Hi,

I am trying to graph some curve C and the vectors from the vector field corresponding to t=1 and t=-1.

My Vector Field is defined by some F(x,y,z) and my Curve is some r(t) [didn't bother putting the actual values here since I only want a general expression...]

In other words I want to have some kind of a curve in 3D with vectors coming out at points t=+/-1 along the curve itself. Is there any way to do such thing?

Thanks!

Hi,

I would like the title of my y axis to say "SaO_² (%)".  When I put in "SaO[2] (%)" the output is SaO[2] (%); However, when I put in SaO[2] (%) the output is "SaO₂ PLOT (...) "  How can I get both parts correct (i.e., the subscript of the 2 and the displaying of the percent sign)?

Thanks!

Hello, I have tried to solve a system of ODE about the gyroscope for a week. I have entered the following commands : >eq1:=(l^2+r^2/2)*(sin(theta(t))^2*diff(diff(psi(t),t),t)+2*diff(psi(t),t)*diff(theta(t),t)*cos(theta(t)))-r^2*(cos(theta(t))*diff(psi(t),t)+omega(t))*diff(theta(t),t)=0;>eq2:=(l^2+r^2/2)*(diff(diff(theta(t),t),t)-(diff(psi(t),t))^2*sin(theta(t))*cos(theta(t)))+r^2*(diff(psi(t),t)*cos(theta(t))+omega(t))*diff(psi(t),t)*sin(theta(t))=g*l*sin(theta(t)); >eq3:=diff(diff(psi(t...

I want to know for what combinations of parameters (x,y) the following holds: Prob(X(x) + Y(y) < z) = alpha. X and Y are random variables (I want to look at different distributions), z and alpha are constants. I tried the following (simplified with X=Y):

Dear Sir / Madam,

Would you recommend me how to isolate the real and imaginary part and simplify the equation A? Maple cannot evaluate this equation to numeric value...

A := evalf(sqrt((Re(B))^2 + (Im(B))^2));
A := evalf(abs(B));

are not working.

I have attached my equation function.txt

f(x)=(sin@@3)(0.5143600172e-2+1.000000039*arcsin(arcsin(sin(sin(-0.1543083839e-1+.9999999610*RootOf((sin@@3)(_Z)-(sin@@3)(0.5143619410e-2+1.000000000*RootOf(-(sin@@3)(_Z)+x))))))))

i want to find inverse of this funtion i am getting nothing

>s := solve(w = f(x), x)

    s:=

i am getting like above.

i want to find inverse of above function plz give me reply to me.

f :=  (0.1953125000e-2+.3750000000*(RootOf(-512*x-7+192*_Z^(2/3)+24*_Z^(1/3)+512*_Z-6*(512*_Z+192*_Z^(2/3)+24*_Z^(1/3)+1)^(2/3)+12*(512*_Z+192*_Z^(2/3)+24*_Z^(1/3)+1)^(1/3))^(2/3))+0.4687500000e-1*(RootOf(-512*x-7+192*_Z^(2/3)+24*_Z^(1/3)+512*_Z-6*(512*_Z+192*_Z^(2/3)+24*_Z^(1/3)+1)^(2/3)+12*(512*_Z+192*_Z^(2/3)+24*_Z^(1/3)+1)^(1/3))^(1/3))+RootOf(-512*x-7+192*_Z^(2/3)+24*_Z^(1/3)+512*_Z-6*(512*_Z+192*_Z^(2/3)+24*_Z^(1/3)+1)^(2/3)+12*(512*_Z+192*_Z^(2/3)+24*_Z^(1/3)+1)^(1/3)))^3

Hi all

I have used pointplot3d to plot a set of points using three vecotrs v1, v2 and v3 which all contain many elements and the same number of elements.

I would like to know how to plot a new set of elements for new vectors v4,v5, and v6 on to the same plot as the previous set of values.

Could I then give each of the two sets a different color?

I am to solve this differential equation (nonlinear):

C'(t) = G[0]+0.1*sqrt(C(t))-C(t)*n+C[ude]*n

G[0] = 1.7*1.2*83

n = 6

C[ude] = 417

i need to use programming since the DE is nonlinear.

Does anybody have the solution to that?

Thanks in advance.

Best regards,

Marie

f:=x->x^3:
y[1]:=0.5:
y[3]:=subs(x=y[1],f(x)):
i := 2:
y[i] := y[i-1]-(y[1]-y[2+1])*(1/2):
i:=1:
g[i] := (y[i+1]-y[i+2])*x/(y[i]-y[i+1])+(y[i+2]*y[i]-y[i+1]*y[i+1])/(y[i]-y[i+1]):
g[i] := unapply(g[i], x):
h[i] := unapply(solve(y = g[i](x), x), y):
for i from 2 by 1 to 7 do
g[i]:=(f@h[i-1])(x);
g[i]:=unapply(g[i],x);
y[i+2]:=subs(x=y[i+1],g[i](x));
s:=solve(z=g[i](x),x);
h[i]:=unapply(s[1],z);
end do:

for i from -1 by -1 to -8 do

f:=x->x^3:
y[1]:=0.5:
y[3]:=subs(x=0.5,f(x)):
i := 2:
y[i] := y[i-1]-(y[1]-y[2+1])*(1/2):
i:=1:
g[i] := (y[i+1]-y[i+2])*x/(y[i]-y[i+1])+(y[i+2]*y[i]-y[i+1]*y[i+1])/(y[i]-y[i+1]):
g[i] := unapply(g[i], x):
h[i] := unapply(solve(y = g[i](x), x), y):
for i from 2 by 1 to 5 do
g[i]:=(f@h[i-1])(x);
g[i]:=unapply(g[i],x):
s:=solve(y=g[i](x),x):
h[i]:=unapply(s[1],y);
end do;

 for this code i got error "Error, (in kernels)...

I have a system of equations  AX=B where the matrix A from dimension 307x200, X from 200x1, and B from 307x1
How can I use Gauss elimination to solve these system of equations.

Hi,

QQ.mw

I want to find the inverse function of the given function h(m),and also plot the inverse.I can't find any help to evaluate the inverse function in an explicit form.I plot the inverse though,but why its so ugly?How I can customize its domain & range?

I'm trying to use dsolve to get a numeric solution to a series of differential equations I have. I've got:

G := 1;

M := 1;

pT := 2;

OrbitEnergy :=  (r0) -> -1/r0+(1/2)*L^2/r0^2-L^2/r0^3;

OrbitDEs := diff(r(tau), [tau$2]) = -G*M/r(tau)^2+L^2/r(tau)^3-3*G*M*L^2/r(tau)^4, diff(phi(tau), tau) = L/r(tau)^2, diff(t(tau), tau) = sqrt(r(tau)/(r(tau)-2*G*M)+(diff(r(tau), tau))^2*r(tau)^2/(r(tau)-2*G*M)^2+r(tau)^3*(diff(phi(tau), tau))^2/(r(tau)-2*G*M));

Dear Sir / Madam,
Could you recommend me how to find the square root of the complex equation correctly?
My equation looks like this
sqrt(complex_equation_1^2 + complex_equation_2^2).