Question: Using is command properly

Below I successfully employed the is command to compare Q1 & Q2.  However, attempting to compare T1 & T2 which is essentially Q1 & Q2 but defined as a functions dependent on m does not work so well.  Can I do this comparison?  If so what is the proper syntax to do this?


 

Ck1 := sin(Pi*k)/(Pi*k);

a[0]+Sum(-(-1+cos(Pi*k))*sin(2*Pi*k*t/T)/(Pi*k), k = 1 .. m)

(1)

Q1 := 2*sin(alpha)*(diff(S11, t)); -1; Q2 := sum(2*sin(alpha)*(2*Ck2*Pi*k*cos(2*Pi*k*t/T)/T), k = 1 .. m); -1; is(Q1 = Q2), is(expand(Q1 = Q2)), is(combine(Q1 = Q2)), is(eval(Q1 = Q2)), is(value(Q1 = Q2)), simplify(Q1-Q2)

true, true, true, true, true, 0

(2)

T1 := proc (m) options operator, arrow; Q1 end proc; 1; T2 := proc (m) options operator, arrow; Q2 end proc; 1; is(T1 = T2), is(expand(T1 = T2)), is(combine(T1 = T2)), is(eval(T1 = T2)), is(value(T1 = T2)), simplify(T1-T2)

false, false, false, false, false, T1-T2

(3)

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