Rouben Rostamian

MaplePrimes Activity

These are questions asked by Rouben Rostamian

This looks like a bug to me but please correct me if it is not.



`Maple 2021.2, X86 64 LINUX, Nov 23 2021, Build ID 1576349`

half_angle_rule := [
        sin(x::name) = 2*sin(x/2)*cos(x/2),
        cos(x::name) = 1 - 2*sin(x/2)^2

[sin(x::name) = 2*sin((1/2)*x)*cos((1/2)*x), cos(x::name) = 1-2*sin((1/2)*x)^2]

In this example, Maple applies the rule to the first element only.
It should apply to both.

A := < sin(u), sin(u) >;
applyrule~(half_angle_rule, A);

Vector(2, {(1) = sin(u), (2) = sin(u)})

Vector[column](%id = 36893628627946684772)

In this example, Maple applies the rule to the second element only.
It should apply to both.

B := < cos(u), cos(u) >;
applyrule~(half_angle_rule, B);

Vector(2, {(1) = cos(u), (2) = cos(u)})

Vector[column](%id = 36893628627946688132)



While solving an exercise in class, I ran into the following interesting solution of a transcendental equation.  It was not intentionally designed to be like this.

eq := 2*exp(-2*t) + 4*t = 127:
fsolve(eq, t=0..infinity);

The solution looks like a rational number while it was expected to be transcendental.  Let's increase the number of digits:

Digits := 20:
fsolve(eq, t=0..infinity);
Digits := 10:

Let's make it even more accurate:

Digits := 29:
fsolve(eq, t=0..infinity);
Digits := 10:

And even more:

Digits := 40:
fsolve(eq, t=0..infinity);
Digits := 10:

Is there a deep reason why the solution is so close to being a rational or is it just a coincidence?


I may be misunderstanding the documentation of implicitplot.  Can someone set me straight?

This is extracted from the implicitplot's help page:

implicitplot(-x^2 + y, x = 0 .. 2, y = 0 .. x);

The plotting range is limited to y ≤ x, as intended.  Let us verify that it does the right thing:

	implicitplot(-x^2 + y, x = 0 .. 2, y = 0 .. x, color=red),
	plot(x, x=0..2, color=blue)

Yes, indeed it does.

Now let us try limiting the plotting range to y ≤ 1 − x2. Here is what we get:

	implicitplot(-x^2 + y, x = 0 .. 2, y = 0 .. 1-x^2, color=red),
	plot(1-x^2, x=0..2, color=blue)

I expected the red curve to lie entirely below the blue curve but it doesn't. Am I misunderstanding implicitplot?

Download worksheet:

I need to calculate dozens of piecewise-defined  (but elementary) definite integrals of the following kind. Maple returns them unevaluated. Is there a trick to force evaluation? 

u := piecewise(0 <= x and 0 <= y and y <= x, x-1, 0 <= x and 0 <= y and x <= y, x, 0);
v := piecewise(0 <= x and 0 <= y and y <= x, x-1, y <= 0 and 0 <= x and -x <= y, x-1, 0);
plot3d(u*v, x=-1..1, y=-1..1);
# integrating over (0,1)x(0,1) works
int(u*v, x=0..1, y=0..1);
# but integrating over (-1,1)x(-1,1) returns unevaluated.
# How to force evaluation on (-1,1)x(-1,1)?
int(u*v, x=-1..1, y=-1..1);


I want to plot a 2D graph without labels. The labes=["",""] option does half of the job—it prints the empty string for labels (that's good) but it reserves room for them (that's bad).  In the following code I use a large size labelfont in order to exaggerate the effect:

plots:-setoptions(labelfont=[TIMES,64]);  # large labelfont selected on purpose
p1 := plot([[0,0],[1,1]], labels=["", ""]);

Note the large blank space at the bottom reserved for the the non-existent label.

I know one way to eliminate the label altogether:

p2 := subs(AXESLABELS=NULL, p1);

This does the right job but is there a more orthodox way of doing that?

Afterthought:  It would be good if the labels option to the plot command  accepted none as argument, as in labels=[none, none].

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