MaplePrimes Questions

We know that the  showstat()  function can provide some available source codes, but it also provides line numbers.  I need to delete one by one to use it, which is not efficient when I want to copy and modify codes. Is there any way to directly remove those line numbers.

for exampe:

showstat(PlaneDual);

I would like to know how to make a graph like the attached. The Figure IV is showing the changes in the evolution of the rate of technological progress (a topic in economics).

I would like to make a graph exactly like the image attached where it clearly shows the name of the x- and y-axis; the name of the functions; the 45-degree line; the transition from "theta_1" to "theta_2" with the arrows, etc. (In fact, I want to have everything the same from the graph). 

 

I have attached a PDF document with the definition of the functions and the figure itself. I have also attached the image of the figure on this thread. 

 

IMG_633.pdf

Dear everyone, ive been trying to get to learn Maple, and i am using the book: Advanced Problem
Solving Using Maple. 

I am having issues with not getting the same results as the examples. Although i am using the same imput as the examples. So to me that is really odd. I also noted to get the same results as the examples, i had to change the imput to get there. Now this is a bit more complex problem, and i cant figure out where it went wrong. 

Can you help me?

It did seem to produce the answers, however not in the same fashion as the example in the book. I still had to add the values together. No the solution i got is not what i am looking for. 

Greetings,

 

The Function 


 

DDS := a(n+1) = (1+.12*(1/12))*a(n)+1000

a(n+1) = 1.010000000*a(n)+1000

(1)

rsolve({DDS, a(0) = 0}, a(n)); a := unapply(%, n)

proc (n) options operator, arrow; 100000*(101/100)^n-100000 end proc

(2)

plot([-100000+100000*(101/100)^n], n = 0 .. 100, a = 0 .. 200000)

 

pts := {seq([k, a(k)], k = 0 .. 24)}; plot(pts, style = point, title = "Savings Account with Monthly Deposit")

 

rsolve({a(0) = 497.5124378, a(n+1) = -1.01*a(n)+1000}, a(n))

-(11/1005000000)*(-101/100)^n+100000/201

(3)

plot([-(11/1005000000)*(-101/100)^n+100000/201], n = 0 .. 20, a = 0 .. 1000)

 

solve(ev = -1.01*ev+1000, ev)

497.5124378

(4)

rsolve({a(n+1) = .5*a(n)+16}, a(n))

a(0)*(1/2)^n-32*(1/2)^n+32

(5)

rsolve({a(0) = 10, a(n+1) = .5*a(n)+16}, a(n))

-22*(1/2)^n+32

(6)

smartplot(-22*(1/2)^n+32)

 

rsolve({a(0) = 20, a(n+1) = .5*a(n)+16}, a(n))

-12*(1/2)^n+32

(7)

smartplot(-12*(1/2)^n+32)

 

rsolve({a(0) = 32, a(n+1) = .5*a(n)+16}, a(n))

32

(8)

rsolve({a(0) = 50, a(n+1) = .5*a(n)+16}, a(n))

18*(1/2)^n+32

(9)

smartplot(18*(1/2)^n+32)

 

solve(ev = .5*ev+16, ev)

32.

(10)

solve(ev = .5*ev+64, ev)

128.

(11)

rsolve({a(0) = A, a(n+1) = .5*a(n)+64}, a(n)); a := unapply(%, [A, n])

A*(1/2)^n+128-128*(1/2)^n

(12)

inits := [0, 50, 100, 150, 200]

gen := proc (i, j) options operator, arrow; evalf(a(inits, i)) end proc

proc (i, j) options operator, arrow; evalf(a(inits, i)) end proc

(13)

DrugConcTable := Matrix(10, 5, gen)

Matrix(%id = 18446746425282593366)

(14)

help("matrix")

``

``


 

Download Discrete_Dynamical_Models_2.mw

 

At age 25, Carrie establishes an individual retirement account (IRA). If she invests #4000 per year for 30years in an ordinary annuity, the account earns 7.75% per year. How much will she have in the account at age 25?

How difficult is it to animate a process using a binary tree for visualization purposes, something that isn't too slow or too complex to implement(as I will then just go with python or something) but also nice to look at(not just boring straight lines).

I'd like to animate, say, a ball moving through different branchings of a multi-tree(binary mainly but ultimately different branchings per node).

 

As an aside. Is there anything like C++ objects/structs in maple that are easy to create using . notation?

 

 

I have a procedure where M:=[m2,m3,m4...] and I  assign the m's values from list L:=[0.1,2....]
The procedure will only run once. Rerunning will not reassign the m's.

What is the correct way to do this?

Assign_in_proc.mw

 

Hi, I have an equation and I want y be as a fuction, in fact, I 'd like a function in which x is independent variable and y is dependent to x,could you please help me how to do it?

A is a complicated equation but doesn't have "y" in it so it is not important what it is, a and b also have values.

(a*y-x*(a+1))/(x^(2)-b*a^(2)*(y-x)^(2))=A


 

restart

sigma := 7.500*10^7+2.005*10^7*sinh(22985.642*z)-2.097*10^7*cosh(22985.642*z)

75000000.00+20050000.00*sinh(22985.642*z)-20970000.00*cosh(22985.642*z)

(1)

sigma_debond := 5.403*10^7

54030000.00

(2)

mid := 0.1653e-3

0.1653e-3

(3)

L := 0.2184e-3

0.2184e-3

(4)

plot(sigma, z = mid .. L)

 

plot(sigma_debond, z = 0 .. mid)

 

``


 

Download join_curves.mw

Hi everyone,

I have a system with trigonometric function, composed of 3 unknows (b,c,d) and 2 input (a,x). I would like to know how to express each of the unknowns in terms of a and x (if it's possible).

Here is my worksheet : test6.mw

Thanks everyone

HOW TO GUESS THE SUM OF FOLLOWING INFINITE SERIES IN MAPLE?

HOW TO GUESS THE EXACT  SOLUTION OF FOLLOWING INFINITE SERIES

How to plot 3D graph for the following infinite series sum?

How do I create a plot like Figure I as uploaded in the PDF-document?

On Figure I, you see the plot of two income functions. The income functions are defined by equations (5), (6), (7), and (8).
Please note that:
0<a<1
0<g<1
0<"tau"<1
0<"delta"*g<1
"delta" belongs to open interval (0,1)

/Regards.

IMG_499.pdf

For examples, they are two non-commutative variables x and y, and i use "Setup(noncommutativeprefix={x,y})" to define.
 As the previous results have shown that AntiCommutator(x,x)=0 and AntiCommutator(y,y)=0, so i just define Setup(algebrarules={%AntiCommutator(x,x)=0, %AntiCommutator(y,y)=0}).
When i am calculating AntiCommutator(x,y), the maple automatically simplifies the results and returns AntiCommutator(x,y)=0, as variables x and y are thought to be GrassmannParity =1 variables.

Consider two  3*3 matrix e23 and e32, the AntiCommutator of (e23, e23)=(e32,e32)=0, but the AntiCommutator(e23,e32)= e22+e33.

So how the algebrarules work and why there is the contradiction ?

How does Maple interpret the second line to get that result ??

I had to put expicitly a dot between the brackets to fix it.

 

Kind regards, Detlef Hoyer

First 382 383 384 385 386 387 388 Last Page 384 of 2427