I have couple questions on displaying/printing items I see from ShowContents(LibLocation). Here is an example

restart;
with(LibraryTools):
LibLocation:=cat(kernelopts(mapledir),"/lib/maple.mla");
c:=ShowContents(LibLocation):

First quesionNow, when I do
c[1];
then I see

When is "%?.m" there? Is this suppoed to be an actual function one can print?

second question

c[30]; gives

But when I do:

interface(verboseproc=3);
print(AiryBiZeros);

I get listing that ends up calling

---------------------------
proc(n::{algebraic, algebraic .. algebraic})
local fn;
   1   if nargs <> 1 then
   2     error "wrong number of arguments"
       end if;
   3   fn := traperror(evalf(n));
   4   if type(fn,'numeric') and not type(n,'posint') or type(fn,('numeric') .. ('anything')) and not type(op(1,n),'posint') or type(fn,('anything') .. ('numeric')) and not type(op(2,n),'posint') then
   5     error "expecting positive integers in argument"
       elif type(n,('integer') .. ('integer')) and op(2,n) < op(1,n) then
   6     NULL
       else
   7     ('AiryBiZeros')(n)   <----- Is this C function/compiled that is why it does not show?
       end if
end proc
--------------------------------------

Which is the same name I printed. So it seems to be another internal procedure with same name? How can I print it as well?

Is there a better way to print Maple procedures/command than what I am doing above so one gets full listing?
I tried Browse(); command in LibraryTools, but found it very cluncky to use (keeps losing listing and screen become blank. Very buggy)

How do I use msolve to solve y^2 + y - 11=0 in Zp for all primes p with 41=< p =<107 ?

Also, using the results make a conjecture describing the primes p for which there are solutions to y^2 + y - 11 = 0 in Zp

This was what I did.

41<=p<=107

msolve(y^2 + y - 11=0, p)

but I received this error, no implementation of msolve matches the arguments in call, msolve(y^2 + y - 11=0, p)

Any help is appreciated. Thanks

if given a prime ideal p, is it possible to find back possible ideal A which output this prime ideal

such that p*A = 0

I have a coefficient matrix A and the constant matrix b.

I want to find the unknowns x_1,x_2,...,x_8. When I put my code and run it in Maple I get an error. Any ideas as to why this is happening? The code I tried is as follows:

with(Student[NumericalAnalysis]):

A := Matrix([[-1, 0, 0, (1/2)*sqrt(2), 1, 0, 0, 0], [0, -1, 0, (1/2)*sqrt(2), 0, 0, 0, 0], [0, 0, -1, 0, 0, 0, 1/2, 0], [0, 0, 0, -(1/2)*sqrt(2), 0, -1, -1/2, 0], [0, 0, 0, 0, -1, 0, 0, 1], [0, 0, 0, 0, 0, 1, 0, 0], [0, 0, 0, -(1/2)*sqrt(2), 0, 0, (1/2)*sqrt(3), 0], [0, 0, 0, 0, 0, 0, -(1/2)*sqrt(3), -1]]);

b := Vector([0, 0, 0, 0, 0, 10000, 0, 0]);

LinearSolve(A, b, maxiterations = 300, method = SOR(1.25), tolerance = 10^(-2));

I also tried it with a SOR variable of 1.5 instead of 1.25, but that gives me the same error.

Hello,

Is it possible in Maple to select summand with some command?

For example:

eq := a+b = 0;
                           a + b = 0
eq-b;
                             a = -b

How to generalize second line?(in this case I explicitly told to subtract b, but I want to pick b by some command)

And I am not talking about solving, isolation or anything like that in this case. I just want to transfer something from lhs to rhs by selecting it beforehand.

Thank you.

Hello,

How can one simplify following expression:

After applying 'simplify' command I am getting this:

Powers are not distributed between bases.

How to force Maple simplify it further to

Thank you.

Hello,

Is it possible to hide the geometry linked to the center of gravity and masses in the implicit geometry and keep only the kinematic joint.

If yes, may you explain how ? For the moment, I only manage to show/hide all the element of the implicit geometry. 

I use MapleSim 6.4.

Thank you for your help.

I have a DEplot :

DEplot(sys, [x(t), y(t)], t = 0 .. 30, [[x(0) = 0.8, y(0) = 0]], x = -1.25 .. 1.25, y = -1.25 .. 1.25, numpoints = 300, axes = boxed);

I would like to draw on this plot two circles centered in the origin with different radiuses.

How can I proceed?

How can I plot a vertical line say x = a in Maple 15 worksheet?

Thanks

I have about a year of experience in Maple, but as we know, we often come accross very simple problems that are difficult to find solutions to. Part of the problem is that I have not used conditional tests within for loops before.

I have a very large matrix, but until I solidify the algorithm, I'm practicing on a small matrix.

I created a 3 by 3 fibonacci matrix A:=<21,5,1|13,3,1|6,2,0>

I am trying to change the 1s to 0s without specific index reference. Here is my psuedocode that I hope to work on after some tips:

• for i from 1 to 9
  if A[k] = 1 then
  A[k]=0
  end if
  end do

I get an error message saying "unterminated for loop," which is confusing me.

I have 4 retangular equations:

z0:=sqrt(3)+I
z1:=-1+I*sqrt(3)
z2:=-sqrt(3)-I
z3:=1-I*sqrt(3)

on polar form they apear as:

polar(z0)=(2,Pi/6)
polar(z1)=(2,2*Pi/3)
polar(z2)=(2,-5*Pi/6)
polar(z3)=(2,-Pi/3)

I want those polar expressions plottet in a polarplot as points(x,y), how is that possible ?

I want to integrate the following cumulative distribution function with variable bounds but maple returns the integral.

>with(Statistics);

>N := RandomVariable(Normal(0, 1)):

>a := (ln(98.53*(1/95))+(0.1e-1+.5*x^2)*.5)/(x*sqrt(.5))

>y:= CDF(N, a, inert = true);

How do i make maple return a function of x instead of an integral?

I'm trying to write the cumulative distribution function into maple but I seem to get an error. The code is:

>with(Statistics):

>N:=RandomVariable(Normal(0,1)):

>CDF(N,t,inert=true);

I get an error message "Error, (in Statistics:-CDF) unexpected parameters: inert = true".

It used to work, maybe because I was using a newer version of Maple.

http://uknowledge.uky.edu/cgi/viewcontent.cgi?article=1001&context=math_etds

Example 3.23 in page 24

degree(2*z^2 + z + 2); #2

how to convert rational function to into (something) - (something) + (something) like in the example

the example 's rational function is 2*z^2+z+2

if rational function is has denominator how to calculate?

2z^2 + z + 2 =

z+2
3


−

z−2
3


+

z+1
2


−

z−4
2


+

z
1


−

z−8
1

when calculate delta p1, what is bi? how to calculate like the example's one?

(z+i-1 i+1-j) - (z+i-bi-1 i+1-1)

sum(d,i=j) (z+i-1 i+1-j) - (z+i-bi-1 i+1-1)

3.23
(z 1) - (z-bi 1)

how to do the expansion in step 3, as i use right shift that can not calculate the same result as in the example.

x0*x1/x0 = x1; # not same as in the example for I

x1^4*x2/x1 = x2*x1^3;  # not same as in the example for I

finally would like to apply to hilbert series 1/((1+z)*(1+z^2))

Joe Riel,

I am interested in making some adjustments to the Syrup package to help tailor it to my needs (expanded error descriptions, variable partial differentiations, and others).   A little over a year ago I had some dialog about how to make Syrup changes, but the program I was working on at the time, cancelled the Maple effort...

I need guidance on (1) how the Maple code is structured so I may explore modest changes, (2) what suggestion do you have on the easiest/smartest code development environment, (3) how to compile the changed code, then (4) how to rerun the revised Syrup.

Thank you and happy holidays.
Jeff Belue