Melvin Brown

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13 years, 251 days

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These are replies submitted by Melvin Brown

@Kitonum 

many thanks; even shorter and same answers as other 2 solutions

MRB

@Carl Love @Kitonum

Many thanks to you both for your impressively prompt reponses and your neat solutions to my problem - and the benefit of cross checking two solutions tothe same problem.  I can now get ahead; cheers.

Melvin Brown

 

@tomleslie 

Are there any plans to extend pdsolve,numeric to solving for functions of more than 2 independent variables?

MRB

@Preben Alsholm 

Thanks again for this and your other contribution 'On using the transform; very helpful. Yes, I wanted to have both the particle and the plots; you and Kitonum, between you, have supplied both!

Much appreciated

MRB

@Kitonum 

Thanks very much for re-drafting my code; your results are what I was aiming for...

MRB

@Preben Alsholm 

Preben thanks for your help on this...

plrPt := proc (t) options operator, arrow; plots[polarplot]([[sin(t), 0], [cos(t), (1/3)*Pi], [cos(2*t), (2/3)*Pi]], axiscoordinates = polar, symbol = solidcircle, style = point, color = red, symbolsize = 12) end proc

MRB

@Melvin Brown 

Just checked again...

Correction: 

plots[fieldplot3d]([2*x, 2*y, 2*z], x = -1 .. 1, y = -1 .. 1, z = -1 .. 1, grid = [5, 5, 5], arrows = SLIM,
colorscheme=["xyzcoloring", (x, y, z)->sin(x)*sin(y)*sin(z)]);

was indeed ignored, as you found.

MRB

@vv 

 

Thanks;

plots[fieldplot3d]([2*x, 2*y, 2*z], x = -1 .. 1, y = -1 .. 1, z = -1 .. 1, grid = [5, 5, 5], arrows = SLIM,
colorscheme=["xyzcoloring", (x, y, z)->sin(x)*sin(y)*sin(z)]);

does indeed work in my 2016.1 version.

MRB

@Preben Alsholm 

Thanks:

color = RGB(sin(x),sin(y),sin(z)) does indeed work in my 2016.1

 

MRB

 

@tomleslie 

....That seems to have worked.  Thanks

@roman_pearce 

Thanks for your help.  (It's getting close to decision time on whether to take the free upgrade to Windows 10 or to stay with Windows 7 for a few more years.)

MRB

@cskoog 

Many thanks; very helpful.

MRB

Thanks, acer.  I'll draw a line under that; it would have been very useful.

MRB

@acer

Ah...  the .mla seems to be in binary (or other obscure format)... at least from viewing in Notepad, it seemed so.  But perhaps there are MAPLE commands that will list the contents of a .mla?  

However, I've just found that one can at least write protect an .mla file

LibraryTools[WriteMode]("/home/user/mylib/MyLib.mla","READONLY");

to guard against accidental corrpution.  I guess one can easily reset the write mode, if necesaary?

MRB

 

 

@acer 

Many thanks. I did appreciate the distinction between those two options, but I was interested to see if it could done with an .mla, partly for security of the code, should that be required.

I'll take a look at the putting the code in the start up code section

MRB

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