khajehmiri

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13 years, 272 days

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I want solve this inequations

> solve((1/4*(beta^2-6))*(-beta^2+2*alpha) > 0);
After running, maple gives an answer in four lines alpha < (1/2)*beta^2 0 < -(1/2)*beta^2+3 (1/2)*beta^2 < alpha -(1/2)*beta^2 < -3 [] beta = -sqrt(6) [] beta = sqrt(6) now I have questions: 1) In spite of knowing range of beta in thhe second parts of first two lines of answer, why maple...

I write this code:

> e1 := a-3;
a - 3
> e2 := sqrt(6)*b+6;
(1/2)
6 b + 6
> trac := e1+e2;
(1/2)
a + 3 + 6 b
> dter := e1*e2;
/ (1/2) \
(a - 3) \6 b + 6/
> dell := trac^2-4*dter;
2

I explain my problem with an example:

 

When I write

sort(3x^3+x^2+x+1);

the answer is

      3    2        
 3 x  + x  + x + 1

 But when I write

sort((x+1)(x+2))

answer is

x(x+2)+1

while I want this form:

   2          
 x  + 2 x + 1

Even when I type only

(x+1)(x+2)

into a blank page, again the answer is 

x(x+2)+1

not 

I have a system with two nonlinear inequality. How can I solve the system?

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