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Question: Error Propagation question?

Question:Error Propagation question?

Mechoption 24
student
March 26 2010
0

Let y1=exp(a*t), and y2=ln(y1)=a*t The error in y1 and y2 is found from sigma=sqrt(diff(y1,a)^2*siga^2) where siga is the uncertainty in a. Therefore, sigy1 = exp(a*t)*t*siga sigy2 = t*siga Therefore, y1 = y1 +/- y1*t*siga y2 = y2 +/- t*siga What I don't get, is as exp(y2)=y1 , then this gives me: y1 = y1 +/- exp(t*siga) What is the correct errror in y1? y1*t*siga or exp(t*siga) ??
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