## 300 Reputation

12 years, 149 days

## Two different answers...

When i try the programs of Kitonum 175 and Joe Rien, i get different answers. I don't understant.

## Thank you...

Thank you very much.

## Thank you...

Thank you very much.

## How i can find the values of f(k) with &...

`How i can find the values of f(k) with  `
`f:=k->Pi/9+2*k*Pi/3 `
`and k is solutions of `
`isolve({(1/9)*Pi+2*k*Pi*(1/3) >= 1, (1/9)*Pi+2*k*Pi*(1/3)<= 2^Pi});`
`Please help me. Thank you.`

## How i can find the values of f(k) with &...

`How i can find the values of f(k) with  `
`f:=k->Pi/9+2*k*Pi/3 `
`and k is solutions of `
`isolve({(1/9)*Pi+2*k*Pi*(1/3) >= 1, (1/9)*Pi+2*k*Pi*(1/3)<= 2^Pi});`
`Please help me. Thank you.`

## Thank you...

Thank you very much.

## Thank you...

Thank you very much.

## Thank you...

Thank you very much.

## Thank you...

Thank you very much.

Thank you.

Thank you.

## convert...

How can i convert M :=<1,-1,3> into point(M, 1, 2, 3)? Please help me. Thank you very much.

## convert...

How can i convert M :=<1,-1,3> into point(M, 1, 2, 3)? Please help me. Thank you very much.

## This is my algebraic method...

This is my algebraic method. Note that, u:=<a,b,c> is direction vector of the line Delta.

restart;with(geom3d): with(LinearAlgebra):

A:=<1,-1,3>:

plane(P,x+y+5*z=0,[x,y,z]):

line(l, [2*t,-5*t, 6*t],t):

n:=convert(NormalVector(P),Vector):

v:= convert(ParallelVector(l),Vector):

u:=<a,b,c>:

w:=CrossProduct(v,u):

d:=abs(DotProduct(w,A,conjugate = false))/Norm(w,2):

solve([a^2 + b^2 + c^2 = 1, d = 1, DotProduct(n,u, conjugate = false)=0],[a,b,c]);

## Thank you...

First, many thanks to Kitonum. Because i want to have a beautiful answer, therefore, i write the equation circle passing three points A, B, C. And then, write the equation tangent of the circle (ABC) at the point C. Thus, the line is this equation of this tangent. Now, i hope Kitonum understand my idea. Thank you again.

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