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Question: How get piecewise function by substitution?

Question:How get piecewise function by substitution?

salim-barzani 1410 Maple 2024
substitution piecewise limit incomplete-question
April 02 2025
3

In this example by applying the substitution i can get half of paicewise function but how get another  half ? i am looking for B_rs as Piecewise function ?

> 

restart
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eij := ((-3*k[i]*(k[i]-k[j])*l[j]+beta)*l[i]^2-(2*(-3*k[j]*(k[i]-k[j])*l[j]*(1/2)+beta))*l[j]*l[i]+beta*l[j]^2)/((-3*k[i]*(k[i]+k[j])*l[j]+beta)*l[i]^2-(2*(3*k[j]*(k[i]+k[j])*l[j]*(1/2)+beta))*l[j]*l[i]+beta*l[j]^2)

((-3*k[i]*(k[i]-k[j])*l[j]+beta)*l[i]^2-2*(-(3/2)*k[j]*(k[i]-k[j])*l[j]+beta)*l[j]*l[i]+beta*l[j]^2)/((-3*k[i]*(k[i]+k[j])*l[j]+beta)*l[i]^2-2*((3/2)*k[j]*(k[i]+k[j])*l[j]+beta)*l[j]*l[i]+beta*l[j]^2)

 (1)
> 

eval(eij, k[j] = b*k[i]); series(%, k[i], 3); convert(%, polynom); eval(%, b = k[j]/k[i]); Bij := (%-1)/(k[i]*k[j])

((-3*k[i]*(-b*k[i]+k[i])*l[j]+beta)*l[i]^2-2*(-(3/2)*b*k[i]*(-b*k[i]+k[i])*l[j]+beta)*l[j]*l[i]+beta*l[j]^2)/((-3*k[i]*(b*k[i]+k[i])*l[j]+beta)*l[i]^2-2*((3/2)*b*k[i]*(b*k[i]+k[i])*l[j]+beta)*l[j]*l[i]+beta*l[j]^2)

  

series(1+((-3*(-b+1)*l[j]*l[i]^2+3*b*(-b+1)*l[j]^2*l[i]+3*(b+1)*l[j]*l[i]^2+3*b*(b+1)*l[j]^2*l[i])/(beta*l[i]^2-2*beta*l[i]*l[j]+beta*l[j]^2))*k[i]^2+O(k[i]^4),k[i],4)

  

1+(-3*(-b+1)*l[j]*l[i]^2+3*b*(-b+1)*l[j]^2*l[i]+3*(b+1)*l[j]*l[i]^2+3*b*(b+1)*l[j]^2*l[i])*k[i]^2/(beta*l[i]^2-2*beta*l[i]*l[j]+beta*l[j]^2)

  

1+(-3*(-k[j]/k[i]+1)*l[j]*l[i]^2+3*k[j]*(-k[j]/k[i]+1)*l[j]^2*l[i]/k[i]+3*(k[j]/k[i]+1)*l[j]*l[i]^2+3*k[j]*(k[j]/k[i]+1)*l[j]^2*l[i]/k[i])*k[i]^2/(beta*l[i]^2-2*beta*l[i]*l[j]+beta*l[j]^2)

  

(-3*(-k[j]/k[i]+1)*l[j]*l[i]^2+3*k[j]*(-k[j]/k[i]+1)*l[j]^2*l[i]/k[i]+3*(k[j]/k[i]+1)*l[j]*l[i]^2+3*k[j]*(k[j]/k[i]+1)*l[j]^2*l[i]/k[i])*k[i]/((beta*l[i]^2-2*beta*l[i]*l[j]+beta*l[j]^2)*k[j])

 (2)
> 

simplify((-3*(-k[j]/k[i]+1)*l[j]*l[i]^2+3*k[j]*(-k[j]/k[i]+1)*l[j]^2*l[i]/k[i]+3*(k[j]/k[i]+1)*l[j]*l[i]^2+3*k[j]*(k[j]/k[i]+1)*l[j]^2*l[i]/k[i])*k[i]/((beta*l[i]^2-2*beta*l[i]*l[j]+beta*l[j]^2)*k[j]))

6*l[j]*l[i]*(l[i]+l[j])/((l[i]-l[j])^2*beta)

 (3)


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