Question: Why does SurfaceInt in spherical coordinates give an unexpected answer?

A person asked me why the following code does not give the integral of (x^2+y^2)*z over the top of the unit sphere.

VectorCalculus:-SurfaceInt((x^2 + y^2)*z, [x, y, z] = Surface(<1, s, t>, s = 0 .. Pi/2, t = 0 .. 2*Pi, coords = spherical))

The correct answer is Pi/2, but Maple gives 2*(-1 + Pi)*Pi^2.

Will someonoe please explain this behavior?

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