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Question: taylor in function of tanh

Question:taylor in function of tanh

briceM 45
taylor
March 04 2017
0

Ho, I try series taylor of tanh, but I want that result is in function of tanh(sqrt(q)*z/y) and not exponential e.

f1 := taylor(tanh(sqrt(q)*z/y+x*m/y), m, 2)

f1 := ((exp(sqrt(q)*z/y))^2-1)/((exp(sqrt(q)*z/y))^2+1)+4*(exp(sqrt(q)*z/y))^2*x*m/(((exp(sqrt(q)*z/y))^2+1)^2*y)+O(m^2)

 

That is, it should look like:

tanh(sqrt(q)*z/y+.....+tanh^2(tanh(sqrt(q)*z/y)m

Regards.

 
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