Could this Multi-Threading Loops thread be the related query you are referring to?

http://www.mapleprimes.com/questions/36771-MultiThreading-Loops

Unfortunately for myself the trickery involves making it work without the refresh=true option.  At the same time I'm also trying to understand the underlying lower level I/O commands. 

There is a streamcall to INTERFACE_COMPONENTSET but I don't think that will help. 

Originally, yes I had intended to try it from a TextArea component.  

I am hoping someone might be able to come up with some code that enters a different character for each keypress, doesn't really matter the route to get there, just hoping it's possible somehow in Maple.

Originally, yes I had intended to try it from a TextArea component.  

I am hoping someone might be able to come up with some code that enters a different character for each keypress, doesn't really matter the route to get there, just hoping it's possible somehow in Maple.

My goal was to change the entered input.

I suppose a Maplet would work better, but the idea is, as the user is typing an entry the letters are replaced by the next letter in the alphabet. 

The real concept is not so much just to shift the letters but how to make it output the next letter as one types. 
ie.  the keyed entry of ... is this interesting ... would be displayed as ... jt uijt joufsfujoh

Of course that is simply done as a whole but can it be done on a keystroke by keystroke basis?

My goal was to change the entered input.

I suppose a Maplet would work better, but the idea is, as the user is typing an entry the letters are replaced by the next letter in the alphabet. 

The real concept is not so much just to shift the letters but how to make it output the next letter as one types. 
ie.  the keyed entry of ... is this interesting ... would be displayed as ... jt uijt joufsfujoh

Of course that is simply done as a whole but can it be done on a keystroke by keystroke basis?

A link to the exact question more recently. 

http://www.mapleprimes.com/questions/144906-Using-RSA-Give-Your-Encryption-As-A

Hm, same question is yet again asked years later.  An answer exists there

http://www.mapleprimes.com/questions/144906-Using-RSA-Give-Your-Encryption-As-A

Hm, same question is yet again asked years later.  An answer exists there

http://www.mapleprimes.com/questions/144906-Using-RSA-Give-Your-Encryption-As-A

This should be the right solution.  It is worked out for the case of alpha=0 and answers shown in terms of an unknown load L.  Negative values indicate that member is in compression, while positive under tension.  Near the end of the worksheet I was only trying to verify that the equations matched my worked out paper version equations for alpha=0.

Download truss2.mw

The general case is quite messy but can easily be found, but subsituting a value for alpha gave it a cleaner look.  Also you can see what happens if alpha is set to 180 degrees that the CE member value becomes positive (under tension).  

This solution is one way to do it.  I haven't actually tried to figure out where your mistake is in your code.

This should be the right solution.  It is worked out for the case of alpha=0 and answers shown in terms of an unknown load L.  Negative values indicate that member is in compression, while positive under tension.  Near the end of the worksheet I was only trying to verify that the equations matched my worked out paper version equations for alpha=0.

Download truss2.mw

The general case is quite messy but can easily be found, but subsituting a value for alpha gave it a cleaner look.  Also you can see what happens if alpha is set to 180 degrees that the CE member value becomes positive (under tension).  

This solution is one way to do it.  I haven't actually tried to figure out where your mistake is in your code.

So how can we get Maple to output a radical in the denominator.  Does Carl's proc fix it?  I'm not using uprotect so I won't run it. 

Basically if a solution outputs an answer with sqrts, I'd like a proc that will force all of the sqrt(#)/# back to 1/sqrt(#)

Similarily x/2^(1/6) , gets turned it into   x * ( 2^(5/6) ) / 2   .   Why can't the radical just stay in the denominator?  It makes no difference to the computer wether it's in the numerator or denominator, I'd like to see it in the denominator. 

As a side note distraction, but not to detract from what we're trying to achieve here in Maple, Mathematica will keep the output of 1/(2^(1/2)). 

So how can we get Maple to output a radical in the denominator.  Does Carl's proc fix it?  I'm not using uprotect so I won't run it. 

Basically if a solution outputs an answer with sqrts, I'd like a proc that will force all of the sqrt(#)/# back to 1/sqrt(#)

Similarily x/2^(1/6) , gets turned it into   x * ( 2^(5/6) ) / 2   .   Why can't the radical just stay in the denominator?  It makes no difference to the computer wether it's in the numerator or denominator, I'd like to see it in the denominator. 

As a side note distraction, but not to detract from what we're trying to achieve here in Maple, Mathematica will keep the output of 1/(2^(1/2)). 

So what about a procedure that can do it?

So what about a procedure that can do it?

Oh, right.  I meant to say.  Is there a simple procedure we could create to force any sqrt(a)/a values back to 1/sqrt(a)

And I'm going to have to disagree with the rationalization for ease of divisibility because what about sqrt(7)/7 - it is not simplified to 1/sqrt(7).  It just so happens that any simplification of numerical values are reduced down to values with sqrts in the numerator.  Perhaps a debate will ensue about which is better.  Personally I think two numbers (one of them being a 1) is better than two numbers where neither is a 1.

As for a procedure, any suggestions?