Question: Force execution on loop (and seq)

Say for a complicated function f(x), there are 10 solutions. I want to check for any of the solutions, the matrix R is defined or not.


Is there a way to force execution like the following ones?


for i from 0 to 3 do
end do;


I think the problem is that, Maple stops immediately when it's undefined. But the following terms could be defined.

Or is there a way to put this check into "solve"? That's

> solve(f(x),x, "some way of making sure that the solution has to be defined for the matrix R" )



Is there a way to achieve this?


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