Melvin Brown

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14 years, 37 days

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These are replies submitted by Melvin Brown

Daniel

Thanks for your guidance.  I'll see how it goes.

Melvin

@Kitonum 

... great, that works well.

 

Thanks

Melvin

@acer 

Thanks; that's great help.

Melvin

@Kitonum 

 

Thanks for clearing up the code; much appreciated.

Melvin

 

@Carl Love 

Carl 

Many thanks; that has cleared up my problem.

Melvin

@Kitonum 

many thanks; even shorter and same answers as other 2 solutions

MRB

@Carl Love @Kitonum

Many thanks to you both for your impressively prompt reponses and your neat solutions to my problem - and the benefit of cross checking two solutions tothe same problem.  I can now get ahead; cheers.

Melvin Brown

 

@tomleslie 

Are there any plans to extend pdsolve,numeric to solving for functions of more than 2 independent variables?

MRB

@Preben Alsholm 

Thanks again for this and your other contribution 'On using the transform; very helpful. Yes, I wanted to have both the particle and the plots; you and Kitonum, between you, have supplied both!

Much appreciated

MRB

@Kitonum 

Thanks very much for re-drafting my code; your results are what I was aiming for...

MRB

@Preben Alsholm 

Preben thanks for your help on this...

plrPt := proc (t) options operator, arrow; plots[polarplot]([[sin(t), 0], [cos(t), (1/3)*Pi], [cos(2*t), (2/3)*Pi]], axiscoordinates = polar, symbol = solidcircle, style = point, color = red, symbolsize = 12) end proc

MRB

@Melvin Brown 

Just checked again...

Correction: 

plots[fieldplot3d]([2*x, 2*y, 2*z], x = -1 .. 1, y = -1 .. 1, z = -1 .. 1, grid = [5, 5, 5], arrows = SLIM,
colorscheme=["xyzcoloring", (x, y, z)->sin(x)*sin(y)*sin(z)]);

was indeed ignored, as you found.

MRB

@vv 

 

Thanks;

plots[fieldplot3d]([2*x, 2*y, 2*z], x = -1 .. 1, y = -1 .. 1, z = -1 .. 1, grid = [5, 5, 5], arrows = SLIM,
colorscheme=["xyzcoloring", (x, y, z)->sin(x)*sin(y)*sin(z)]);

does indeed work in my 2016.1 version.

MRB

@Preben Alsholm 

Thanks:

color = RGB(sin(x),sin(y),sin(z)) does indeed work in my 2016.1

 

MRB

 

@tomleslie 

....That seems to have worked.  Thanks

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