taro

470 Reputation

12 Badges

7 years, 251 days
Maple is to me difficult. The first version I bought was Maple9, and it was more than 15 years ago. But, I couldn't use it, feeling it too difficult. But, three years ago, I thought Maple might be helpful to my study, and since then, I have continued to learn Maple. As I got able to read the Maple help, I think that I could get to use maple better now than before. But, I feel that I am a beginner yet.

MaplePrimes Activity


These are replies submitted by taro

@acer 

Thank you for teaching me.

 

@Carl Love 

Sorry, Carl.

I couldn't understand the code of convert/list.
I will appreciate if you write some comments on the code.

Sorry.


 

 

@acer 

Thank you for teaching me a lot.
And, thank you for your detailed worksheet.
I could understand that 3 means the hight z, owing to you.

 

@acer 

Thank you. Owing to you, I could understand what I hadn't understood before.
I have another question.

1 of (3, 2, 1) = HFloat(-.832293673094284814) means 1 of x_1, and 2, which is at the end of (3,2,2), means 2 of x_2. So, I did understand. Then,
what is 3 at the end of (3, 2, 3)? What is 3 at the end of (2, 2, 3) = HFloat(1.)?

As vector has only two dimensions of x_1 and x_2, so I can't understand from where 3 appeared.
I hope you will give me an answer to this question of mine.

 

 

@acer 

Thank you.
I could get the output file with the way you kindly taught to me.

 

 

@Preben Alsholm 

Thank you for teaching me quite a lot.
As for the principal root, I couldn't understand till you teach it to me.
And, reading your answer, I found it necessary to solve the cubic equation to obtain 1+RootOf(_Z^2 + 3, index = 1).

I had thought only modifying x^3 + 8=0 was necessary to do it, and I couldn't do it.

Thank you for teaching me.

 

 

 

@acer 

Your way of how to use maple to have maple calculate step by step is, I think, one which is applicable widely to various calculation. It will be very helpful to me in using maple hereafter.

Thank you very much

@Kitonum 

Simplifying the double square was very difficult to me.
Your way to solve the problem is very helpful.
Thank you.
 

I tried what you mentioned, but even with parameters not numbers, factoring worked well.

example.mw

So, please append your file.

I think your worksheet might be necessary.

 

@acer 

Thank you for telling me the difference of the outputs according to the expression to which
the code is directed.

 

@John Fredsted

Thank you for your reply, and for telling me a simple and very helpful code.

 

@John Fredsted 

Hello, by the way, as this is a good opportunity I think I will ask you.
How do you manage so called session dependency?
Do you think that only sort command remove that dependency?
Thinking of it, it might be better to avoid to use commands related to op, but
doing so surely makes it inconvenient to write codes.
I hope for hearing from you about your dealing with those dependencies in general.

@acer 
Thank you.
I spent a time in understanding your code. And, now, I understand it.

And, the actual numerator and the actual denominator are different from those seen in screen, multiplied by , in my case, Omega, and sometimes multiplied by (-1), so that in that case the signs of the denominater and the numelator have changed.

And, the order of terms in the same expression differs at each time restart is executed and
the calculation begins from the top of the worksheet.

Your code is about the way to deal without these complexities.
Extracting contents of an expression as you do in your code
is very useful information to me.

Thank you.

p.s.
I surely understand your code. But, what I think I had understood haven't
fallen into my mind,yet. So, there might be the case that I have to ask to you
about your code. In that case, I will be very glad if you rely to my then question.

 

 

@John Fredsted 

Thank you very much.
expand in expand(x/denom(a)) was what I couldn't write before I asked about the question.
I owe you a lot.
 

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