I'm creating a table of random math problems for my daughter to print out.  How do I get more columns?

a := rand(1 .. 15):
b := ["+", "-", "x", "/"]:

for i to 15 do
  print(cat(a(),b[rand(1..nops(b))()],a(),"_____")):
  print(``):
end do;

                                  13x4_____

I have written a 20-page program created on Maple 14 Classic Worksheet that generates holding patterns in crosswinds.  The program requires about 10 input values.  Can this be migrated to an Ipad or accessed from an Ipad?

Dear All,

How can I define the following commands of MATLAB in MAPLE,

MATLAB:

zimag=j*[0:thetas/N:thetas];

zreal(1:length(zimag))=log(R);

z=zreal+zimag

Also

MATLAB

For i=1:length(z)

Your help will be really appreciated.

Best Regards

A.Q

SOTON

I have two list, x1 and d, I want to make a piecewise function out of them and plot it, but I may have some other stuffs like this so I decided to write this procedure in a proc, the proc makes the input of the piecewise right, but when I want to make a function out of this and pass it to plot this does not works properly, I tried something else; first assigned a seri to a variable and passed it to the piecewise to make a function out of it this does not works either, but when...

I have program in txt,I want to copy it into the command-line maple 15 as belows:

How to do it. Ctrl+V is useless

code:
> MEMBER := proc(x::anything, L::list, p::evaln) local i;
> for i to nops(L) do
> if x=L[i] then
> if nargs>2 then p := i end if;
> RETURN(true)
> end if
> end do;

2.6_map.mw

I try to solve this problem,but there is an error occur.Is there a problem in the equation?

Hello all, I am wondering if anyone knows how to impose a finite value boundary condition to solve an ordinary differential equation? Specifically, suppose that the solution Maple obtains to an ordinary differential equation is y(x)=-2*x^2+C1*ln(x), C1 being a constant. Given that y(x) must be finite when x=0, then C1 has to be zero. Is there a way to implement this condition when setting up to solve the ODE in Maple, i.e. dsolve({ODE, ICs}, y(x), options)? Many thanks for your help!

Hi all,

I am trying to check a conditional statement in maple, I know it is true but my teacher has us do the entire assignment in maple. I am proving the alternating series test of convergence for a series and need to show that the Un's are all positive so

I am trying to check this statement for truth:

5/sqrt(x+4) > 0 for all real values x > 1

Dear All,

Can someone help me,  to write following matlab code in MAPLE  (only two highlighted lines).   I shall be very thankful to you.

w0=[0.01*aCM];                          %initial values

options=optimset('Display','off','TolFun',1e-24,'TolX',1e-18,'LargeScale','on','MaxFunEvals',5000); % Option to display output

	for i=1:length(z) 

Hi
I run Maple 15 on an Acer laptop with Windows 7 and have the following problem:

When my Maple documents become "too" long, some of the vectors I have created seem to become tables instead (without me doing anything) rendering vector multiplications and additions/subtractions impossible (they'll throw an error; something like it not being possible to multiply a vector and a table. As if one of the vectors in my multiplication has become a table). Should it...

Dear Sir/Madam,

I have a list with positive and negative values. Now I want to count the amount of values less than 0. I tried a few things from the ListTools but nothing is working. I hope you can point me in the right direction.

Kind regards,

Nine Klaassen

Master student TU Delft

how can I caculate the Clifford Algebra in using symbolic expression?

Can maple solve this kind of inequality:
piecewise(x > k, x-k, 0) > q * piecewise(x*(1+a) - k > 0, x*(1+a) - k, 0) + p * piecewise(x*(1+b) - k > 0, x*(1+a) - k, 0)
where p, q, a, b, k are parameters?

I'm trying solve-command with allsolutions option but it doesn't work :(

Thanks for answering :)

Hi

How can I use loop-varible in a definition of piecewise function? For example, when I do:

for k to 5 do

f[k] := x -> piecewise(x > 0, k, 0);

end do;

f[3](1);

f[2](1);

I get:

f[3](1) = 6

f[2](1) = 6

Hi all, I found that the expression:

(2x+7)/5+(6x-3)/3

automatically simplifies to

Is there a function that will return

which is one fraction, instead?