions with unit. You can see my latest attempt down below

b := 120*Unit('mm');
h := 200*Unit('mm');
V := 8*Unit('kN');

I__x := (1/12)*b*h^3

Q(x):=(1/2)*((1/4)*h^2-(100*Unit('mm')-x)^2)*b 
tau(x):=V*Q(x)/(I__x*b)

plot(Q(x(Unit('mm')), units), x = 0*Unit('mm') .. 100*Unit('mm'))

Plot_function_with_units.mw

If anyone is able to help me with this problem, I would greatly appreciate it.