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What exactly is Maple 2025 for Screen Readers ...

Asked by: C_R 3437
gui
March 26 2025
2  0

I found this version after Maple 2025 installation in Windows programs menu. It looks like a fully functional Maple version using the old GUI.

Why is it called "for screen readers"? I do not understand the link to persons with disabilites (I assume that the icon stands for it)?
In which respect is the new GUI less suited for visually impaired(?) people? I think the readabilty of the new GUI is at least as good as the old GUI.

In case Maple 2025 for Screen Readers is a fully functional Maple version, I give two thumbs up to Maplesoft. Smart move not to immediately impose a "disruptive" new GUI with allot of potential for new users to everyone.

Using Solve for special variable leeds to missing ...

Asked by: Saalehorizontale 55
solve inequality
March 26 2025
0  2

Hey guys, 

I have a problem with the solve command. And since the websites are down, I cant help myself. I have a function x(y) and an intervall for y. This function or the set of points described by the function should now be transformed to another area of the plane. So now I can get a(x,y)=1/y and b(x,y)=x/(x+y-1) with just plugging in, then everything depeends from the y Invtervall. But I want to get the form b(a) and an intervall for a. So that I can see the function directly. So i thought I just put everything into the solve command and than ask for a solution for {a,b} and expected to get what I want. (Uploading the script here gives an error)
 

restart;
Sol := solve({a = 1/y, b = x/(x + y - 1), x = (y - 1)^2, 1 < y, y < 5/4});
Sol_ab := solve({a = 1/y, b = x/(x + y - 1), x = (y - 1)^2, 1 < y, y < 5/4}, {a, b});

#expected (or wanted) solution
#with y = 1/a and the inequalities we get 4/5 < a and a < 1 with y
#with y = we get x(a)/a and y(a) and reach b = 1/a - 1
#all together: Sol={b=1/a - 1, 4/4<a, a<1};

THe problem is, that I get an empty set which is obviously wrong. So I somehow make an error when making the variables I want concrete with adding {a,b}. What do I do wrong? Or is there a better command for what I want to achieve? In this case I can solve the problem via hand, but I have more complex tranformations and mor ecomplex functions x(y), so thats why I ask for general help with my problem. 

Thank ypu in advance

Felix

Download QUESTI~1.MW

Matlab (R2024b) connection does not work on Maple ...

Asked by: MichalKvasnicka 219
matlab
March 26 2025
2  3

On Ubuntu 24.04 or LinuxMint 22.1 (based on Ubuntu 24.04) I have the problem with(Matlab) funtions functionality

Matlab[openlink]();
Error, (in Matlab:-openlink) There was a problem initializing the Matlab engine. Refer to ?Matlab,setup for help configuring your system to work with the Matlab-link.  The error was: Maple/Matlab Link: Can't start Matlab engine; environment variable $MATLAB_BASEDIR not set

+ other error mesages from CLI:

starting mmatlink
In connectToMatlab
/bin/csh: /opt/MATLAB/R2024b/bin/glnxa64/libbsd.so.0: version `LIBBSD_0.7' not found (required by /bin/csh)

MATLAB R2024b using obsolete libbsd ver. 0.4.2 !!! So this is probably the problem...

$MATLAB_BASEDIR is properly defined at maple script:

# In order to link to MATLAB from within Maple, correct the following path
# and uncomment the next four lines, or define the environment variable,
# $MATLAB_BASEDIR outside this script.
if [ -z "$MATLAB_BASEDIR" ] ; then
MATLAB_BASEDIR=/opt/MATLAB/R2024b
export MATLAB_BASEDIR
fi

# C-shell is required for link to MATLAB (sudo apt install csh)

Any help???

What is wrong that the command solve does not disp...

Asked by: abdulganiy 145
solve
March 26 2025
0  5

Good day, all.

Please, I am working on the following code but found out that the command solve is not displaying any result. Your assistance and suggestions would be appreciated. Thank you, and best regards.

 

restart;
NULL;
t := sum(a[j]*q^j, j = 0 .. 9);
H := diff(t, q);
F := diff(t, q $ 2);
p1 := simplify(eval(t, q = x)) = y[n];
p2 := simplify(eval(F, q = x)) = f[n];
p3 := simplify(eval(F, q = x + h/4)) = f[n + 1/4];
p4 := simplify(eval(F, q = x + h/2)) = f[n + 1/2];
p5 := simplify(eval(F, q = x + (3*h)/4)) = f[n + 3/4];
p6 := simplify(eval(F, q = x + h)) = f[n + 1];
p7 := simplify(eval(F, q = x + (5*h)/4)) = f[n + 5/4];
p8 := simplify(eval(F, q = x + (3*h)/2)) = f[n + 3/2];
p9 := simplify(eval(F, q = x + (7*h)/4)) = f[n + 7/4];
p10 := simplify(eval(F, q = x + 2*h)) = f[n + 2];
r := seq(a[i], i = 0 .. 9);
s := p || (1 .. 10);

solve({s}, {r});

How find Auxiliary solution function by using seri...

Asked by: salim-barzani 1575
substitution pde series
March 26 2025
4  0

in a lot of paper i see that they just use the Auxiliary function without mention any detail but now i have to find out how i can reach this function, always i used u=Rdiff(ln(f),x#1,2) or u=Rdiff(ln(f),y,x)  (eq17) in mw. and it is answer for me untill now without knowing finding, but i have to figure out how they reach this in more than 1000 paper i didn't see any explanation about that they just used just in one of the paper mentioned something  like a series which i think they used this series but again is so complicated for undrestanding , i will put some problem picture and now i want to know how find them  eq17 for any equation based on the series in last picture mentioned

 

second example

third example which is so  different from other and i don't know how author reach this point 

i have to find this auxiliary function by using something like series  as mentioned in other question? how i can use this series for finding my auxiliary function u= u_0+R*diff(ln(f),x)  


 

#picture one

NULL

> 

restart
> 

with(PDEtools)
> 

with(LinearAlgebra)
> 

NULL
> 

with(SolveTools)
> 

_local(gamma)

Warning, A new binding for the name `gamma` has been created. The global instance of this name is still accessible using the :- prefix, :-`gamma`.  See ?protect for details.

  
> 

undeclare(prime)

`There is no more prime differentiation variable; all derivatives will be displayed as indexed functions`

 (1)
> 

declare(u(x, y, z, t))

u(x, y, z, t)*`will now be displayed as`*u

 (2)
> 

declare(f(x, y, z, t))

f(x, y, z, t)*`will now be displayed as`*f

 (3)
> 

pde := diff(diff(u(x, y, z, t), t)+6*u(x, y, z, t)*(diff(u(x, y, z, t), x))+diff(u(x, y, z, t), `$`(x, 3)), x)+diff(alpha*(diff(u(x, y, z, t), x))+beta*(diff(u(x, y, z, t), y))+delta*(diff(u(x, y, z, t), z)), x)+mu*(diff(u(x, y, z, t), `$`(t, 2)))

diff(diff(u(x, y, z, t), t), x)+6*(diff(u(x, y, z, t), x))^2+6*u(x, y, z, t)*(diff(diff(u(x, y, z, t), x), x))+diff(diff(diff(diff(u(x, y, z, t), x), x), x), x)+alpha*(diff(diff(u(x, y, z, t), x), x))+beta*(diff(diff(u(x, y, z, t), x), y))+delta*(diff(diff(u(x, y, z, t), x), z))+mu*(diff(diff(u(x, y, z, t), t), t))

 (4)
> 

pde_linear, pde_nonlinear := selectremove(proc (term) options operator, arrow; not has((eval(term, u(x, y, z, t) = a*u(x, y, z, t)))/a, a) end proc, expand(pde))

diff(diff(u(x, y, z, t), t), x)+diff(diff(diff(diff(u(x, y, z, t), x), x), x), x)+alpha*(diff(diff(u(x, y, z, t), x), x))+beta*(diff(diff(u(x, y, z, t), x), y))+delta*(diff(diff(u(x, y, z, t), x), z))+mu*(diff(diff(u(x, y, z, t), t), t)), 6*(diff(u(x, y, z, t), x))^2+6*u(x, y, z, t)*(diff(diff(u(x, y, z, t), x), x))

 (5)
> 

thetai := k[i]*(t*w[i]+y*l[i]+z*r[i]+x)+eta[i]; eval(pde_linear, u(x, y, z, t) = exp(thetai)); eq15 := isolate(%, w[i])

k[i]*(t*w[i]+y*l[i]+z*r[i]+x)+eta[i]

  

k[i]^2*w[i]*exp(k[i]*(t*w[i]+y*l[i]+z*r[i]+x)+eta[i])+k[i]^4*exp(k[i]*(t*w[i]+y*l[i]+z*r[i]+x)+eta[i])+alpha*k[i]^2*exp(k[i]*(t*w[i]+y*l[i]+z*r[i]+x)+eta[i])+beta*k[i]^2*l[i]*exp(k[i]*(t*w[i]+y*l[i]+z*r[i]+x)+eta[i])+delta*k[i]^2*r[i]*exp(k[i]*(t*w[i]+y*l[i]+z*r[i]+x)+eta[i])+mu*k[i]^2*w[i]^2*exp(k[i]*(t*w[i]+y*l[i]+z*r[i]+x)+eta[i])

  

w[i] = (1/2)*(-1+(-4*beta*mu*l[i]-4*delta*mu*r[i]-4*mu*k[i]^2-4*alpha*mu+1)^(1/2))/mu

 (6)
> 

eqf := f(x, y, z, t) = 1+eval(exp(thetai), eq15)

f(x, y, z, t) = 1+exp(k[i]*((1/2)*t*(-1+(-4*beta*mu*l[i]-4*delta*mu*r[i]-4*mu*k[i]^2-4*alpha*mu+1)^(1/2))/mu+y*l[i]+z*r[i]+x)+eta[i])

 (7)
> 

eq17 := u(x, y, z, t) = R*(diff(ln(f(x, y, z, t)), `$`(x, 2)))

u(x, y, z, t) = R*((diff(diff(f(x, y, z, t), x), x))/f(x, y, z, t)-(diff(f(x, y, z, t), x))^2/f(x, y, z, t)^2)

 (8)
> 

eval(eq17, eqf); simplify(eval(pde, %)); sort([solve(%, R)]); eq17 := eval(eq17, R = simplify(%[2]))

u(x, y, z, t) = R*(k[i]^2*exp(k[i]*((1/2)*t*(-1+(-4*beta*mu*l[i]-4*delta*mu*r[i]-4*mu*k[i]^2-4*alpha*mu+1)^(1/2))/mu+y*l[i]+z*r[i]+x)+eta[i])/(1+exp(k[i]*((1/2)*t*(-1+(-4*beta*mu*l[i]-4*delta*mu*r[i]-4*mu*k[i]^2-4*alpha*mu+1)^(1/2))/mu+y*l[i]+z*r[i]+x)+eta[i]))-k[i]^2*(exp(k[i]*((1/2)*t*(-1+(-4*beta*mu*l[i]-4*delta*mu*r[i]-4*mu*k[i]^2-4*alpha*mu+1)^(1/2))/mu+y*l[i]+z*r[i]+x)+eta[i]))^2/(1+exp(k[i]*((1/2)*t*(-1+(-4*beta*mu*l[i]-4*delta*mu*r[i]-4*mu*k[i]^2-4*alpha*mu+1)^(1/2))/mu+y*l[i]+z*r[i]+x)+eta[i]))^2)

  

12*R*k[i]^6*exp(((1+(-4*beta*l[i]-4*delta*r[i]-4*k[i]^2-4*alpha)*mu)^(1/2)*t*k[i]+((2*y*l[i]+2*z*r[i]+2*x)*mu-t)*k[i]+2*eta[i]*mu)/mu)*(exp(((1+(-4*beta*l[i]-4*delta*r[i]-4*k[i]^2-4*alpha)*mu)^(1/2)*t*k[i]+((2*y*l[i]+2*z*r[i]+2*x)*mu-t)*k[i]+2*eta[i]*mu)/mu)-3*exp((1/2)*((1+(-4*beta*l[i]-4*delta*r[i]-4*k[i]^2-4*alpha)*mu)^(1/2)*t*k[i]+((2*y*l[i]+2*z*r[i]+2*x)*mu-t)*k[i]+2*eta[i]*mu)/mu)+1)*(R-2)/(1+exp((1/2)*((1+(-4*beta*l[i]-4*delta*r[i]-4*k[i]^2-4*alpha)*mu)^(1/2)*t*k[i]+((2*y*l[i]+2*z*r[i]+2*x)*mu-t)*k[i]+2*eta[i]*mu)/mu))^6

  

[0, 2]

  

u(x, y, z, t) = 2*(diff(diff(f(x, y, z, t), x), x))/f(x, y, z, t)-2*(diff(f(x, y, z, t), x))^2/f(x, y, z, t)^2

 (9)
> 

eq19 := eval(eq17, eqf)

u(x, y, z, t) = 2*k[i]^2*exp(k[i]*((1/2)*t*(-1+(-4*beta*mu*l[i]-4*delta*mu*r[i]-4*mu*k[i]^2-4*alpha*mu+1)^(1/2))/mu+y*l[i]+z*r[i]+x)+eta[i])/(1+exp(k[i]*((1/2)*t*(-1+(-4*beta*mu*l[i]-4*delta*mu*r[i]-4*mu*k[i]^2-4*alpha*mu+1)^(1/2))/mu+y*l[i]+z*r[i]+x)+eta[i]))-2*k[i]^2*(exp(k[i]*((1/2)*t*(-1+(-4*beta*mu*l[i]-4*delta*mu*r[i]-4*mu*k[i]^2-4*alpha*mu+1)^(1/2))/mu+y*l[i]+z*r[i]+x)+eta[i]))^2/(1+exp(k[i]*((1/2)*t*(-1+(-4*beta*mu*l[i]-4*delta*mu*r[i]-4*mu*k[i]^2-4*alpha*mu+1)^(1/2))/mu+y*l[i]+z*r[i]+x)+eta[i]))^2

 (10)
> 

simplify(eq19)

u(x, y, z, t) = 2*k[i]^2*exp((1/2)*((1+(-4*beta*l[i]-4*delta*r[i]-4*k[i]^2-4*alpha)*mu)^(1/2)*t*k[i]+((2*y*l[i]+2*z*r[i]+2*x)*mu-t)*k[i]+2*eta[i]*mu)/mu)/(1+exp((1/2)*((1+(-4*beta*l[i]-4*delta*r[i]-4*k[i]^2-4*alpha)*mu)^(1/2)*t*k[i]+((2*y*l[i]+2*z*r[i]+2*x)*mu-t)*k[i]+2*eta[i]*mu)/mu))^2

 (11)
> 

pdetest(eq19, pde)

0

 (12)
> 

#second example
> 

NULL
> 

restart
> 

with(PDEtools)
> 

with(LinearAlgebra)
> 

NULL
> 

with(SolveTools)
> 

_local(gamma)
> 

``

`There is no more prime differentiation variable; all derivatives will be displayed as indexed functions`

 (13)
> 

declare(u(x, y, t))

u(x, y, t)*`will now be displayed as`*u

 (14)
> 

declare(f(x, y, t))

f(x, y, t)*`will now be displayed as`*f

 (15)
> 

pde := diff(u(x, y, t), x, t)+alpha*(diff(u(x, y, t), `$`(x, 4))+6*(diff(u(x, y, t), x))*(diff(u(x, y, t), `$`(x, 2))))+beta*(diff(u(x, y, t), `$`(y, 2)))+a*(diff(u(x, y, t), `$`(x, 2)))+b*(diff(u(x, y, t), x, y))

diff(diff(u(x, y, t), t), x)+alpha*(diff(diff(diff(diff(u(x, y, t), x), x), x), x)+6*(diff(u(x, y, t), x))*(diff(diff(u(x, y, t), x), x)))+beta*(diff(diff(u(x, y, t), y), y))+a*(diff(diff(u(x, y, t), x), x))+b*(diff(diff(u(x, y, t), x), y))

 (16)
> 

oppde := [op(expand(pde))]; u_occurrences := map(proc (i) options operator, arrow; numelems(select(has, [op([op(i)])], u)) end proc, oppde); linear_op_indices := ListTools:-SearchAll(1, u_occurrences); pde_linear := add(oppde[[linear_op_indices]]); pde_nonlinear := expand(simplify(expand(pde)-pde_linear))

diff(diff(u(x, y, t), t), x)+alpha*(diff(diff(diff(diff(u(x, y, t), x), x), x), x))+beta*(diff(diff(u(x, y, t), y), y))+a*(diff(diff(u(x, y, t), x), x))+b*(diff(diff(u(x, y, t), x), y))

  

6*alpha*(diff(u(x, y, t), x))*(diff(diff(u(x, y, t), x), x))

 (17)
> 

thetai := k[i]*(t*w[i]+y*l[i]+x)+eta[i]; eval(pde_linear, u(x, y, t) = 1+exp(thetai)); eq15 := isolate(%, w[i])

k[i]*(t*w[i]+y*l[i]+x)+eta[i]

  

k[i]^2*w[i]*exp(k[i]*(t*w[i]+y*l[i]+x)+eta[i])+alpha*k[i]^4*exp(k[i]*(t*w[i]+y*l[i]+x)+eta[i])+beta*k[i]^2*l[i]^2*exp(k[i]*(t*w[i]+y*l[i]+x)+eta[i])+a*k[i]^2*exp(k[i]*(t*w[i]+y*l[i]+x)+eta[i])+b*k[i]^2*l[i]*exp(k[i]*(t*w[i]+y*l[i]+x)+eta[i])

  

w[i] = -alpha*k[i]^2-beta*l[i]^2-b*l[i]-a

 (18)
> 

eqf := f(x, y, t) = 1+eval(exp(thetai), eq15)

f(x, y, t) = 1+exp(k[i]*((-alpha*k[i]^2-beta*l[i]^2-b*l[i]-a)*t+l[i]*y+x)+eta[i])

 (19)
> 

eq17 := u(x, y, t) = R*(diff(ln(f(x, y, t)), x))

u(x, y, t) = R*(diff(f(x, y, t), x))/f(x, y, t)

 (20)
> 

eval(eq17, eqf); simplify(eval(pde, %)); sort([solve(%, R)]); eq17 := eval(eq17, R = simplify(%[2]))

[0, 2]

  

u(x, y, t) = 2*(diff(f(x, y, t), x))/f(x, y, t)

 (21)
> 

eq19 := eval(eq17, eqf)

u(x, y, t) = 2*k[i]*exp(k[i]*((-alpha*k[i]^2-beta*l[i]^2-b*l[i]-a)*t+l[i]*y+x)+eta[i])/(1+exp(k[i]*((-alpha*k[i]^2-beta*l[i]^2-b*l[i]-a)*t+l[i]*y+x)+eta[i]))

 (22)
> 

M := eval(rhs(eq19), i = 1)

2*k[1]*exp(k[1]*(t*(-alpha*k[1]^2-beta*l[1]^2-b*l[1]-a)+y*l[1]+x)+eta[1])/(1+exp(k[1]*(t*(-alpha*k[1]^2-beta*l[1]^2-b*l[1]-a)+y*l[1]+x)+eta[1]))

 (23)
> 

simplify(eq19)

u(x, y, t) = 2*k[i]*exp(-alpha*t*k[i]^3+((-beta*l[i]^2-b*l[i]-a)*t+y*l[i]+x)*k[i]+eta[i])/(1+exp(-alpha*t*k[i]^3+((-beta*l[i]^2-b*l[i]-a)*t+y*l[i]+x)*k[i]+eta[i]))

 (24)
> 

pdetest(eq19, pde)

0

 (25)
> 

#third example which is so different and really i don't know how the author reach this point? which is diff(arctan(f),x)?
> 

NULL
> 

restart
> 

with(PDEtools)
> 

with(LinearAlgebra)
> 

NULL
> 

with(SolveTools)
> 

_local(gamma)
> 

undeclare(prime)

`There is no more prime differentiation variable; all derivatives will be displayed as indexed functions`

 (26)
> 

declare(u(x, y, z, t))

u(x, y, z, t)*`will now be displayed as`*u

 (27)
> 

declare(f(x, y, z, t))

f(x, y, z, t)*`will now be displayed as`*f

 (28)
> 

pde := diff(u(x, y, z, t), t)+6*u(x, y, z, t)^2*(diff(u(x, y, z, t), x))+diff(u(x, y, z, t), `$`(x, 3))+alpha*(diff(u(x, y, z, t), x))+beta*(diff(u(x, y, z, t), y))+delta*(diff(u(x, y, z, t), z))+lambda*(diff(u(x, y, z, t), x, t))+mu*(diff(u(x, y, z, t), `$`(t, 2)))

diff(u(x, y, z, t), t)+6*u(x, y, z, t)^2*(diff(u(x, y, z, t), x))+diff(diff(diff(u(x, y, z, t), x), x), x)+alpha*(diff(u(x, y, z, t), x))+beta*(diff(u(x, y, z, t), y))+delta*(diff(u(x, y, z, t), z))+lambda*(diff(diff(u(x, y, z, t), t), x))+mu*(diff(diff(u(x, y, z, t), t), t))

 (29)
> 

pde_linear, pde_nonlinear := selectremove(proc (term) options operator, arrow; not has((eval(term, u(x, y, z, t) = a*u(x, y, z, t)))/a, a) end proc, expand(pde))

diff(u(x, y, z, t), t)+diff(diff(diff(u(x, y, z, t), x), x), x)+alpha*(diff(u(x, y, z, t), x))+beta*(diff(u(x, y, z, t), y))+delta*(diff(u(x, y, z, t), z))+lambda*(diff(diff(u(x, y, z, t), t), x))+mu*(diff(diff(u(x, y, z, t), t), t)), 6*u(x, y, z, t)^2*(diff(u(x, y, z, t), x))

 (30)
> 

thetai := k[i]*(t*w[i]+y*l[i]+z*r[i]+x)+eta[i]; eval(pde_linear, u(x, y, z, t) = exp(thetai)); eq15 := isolate(%, w[i])

k[i]*(t*w[i]+y*l[i]+z*r[i]+x)+eta[i]

  

k[i]*w[i]*exp(k[i]*(t*w[i]+y*l[i]+z*r[i]+x)+eta[i])+k[i]^3*exp(k[i]*(t*w[i]+y*l[i]+z*r[i]+x)+eta[i])+alpha*k[i]*exp(k[i]*(t*w[i]+y*l[i]+z*r[i]+x)+eta[i])+beta*k[i]*l[i]*exp(k[i]*(t*w[i]+y*l[i]+z*r[i]+x)+eta[i])+delta*k[i]*r[i]*exp(k[i]*(t*w[i]+y*l[i]+z*r[i]+x)+eta[i])+lambda*k[i]^2*w[i]*exp(k[i]*(t*w[i]+y*l[i]+z*r[i]+x)+eta[i])+mu*k[i]^2*w[i]^2*exp(k[i]*(t*w[i]+y*l[i]+z*r[i]+x)+eta[i])

  

w[i] = (1/2)*(-lambda*k[i]-1+(-4*beta*mu*k[i]*l[i]-4*delta*mu*k[i]*r[i]+lambda^2*k[i]^2-4*mu*k[i]^3-4*alpha*mu*k[i]+2*lambda*k[i]+1)^(1/2))/(mu*k[i])

 (31)
> 

eqf := f(x, y, z, t) = 1+eval(exp(thetai), eq15)

f(x, y, z, t) = 1+exp(k[i]*((1/2)*(-lambda*k[i]-1+(-4*beta*mu*k[i]*l[i]-4*delta*mu*k[i]*r[i]+lambda^2*k[i]^2-4*mu*k[i]^3-4*alpha*mu*k[i]+2*lambda*k[i]+1)^(1/2))*t/(mu*k[i])+l[i]*y+r[i]*z+x)+eta[i])

 (32)
> 

eq17 := u(x, y, z, t) = R*(diff(ln(f(x, y, z, t)), x))

u(x, y, z, t) = R*((diff(diff(f(x, y, z, t), y), y))/f(x, y, z, t)-(diff(f(x, y, z, t), y))^2/f(x, y, z, t)^2)

 (33)
> 

eval(eq17, eqf); simplify(eval(pde, %)); sort([solve(%, R)]); eq17 := eval(eq17, R = simplify(%[2]))


 

Download F-series.mw

Thanks for any help!

remove the rank column from my DataFrame?...

Asked by: jalal 435
dataframe tabulate
March 26 2025
1  2

Hi,

Ideas to remove the rank column (i.e., the first column displaying indices 1, 2, 3, ...) from my DataFrame?

Thanks

Q_DataFrame.mw

Failure/stress analysis...

Asked by: Christopher2222 6030
differential-equations stress
March 26 2025
0  5

I'm no mechanical engineer, but are there any good failure analysis for stresses on different shapes of material in either maple or maplesim?  

I recall something, maybe, in maplesim or maple, possibly an application where I think I saw a graph with force increasing and then levelling off indicating the material broke?  I'm not exactly sure.  Maybe there are some posts somewhere but can't seem to find any. 

Maple Online Help...

Asked by: Henning Broge 10
documentation online
March 26 2025
2  0

Hi

does anyone know when Maple Online Help will be up again?

Regards

Henning

Does Maple 2025 have a dark theme yet?...

Asked by: nmacsai 260
interface color duplicate-question
March 25 2025
2  4

Does Maple 2025 have a dark theme or GUI color customization?

bug report (Maple 2024). Adding Physics:-Setup(ass...

Asked by: nm 11363
assuming odetest physics
March 25 2025
0  5

Does this happen in Maple 2025?

Why when adding Physics:-Setup(assumingusesAssume = true): now Maple gives internal exception which can not even be cought?

> 

interface(version);

`Standard Worksheet Interface, Maple 2024.2, Windows 10, October 29 2024 Build ID 1872373`

> 

Physics:-Version();

`The "Physics Updates" version in the MapleCloud is 1849 and is the same as the version installed in this computer, created 2025, March 12, 12:37 hours Pacific Time.`

> 

restart;
> 

ode:=diff(y(x),x) = (ln(y(x))^2+2*_C1)^(1/2)*y(x);
sol:=y(x) = exp((-2*_C1)^(1/2))

diff(y(x), x) = (ln(y(x))^2+2*_C1)^(1/2)*y(x)

y(x) = exp((-2*_C1)^(1/2))

> 

odetest(sol,ode) assuming positive;

-(ln(exp(I*2^(1/2)*_C1^(1/2)))^2+2*_C1)^(1/2)*exp(I*2^(1/2)*_C1^(1/2))

> 

restart;
> 

ode:=diff(y(x),x) = (ln(y(x))^2+2*_C1)^(1/2)*y(x);
sol:=y(x) = exp((-2*_C1)^(1/2)) ;

diff(y(x), x) = (ln(y(x))^2+2*_C1)^(1/2)*y(x)

y(x) = exp((-2*_C1)^(1/2))

> 

Physics:-Setup(assumingusesAssume = true):
> 

odetest(sol,ode) assuming positive;

Error, (in type/evalc/cx) too many levels of recursion

> 

restart;
> 

ode:=diff(y(x),x) = (ln(y(x))^2+2*_C1)^(1/2)*y(x);
sol:=y(x) = exp((-2*_C1)^(1/2)) ;

diff(y(x), x) = (ln(y(x))^2+2*_C1)^(1/2)*y(x)

y(x) = exp((-2*_C1)^(1/2))

> 

Physics:-Setup(assumingusesAssume = false):
> 

odetest(sol,ode) assuming positive;

-(ln(exp(I*2^(1/2)*_C1^(1/2)))^2+2*_C1)^(1/2)*exp(I*2^(1/2)*_C1^(1/2))

 

 

Download ode_test_with_physics_march_25_2025.mw

My interactive Planck Curve works in Maple 2023, b...

Asked by: erik10 786
March 25 2025
1  7

Dear Maple users

I have an Interactive Planck Curve working great in Maple 2023, but not in Maple 2024 and 2025. Can you explain why? When I drag in the Temperature slider it fails with the window: (in plottools:-getdata) range out of bounds. 

Is it a bug or has some command changed?

File attached.

Kind regards,

Erik

Planck_Curve.mw

How to resize Maple 2025 to half of the screen...

Asked by: C_R 3437
March 25 2025
2  8

Neither dragging the Maple Window to the screen edge nor Windows key & Arrow keys works on my
Windows 10 machine.

Is this only my installation?

Anything I can do get normal Windows windows behaviour back?

Maple 2025 - TextArea component ignores zoom facto...

Asked by: Anthrazit 885
embedded-components textarea
March 25 2025
1  1

I've posted this issue in the beta forum for Maple previously, but apparently this issue was never addressed, so I am going to repost it here.

Contrary to Maple 2024, components like TextArea now ignore the general view zoom factor in Maple 2025.

I'll submit it as a software change request once Maple 2025 is on the list.

Pattern Matching with Indices...

Asked by: ptjb 10
patmatch
March 25 2025
2  3

Hi all, I have recently started playing around with Maple after using Mathematica for years. I am trying to understand how to do pattern matching in Maple, and am being frustrated by the following example using indices:

patmatch(S[a],S[b::symbol])

I would expect this to evaluate to true when none of the symbols have been given other meanings, but this isn't the case. For the life of my I can't work out what I'm doing wrong, and have been unable to find an example of pattern matching with indices online. What am I missing here?

The equivalent statement using functions:

patmatch(S(a),S(b::symbol))

returns true as expected.

Many thanks in advance!

Converting math to text but still executing...

Asked by: PerKirkegaard64 20
March 25 2025
0  2

I have a student who has a problem when closing and opening a Maple file.

It seems as if Maple turns math fields into text, but still execute when using ! or !!!

The dark red part is written in a text field, but Maple still executes

If I try to write in a math field and executes, closes Maple and opens again, this does not happen, so it is not the file that is the problem.  The student is running 2024.2 version.

Can anyone explain the problem and how to solve it.

 

I am unable to add a comment or the file. I have tried several times, without any luck

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