Question: matrix code help

hey friends
how can i have program for following matrix of m x m order in maple 

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a := Matrix(8, 8, {(1, 1) = m[1, 1], (1, 2) = m[1, 2], (1, 3) = m[1, 3], (1, 4) = m[1, 4], (1, 5) = m[1, 5], (1, 6) = m[1, 6], (1, 7) = m[1, 7], (1, 8) = m[1, 8], (2, 1) = m[2, 1], (2, 2) = m[2, 2], (2, 3) = m[2, 3], (2, 4) = m[2, 4], (2, 5) = m[2, 5], (2, 6) = m[2, 6], (2, 7) = m[2, 7], (2, 8) = m[2, 8], (3, 1) = m[3, 1], (3, 2) = m[3, 2], (3, 3) = m[3, 3], (3, 4) = m[3, 4], (3, 5) = m[3, 5], (3, 6) = m[3, 6], (3, 7) = m[3, 7], (3, 8) = m[3, 8], (4, 1) = m[4, 1], (4, 2) = m[4, 2], (4, 3) = m[4, 3], (4, 4) = m[4, 4], (4, 5) = m[4, 5], (4, 6) = m[4, 6], (4, 7) = m[4, 7], (4, 8) = m[4, 8], (5, 1) = m[5, 1], (5, 2) = m[5, 2], (5, 3) = m[5, 3], (5, 4) = m[5, 4], (5, 5) = m[5, 5], (5, 6) = m[5, 6], (5, 7) = m[5, 7], (5, 8) = m[5, 8], (6, 1) = m[6, 1], (6, 2) = m[6, 2], (6, 3) = m[6, 3], (6, 4) = m[6, 4], (6, 5) = m[6, 5], (6, 6) = m[6, 6], (6, 7) = m[6, 7], (6, 8) = m[6, 8], (7, 1) = m[7, 1], (7, 2) = m[7, 2], (7, 3) = m[7, 3], (7, 4) = m[7, 4], (7, 5) = m[7, 5], (7, 6) = m[7, 6], (7, 7) = m[7, 7], (7, 8) = m[7, 8], (8, 1) = m[8, 1], (8, 2) = m[8, 2], (8, 3) = m[8, 3], (8, 4) = m[8, 4], (8, 5) = m[8, 5], (8, 6) = m[8, 6], (8, 7) = m[8, 7], (8, 8) = m[8, 8]})

 



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