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Question: Floating-point evaluation

Question:Floating-point evaluation

fbackelj 271
December 22 2005
0
Hello, I have a question regarding the floating-point evaluation of certain expressions. In the helppage for float we read the following: "The presence of a floating-point number in an expression generally implies that the computation will use floating-point evaluation. The floating-point evaluator, evalf, can be used to force computation to take place in the floating-point domain." So, this explains the following behavior: > 0.1+1/3; 0.4333333333 But what is the difference with the following expression: > 0.1 + Pi; 0.1 + Pi This contradicts what is in the float helppage; both Pi and 1/3 are exact mathematical quantities, yet 0.1 is a float, so one would expect a floating-point behavior to be happening. Maybe this behavior is explained somewhere else? So, why does this behavior appear? Regards, Franky.
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