Question: How I can plot the answers obtained from solving two differential equations?

How I can plot the answers obtained from solving two differential equations?

Thanks

SAL.mw
 

restart

e := 0.62e-2

0.62e-2

(1)

r := 0.15e-1

0.15e-1

(2)

DDo2 := .17*3600

612.00

(3)

DDco2 := .12*3600

432.00

(4)

NULL

N := 20

20

(5)

P1o2 := 3600*(1000*(27*10^(-13)*24.45)*100)/(10000*0.986923267e-2)

0.2408029155e-3

(6)

P1co2 := 3600*(1000*(99*10^(-13)*24.45)*100)/(10000*0.986923267e-2)

0.8829440235e-3

(7)

P2o2 := Pi*r^2*DDo2*N/(e+r)

408.1106684

(8)

P2co2 := Pi*r^2*DDco2*N/(e+r)

288.0781188

(9)

diff(y[o2](t), t) = ((P1o2+P2o2)*(21-y[o2](t))-100*(167*y[o2](t)/(1.6+y[o2](t))*.25))*(1/1300)

diff(y[o2](t), t) = 6.592560841-.3139314686*y[o2](t)-3.211538462*y[o2](t)/(1.6+y[o2](t))

(10)

diff(y[co2](t), t) = ((P1co2+P2co2)*(0.4e-1-y*y[co2](t))+.25*(.8*(167*y*y[co2](t)/(1.6+y*y[co2](t))))*100)*(1/1300)

diff(y[co2](t), t) = 0.8863969285e-2-.2215992321*y*y[co2](t)+2.569230769*y*y[co2](t)/(1.6+y*y[co2](t))

(11)

                 initial*conditional     @t=0     yO2=21 , yco2=0.04


 

Download SAL.mw

 

Please Wait...