Hi all,

For example, I have:

restart:

with(VectorCalculus):

z1:=1+I*5;

z2:=6-I*3;

I want to plot three vectors which are represented by z1, z2 and z1+z2.

I can plot them as:

PlotVector([<Re(z1),Im(z1)>,<Re(z2),Im(z2)>,<Re(z1+z2),Im(z1+z2)>],color=[red,blue,yellow]);

But the three vectors have origin at point x:=0 and y:=0.

I can change this by applying VectorSpace as:

vs1 := VectorSpace('cartesian', [0, 0...

I found following bug:

p := proc (k) sum((-1)^n*n/(factorial(k-n)*factorial(n)), n = 1 .. k) end proc; 

sum(p(k), k = 1 .. 1); 

sum(p(1), k = 1 .. 1); 

p(1)

Results must be same, but output is 0 (bug!), -1 (correct), -1 (correct)

Good morning.

I want to do a program in a worksheet that it can recall other workeet for plotting with display.

I don´t know how can recall other worksheets.

Please help me.

P.D.: I send a worksheet 01-06-2011-robot-man.mw

Like when I type

1/2^2;

it gives

1/4

but if I type

0.5^2;

it gives

0.25

I want it to consider 0.5 as 1/2, because sometimes I make computations on large equations and I want to have access to the symbolic output, not the numeric output.

Hi,

I have 5 docs with datas (x,y), like this one : BEF1txt

I want to put the 5 graphs side by side (parallels linears fonctions in a 3D graph). So I added the z data, z=1 in this case, and BEF2 got z=2, etc... But I am not able to make the 3D plot with the 5 linears fonction side by side.

May you help me please?

Thanks

Hello!

I have a problem that has to do with the function dsolve in Maple 14.

This is my code:

Good afternoon

I have just installed Maple on Linux - Ubuntu, but i have problems.

Please help me. how can i do



I want to use leibniz rule to differentiate the following Integral with variable domain:
A :=(t,x) -> int(Yt^2, x = 0 .. zeta);
Yt and zeta are defined as:
alias(zeta=zeta(t));
Yt:=(t,x)->diff(y(t,x),t);
When I want maple to derive D[1](A(t,x)), its answer is:
2*D[1](Yt)*Yt*Zeta+Yt^2*D[1](Zeta)
Although it uses Leibniz rule correctly, it dose not take Yt as a function of x by mistake. 2*D[1](Yt)*Yt*Zeta should had been derived as int(2*D[1](Yt)*Yt,x=0..zeta).

Hello:

I'm studying many time ago the quantum chemistry of rectivity . so far, I can arrive to news theories from my experince on Maple productcs as they are incorporated in my theoric equations. I have glad  on communicat my previous results on Chemical Reactivity and Uniffied Field. botn of those ara closely related and my purpose is obtain diffusion and comments on these.

- My first paper was on Chemical Reactivity (Kinetics and Dynamics) and...

with(Physics):with(combinat):
comn := choose([u, v, mu, nu], 2):

def := seq(seq(seq(Physics[`.`](Dagger(Ket(aa, k)), Ket(bb, m)) = Physics[`.`](Ket(bb, m), Dagger(Ket(aa, k))), `in`(aa, comn[i][1])), `in`(bb, comn[i][2])), i = 1 .. nops(comn)), seq(seq(seq(Dagger(Physics[`.`](Dagger(Ket(aa, k)), Ket(bb, m)) = Physics[`.`](Ket(bb, m), Dagger(Ket(aa, k)))), `in`(aa, comn[i][1])), `in`(bb, comn[i][2])), i = 1 .. nops(comn));
Setup(def):

d1 := Physics[`.`...

I have three different matrices, say A(3x6),B(3x6) and C(3x12) with the size of each matrix mentioned within parenthesis. I want to define a fourth matrix D (6x12) so that D=[A,B;C] (in Matlab notation). Can anyone please tell me how to define this D in Maple? Maple help seems not that helpful at least for beginners like me. Thank you in advance.

Hi,

I encountered the following problem in Maple 14

expr1:=sqrt(a)

assume(a>0)

expr2:=sqrt(a)

additionally(a>1)

subs(a=2,expr1) #gives correct answer of sqrt(2)

subs(a=2,expr2) #does not substitute a=2 in expr2

It seems the last statement with expr2 does not work as expected, I wondered why this behaviour is so, because it does work with expr1. The added assumption does not invalidate the first...

Hey all,

My question is better explained with an example

the algorithm I have here creates a matrix M[j] for each run of j.

I want to be able to export each of these matrices to a different spreadsheet and if possible, set up a naming critiria for each spreadsheet(so that I dont have to enter a name in the dialog box after each run)

Any suggestion will be really appreciated. Thanks

Lovinash

here's the example:

Hi everyone,

I have a 2nd order system which I want to solve. But the solver outputs no results after evaluation, just returns to the prompt. Do you know what I am doing wrong?

deq1:=diff(x[1](t),t$2)=k[1]/abs(x[2](t)-x[1](t))^2;
deq2:=diff(x[2](t),t$2)=k[2]/abs(x[2](t)-x[1](t))^2;
sys_ode:=deq1,deq2;
ICS:=x[1](0)=5, x[2](0)=10, D(x[1])(0)=0.1,D(x[2])(0)=0.2;
dsolve({sys_ode, ICS});

thanks.

Good morning.

I have a problem.

My Foco1 function is slower than Foco and how can i do it faster?, because that takes a long time.

26-05-2011-robot-man.mw

thank your for your answer