Question: Inverse Laplace Transformation

Dear all,

I have a question, why is the output of the inverse Laplace transformation if the signal is multiplied by itself not just convoluted in time domain:

restart:
with(inttrans):
u0(s):=laplace(u0(t),t,s):
ul(s):=laplace(ul(t),t,s):

invlaplace(u0(s)*ul(s),s,t);
invlaplace(u0(s)*u0(s),s,t);

 

Thanks!

 

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