I've searched quite extensively across the internet and cannot seem to find my answer, even on this forum or in maple help.

     I'm trying to plot parametric surfaces using the (u,v) notation or in other words

cos(v)i + sin(v)j + (u)k

so have tried in maple as such:

cylinder := (u,v) -> [cos(v), sin(v), u];

Hello,

I was wondering what the easiest way to calculate the derivative of a matrix is?

So far I am trying:

> with(LinearAlgebra);
with(VectorCalculus);
> A := Matrix(2, 2, {(1, 1) = 1, (1, 2) = x^2, (2, 1) = 4*x^7, (2, 2) = x^3});
                           Matrix(%id = 163320844)
> B := D(A);
 

hi.

when i want to modify a parameter it's easy:

test1 := proc(x::uneval)
    x:=eval(x)+1;
    NULL;
end proc;

x:=5;
test1(x);
x;

ok x is now 6

How to do that with lists of names ?
ie writing a procedure test2 so that I can do that:

x:=10;
y:=20;
test2([x,y]);
x,y;
      11,21

thank you

 

Dear all:

   I wonder if there is any function in Maple checking whether a given function is (m-th) differentiable or continuous? 

 

Thanks,

Peter

Hi,

I have the following set of ODE:

sys := diff(U(t), t) = Itot/C-U(t)/(R*C), diff(U(t), t) = (Itot-I1(t))/C, diff(U(t), t) = I2(t)/C

The general solution is easily obtained by:

sol1 := dsolve({sys})

SOLUTION: sol1:={U(t)=Itot R+(e)^((-(t)/(R C))) _C1,I2(t)=-((e)^((-(t)/(R C))) _C1)/(R),I1(t)=(Itot R+(e)^((-(t)/(R C))) _C1)/(R)}

However, I cannot get the solution for initial conditions. In fact, we only need one initial condition, to solve for _C1:

IC:=U(0)=0  #Alternatively: I1(0)=0 or I2(0)=Itot.

Let w =f(z) = sum of z^(k+a) / (k + a)

where k= 0 to infinity and a is a nonzero parameter.

I need to find the inverse of this series, z = g(w). The powseries examples in Maple Help don't help. They don't work on my example, with a symbolic variable, a, stuck in there.  I hope that if I see about 7 or 8 terms of the inversion, I will get the general pattern.  I have tried to compute the inverse directly from the Lagrange Inversion Formula, but the complexity always grows too quickly for me to complete the solution, no matter which shortcut I try to take.

I have an equation which i have differentiated twice and evaluated at eta=1.
F''(eta)=-3*eta+(3*eta^5/20-9*eta/140)*R+(eta^9/840-3*eta^7/140+9*eta^5/1400)*R^2+...
evaluated at 1 we get
F''(1)=-1+3*R/35-394*R^2/40425+4924*R^3/6131125-43969148*R^4/980274920625+...
This equation is derived by an iteration process. Each time it is iterated we add an extra term where the power of R increases by 1.
I want to write R in powers of (F''(1)+3).
How would i go about doing this with maple?
If it is easier to write

Write a procedure

input:a polygon and a linear transformation

output :applying the transformation to the polygon
 

Find the coordinates of the linear transformation that would have  the a larger square to the pink (smaller) square.Apply the transformation to the blue square.
 

please help with this, thnaks

Hello, it's been awhile since I've used maple and I'm a little stuck here.

I'm basically trying to model charging of a capacitor with a load dependant voltage source. Capacitor voltage depends on source voltage but source voltage depends on capacitor voltage, classic ode problem. Now I can define the entire ode in one statement and then solve but I'd like to define the components that the ode is made of and then solve for d(f(x))/dx and then dsolve. When I try to build an ode with multiple statements however, I get a 'too many levels of resursion' error.

Use a procedure that takes as input a positive integer and two real numbers a and b
and produces as output  a polygon centered at (a, b). Base on the procedure,  obtain a list of twenty decagons centered in (0, 0), (1, 1), ..(20, 20)

(I have no hint,please help, thanks)

hi, i am trying to show that the sum of (1/2 + 2/3 + 3/4 + 4/5 + ... +n*(n+1)+ ...) can be approximated by the following: sum(1/(exp(1))^(1/n), n = 1 .. infinity). e.g. > sum(1/exp(1/n), n = 1 .. 10); print(1/exp(1)+1/exp(1/2)+1/exp(1/3)+1/exp(1/4)+1/exp(1/5)+1/exp(1/6)+1/exp(1/7)+1/exp(1/8)+1/exp(1/9)+1/exp(1/10)); 1 1 1 1 1 1 1 1 1 ------ + ------ + ------ + ------ + ------ + ------ + ------ + ------ + ------ exp(1) /1\ /1\ /1\ /1\ /1\ /1\ /1\ /1\

I have tried the Physics package. First of all, how can I define a non-ortogonal basis (using kets)? Suppose I have a basis formed by linearly independt vectors. How to set them non-ortogonal?

Using plot3d I can obtain a plot of a function u:=f(x,y). Then I rotate the plot and find the view that I want by trial and error. However, If I run the plot again with different parameters, I have to again find the view I want by trial and error. Setting the plot3d orientation option by trial and error to achieve the required view is very tedious. My question is: Once I have found the view I like, is it possible to then obtain the orientation data so that it can be used in subsequent calls to plot3d? Any help appreciated.

Hi there, in this post http://www.mapleprimes.com/forum/howplot1 I asked one plotting question when Y[1] and Y[2] are independent what if they are not independnt? say I have f( y1, y2) for Y[1] in [a,b] and Y[2] in[c,d] then I have U[1] = f ( Y[1], Y[2] ) and U[2] f ( Y[1], Y[2] ) (different functions of Y[1] and Y[2]) How do I plot the mapping for U[1] and U[2]? to determine the range for u1 and u2? Thanks Casper =============================