MaplePrimes Questions

Dear all,

I want to use the Maple Compiler to improve the performance of some of my codes. To get used to it, I tried doing the examples from the ?Compiler help-page, but everytime I run the compiler, I get the error message:

"Error, (in Compiler:-Compile) compiler exited with nonzero status 1: 

Do some of you know a possible reason for this?

Thank you all.

Download test.mw

I am not aware if is a problem with me or else.

Have some questions about the select command and (possible) big tensorial expressions. I think it would be a simple question to manage, but I still have problems.

TensorEnergiaMomento.mw

Thanks a lot

Is it possible to let maple, given a certain equation of the form f(x,y,z)=0, find a parametric form of the surface/volume enclosed by that function?

When solving a nonlinear differential equation on some variable x, but using some other parameter w, I am finding on Maple some complicated solution, which I would like to simplify by making evident what is the x dependence, and where I can compact complicated functions of the parameter w alone into new constants. How can I do that automatically?

 

For example, to have

 

(sinh(w) + ln(w))*x 

 

to be automatically called

 

c*x

 

Thank you in advance.


Hi
Please give me the matlab coding for plot together of attach figure by matlab.fig
thanks...!

Hello.

given this expression

T:=unapply((1/6930)*exp(-(1/7938)*(X[4]-933)^2)*exp(-(1/6050)*(X[2]-805)^2)/((1+exp((1/50)*X[4]-(1/50)*X[2]))*Pi),X[2]);

U := unapply(sum(T(X[2]), X[4] = 0 .. 3600), X[2]):

I want to display U, but not all 3600 terms. is there anyway to simplify/reduce this sum?

kind of like geo series a+ar+ar^2+ar^3+...+ar^(n-1)=sum(ar^k,k=0..n-1) can be reduced to a*(1-r^n)/(1-r)

 

Hello. Earlier, I asked about it, (see http://www.mapleprimes.com/questions/203573-How-To-Do-Simple-Operations-On-Tensors). However, not all I was able to understand. Below I will give a try, and maybe you'll show me where I'm wrong.

Also, I'm interested in how you can determine the components of the tensor in a different coordinate system connected with the original in any conversion. Thank for your help.

restart; with(Physics); with(DifferentialGeometry)

ds := Physics:-`^`(dx__1, 2)+Physics:-`^`(dx__2, 2)+Physics:-`^`(dx__3, 2)

dx__1^2+dx__2^2+dx__3^2

(1)

Physics:-Setup(coordinates = (X = [x__1, x__2, x__3]), dimension = 3, metric = ds, quiet)

[coordinatesystems = {X}, dimension = 3, metric = {(1, 1) = 1, (2, 2) = 1, (3, 3) = 1}]

(2)

g_[]

g_[mu, nu] = (Matrix(3, 3, {(1, 1) = 1, (1, 2) = 0, (1, 3) = 0, (2, 2) = 1, (2, 3) = 0, (3, 3) = 1}, storage = triangular[upper], shape = [symmetric]))

(3)

``

u__1 := Physics:-`*`(Physics:-`*`(P, Physics:-`^`(Physics:-`*`(Physics:-`*`(4, Pi), G), -1)), Physics:-`*`(x__3, Physics:-`*`(x__1, Physics:-`^`(Physics:-`^`(r, 3), -1)))-Physics:-`*`(Physics:-`*`(1-Physics:-`*`(2, nu), x__1), Physics:-`^`(Physics:-`*`(r, r+x__3), -1))):u__2 := Physics:-`*`(Physics:-`*`(P, Physics:-`^`(Physics:-`*`(Physics:-`*`(4, Pi), G), -1)), Physics:-`*`(x__2, Physics:-`*`(x__3, Physics:-`^`(Physics:-`^`(r, 3), -1)))-Physics:-`*`(Physics:-`*`(1-Physics:-`*`(2, nu), x__2), Physics:-`^`(Physics:-`*`(r, r+x__3), -1))):u__3 := Physics:-`*`(Physics:-`*`(P, Physics:-`^`(Physics:-`*`(Physics:-`*`(4, Pi), G), -1)), Physics:-`*`(Physics:-`*`(2, 1-nu), Physics:-`^`(r, -1))+Physics:-`*`(Physics:-`^`(x__3, 2), Physics:-`^`(Physics:-`^`(r, 3), -1))):

`e__1,1` := diff(u__1, x__1):`e__2,2` := diff(u__2, x__2):`e__3,3` := diff(u__3, x__3):

`e__1,2` := Physics:-`*`(Physics:-`^`(2, -1), diff(u__1, x__2)+diff(u__2, x__1)):`e__1,3` := Physics:-`*`(Physics:-`^`(2, -1), diff(u__1, x__3)+diff(u__3, x__1)):`e__2,3` := Physics:-`*`(Physics:-`^`(2, -1), diff(u__2, x__3)+diff(u__3, x__2)):

`e__2,1` := `e__1,2`:

`e__3,1` := `e__1,3`:

`e__3,2` := `e__2,3`:

  E := matrix(3, 3, proc (i, j) options operator, arrow; e[i, j] end proc)

Matrix(3, 3, {(1, 1) = e[1, 1], (1, 2) = e[1, 2], (1, 3) = e[1, 3], (2, 1) = e[2, 1], (2, 2) = e[2, 2], (2, 3) = e[2, 3], (3, 1) = e[3, 1], (3, 2) = e[3, 2], (3, 3) = e[3, 3]})

(4)

Physics:-Define(E[i, j])

{gamma[mu], E[i, j], sigma[mu], Physics:-d_[mu], Physics:-g_[mu, nu], delta[mu, nu], epsilon[alpha, mu, nu], Physics:-SpaceTimeVector[mu](X)}

(5)

Physics:-TensorArray(%)

{E[i, j], Array(1..3, 1..3, 1..3, {(1, 1, 1) = 0, (1, 1, 2) = 0, (1, 1, 3) = 0, (1, 2, 1) = 0, (1, 2, 2) = 0, (1, 2, 3) = 0, (1, 3, 1) = 0, (1, 3, 2) = 0, (1, 3, 3) = 0, (2, 1, 1) = 0, (2, 1, 2) = 0, (2, 1, 3) = 0, (2, 2, 1) = 0, (2, 2, 2) = 0, (2, 2, 3) = 0, (2, 3, 1) = 1, (2, 3, 2) = 1, (2, 3, 3) = 1, (3, 1, 1) = 0, (3, 1, 2) = 0, (3, 1, 3) = 0, (3, 2, 1) = -1, (3, 2, 2) = -1, (3, 2, 3) = -1, (3, 3, 1) = 0, (3, 3, 2) = 0, (3, 3, 3) = 0}), Array(1..3, {(1) = x__1, (2) = x__2, (3) = x__3}), Array(1..3, {(1) = Physics:-Psigma[1], (2) = Physics:-Psigma[2], (3) = Physics:-Psigma[3]}), Array(1..3, {(1) = Physics:-d_[1], (2) = Physics:-d_[2], (3) = Physics:-d_[3]}), Array(1..3, {(1) = Physics:-Dgamma[1], (2) = Physics:-Dgamma[2], (3) = Physics:-Dgamma[3]}), Matrix(3, 3, {(1, 1) = 1, (1, 2) = 0, (1, 3) = 0, (2, 1) = 0, (2, 2) = 1, (2, 3) = 0, (3, 1) = 0, (3, 2) = 0, (3, 3) = 1}), Matrix(3, 3, {(1, 1) = 1, (1, 2) = 0, (1, 3) = 0, (2, 1) = 0, (2, 2) = 1, (2, 3) = 0, (3, 1) = 0, (3, 2) = 0, (3, 3) = 1})}

(6)

``

Physics:-Setup(dimension)

[dimension = 3]

(7)

NULL

Physics:-Define(E[i, j], query)

[E, [0, 0, 0], 0]

(8)

DifferentialGeometry:-DGsetup([y__1, y__2, y__3], M):

Phi1 := DifferentialGeometry:-Transformation(N, M, [y__1 = Physics:-`*`(Physics:-`^`(sqrt(6), -1), x__1)+Physics:-`*`(Physics:-`*`(2, Physics:-`^`(sqrt(6), -1)), x__2)+Physics:-`*`(Physics:-`^`(sqrt(6), -1), x__3), y__2 = Physics:-`*`(Physics:-`^`(sqrt(2), -1), x__1)-Physics:-`*`(Physics:-`^`(sqrt(3), -1), x__2)+Physics:-`*`(Physics:-`^`(sqrt(3), -1), x__3), y__3 = Physics:-`*`(Physics:-`^`(sqrt(2), -1), x__1)-Physics:-`*`(Physics:-`^`(sqrt(2), -1), x__3)]):

NULL

 

Download 1.mw

Hi! 

 

I have been trying to solve the following system of equations:

 

ODEs:=diff(f[0, 0](x), x)+2.*f[0, 0](x)/x^5+.5000000000*f[0, 0](x)/x+0.1500000000e-1*f[0, 1](x)/sqrt(x) = -15.58845727*sin(.5773502693*x)/x^2+140.2961154*sin(.5773502693*x)/x^4-81.*cos(.5773502693*x)/x^3, diff(f[0, 1](x), x)+2.*f[0, 1](x)/x^5+.5000000000*f[0, 1](x)/x-0.6666666667e-2*f[0, 0](x)/sqrt(x) = -1039.230485*sin(.5773502693*x)/x^(5/2)+600.0000000*cos(.5773502693*x)/x^(3/2)-346.4101616*sin(.5773502693*x)/x^(9/2)+2078.460970*sin(.5773502693*x)/x^(13/2)-1200.000000*cos(.5773502693*x)/x^(11/2), f[0, 0](.1) = 1.503498543, f[0, 1](.1) = -1.053038610

 

Using dsolve I cant get it to work. I have tried both dverk78 and lsode methods, with default options. For example:

 

Sollsode := dsolve({ODEs}, numeric, method = lsode) 

 

Gives me the follwing error, if I try to estimate the solution anywhere past the initial point of 0.1: Error, (in Sollsode) an excessive amount of work (greater than mxstep) was done

I have also attempted to solve it with dverk78, thinking perhaps the improved accuracy of the method will help.

Soldverk := dsolve({ODEs}, numeric, method = dverk78) 

 

However I will get the following error message then: Error, (in Soldverk) cannot evaluate the solution past .10000000, step size < hmin, problem may be singular or error tolerance may be too small

 

 

Any ideas on how to proceed? Thanks so much!

I am trying to explore the equality of two lengthy expressions. Unfortunately, my relations that all are symbolic, are lengthy and I use 'verify' command to explore the equality of them. When I use this command the 'FAIL' message appears. Maybe it is because of lengthy expressions and Maple cannot exploring equality of them. I have attached the corresponding file. Does anyone know what's the real problem? Thanks in advance.

MMatrix.mw

I have some problems with Commutator and d_.

Please any help will be good for me.

Identidades_de_Bianchi.mw

 

Thanks a lot.

Hello, 

is there a way I can use data (variables) from Maple environment in the Maplesim environment. 

I have a scirpt in maple that generates the robots joints angles and need to use them in the 3D robot built in maplesim. I know I can export/Import data, but this sounds redundant. Is there a way to simply use an input block as a source of the data in maplesim and have the variable name generated in maple used int. Similar to what Matlab/Simulink does.. 

 

 

thanks.

Могу ли я использовать Клен, чтобы найти конкретные решения, которые выражаются либо в начальных и эллиптических функций для систем обыкновенных дифференциальных уравнений. Например, вы можете получить в Maple решений (sub_Solve01, sub_Solve02) для систем, которые перечислены в файле?
exp01.mw

hello
i have a problem that you could help me
i have an expression that i want convert it to an expression according to the expression q[d] with maple
i have bellow expressions
B[d]:=(-d*w[1]+w[3])/(((-2*w[1]+w[3])^2)-((-d*w[1]+w[3])^2))
B[o]:=(-2*w[1]+w[3])/(((-2*w[1]+w[3])^2)-((-d*w[1]+w[3])^2))
A[o]:=w[1]*(alpha[o]-c[o]-t[o])+2*w[2]*e[o]
A[d]:=w[1]*(alpha[d]-c[d]-t[d])+2*w[2]*e[d]
q[o]:=B[o]*A[o]-B[d]*A[d]
q[d]:=B[o]*A[d]-B[d]*A[o]
i want simplify expression U[d] such as this one
U[d]:=w[1]*(q[d]*(alpha[d]-q[d]-d*q[o]-c[d]-t[d])-C)+w[2]*(e[d]*q[d]+e[o]*q[o])+w[3]*((1/2)*(q[d]+q[o])^2)
I'm looking to simplify U[d] according to the expression q[d]
please please help me

 

``

``

``

plot(KummerM(1/2-(1/4)*sqrt(2*Nu), 1, sqrt(2*Nu)), Nu = 0 .. 120)

 

``

j := 1

"for i from 0 to 100000 do  Nu[i]= i/(1000); end do;    for i from 0 to 100000 do  if (KummerM(1/(2)-1/(4)*sqrt(2*Nu[i]),1,sqrt(2*Nu[i]))=0)  x[j]=Nu[i]; j= j+1;  end do if ;  end;   I know the answers for   x    are: 3.6568,  22.3047,  56.9605,  107.6203,  174.2820,  256.9450,  355.6088,  470.2730...     I    can    solve    only    one    of    them:           "

evalf(solve(KummerM(1/2-(1/4)*sqrt(2*Nu), 1, sqrt(2*Nu)) = 0))

3.656793458

(1)

PLEASE*HELP*ME

 

Download loop.mw

Hey,

Basically the problem is that when I try to derive a variable L, which is defined by a very big equation, Maple does not do the maple. But if I copy and paste the big equation it calculates everything perfectly. Could I get any insight on why is that?

The copy paste method is very space consuming.

Thanks in advance.

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