Level: Idiot (Me)

I have a matrix of 3 columns and lots of rows M

• First column is latitude in degrees
• Second column is longitude in degrees
• Third column is data

So I set lambda:=M(..,1) and phi_g:=M(..,2) giving me two column vectors.

I want to convert lambda and phi_g to polar coordinates theta and phi

theta:=90-lambda produces "Error, (in rtable/Sum) invalid arguments"

WHY?

I also want to convert phi_g to phi where phi=phi_g when phi_g is 0...180 and phi=phi_g +360 when phi_g <0

How do I create a conditional function like this?

How can I get the Automorphism Group of a group G as a Permutationgroup?

Best regards

Kurt Ewald

Hello,

this is the second time I'm writing.

I posted this question in June http://www.mapleprimes.com/questions/201781-System-Of-Parametric-Equations.

This time I have  a similar problem because I'm trying to find a solution for a parametric system of equations but the number of equations and parameters is much bigger and using the tips you gave me last time I couldn't reach any result.

Here is the system:

1) alpha[1]=v*a*u*b ;
2) alpha[2]=v*a*u*(1-b);
3) alpha[3]= v*z*c*(1-a) ;
4) alpha[4]=v*z*(1-a)*(1-c) ;
5) alpha[11]=1/2*v*a* u* b* (-p*u*b+p*u*b*a+b*g-g);
6) alpha[22]=1/2*v*a*u*(1-b)* (p u b-p u b a-b g-p u+p u a);
7) alpha[33] =1/2*v*c*z*(1-a)* (c* (-z*p*a+q)-q);
8) alpha[44]=1/2*v*z*((1-a)*(1-c)* (c*z*p*a-z*p*a-q*c);
9) alpha[12]=v*a*u*b*(1- b)*(-p*u+p*u*a+g) ;
10) alpha[13]=v*a*u*b*z*c*p*(1-a) ;
11) alpha[14]=a*u*b*z*(1-a)*(1-c) ;
12) alpha[23]=a*u*z*c*(1-a)*(1-b);
13) alpha[24]=v*a*u*z*p*(1-a)*(1-b)*(1-c);
14) alpha[34]= v*c*z*(1-a)*(1-c)*(-z*p*a+q);

I have 14 equations/unknowns and 8 parameters (a, b, c, u, v, z, p, q).

I would like to write this system only in terms of alphas. In order to do so, I usually try to find the value for the parameters and the substitute them into the equations (and I have already found b,c,g,q using this technique) but I couldn't manage to find all of them. 

Howveer, as you suggested me, with Maple there is the command "eliminate" that implement exactly what I'm looking for but I can't make it work.

This is my code:

> sys := {alpha[1] = v*a*u*(1-b), alpha[2] = v*a*u*b, alpha[3] = v*z*c*(1-a), alpha[4] = v*z*(1-a)*(1-c), alpha[11] = (1/2)*v*a*u*(1-b)*(p*u*b-p*u*b*a-b*g-p*u+p*u*a), alpha[12] = v*a*u*b*(1-b)*(-p*u+p*u*a+g), alpha[13] =      z*c*a*u*(1-a)*(1-b), alpha[14] = v*z*a*u*p*(1-a)*(1-b)*(1-c), alpha[22] = (1/2)*v*a*u*b*(-p*u*b+p*u*b*a+b*g-g), alpha[23] = v*z*c*a*u*b*p*(1-a), alpha[24] = z*a*u*b*(1-a)*(1-c), alpha[33] = (1/2)*v*c*z*(1-a)*(c*(-z*p*a+q)-q), alpha[34] = v*c*z*(1-a)*(1-c)*(-z*p*a+q), alpha[44] = (1/2)*v*z*(1-a)*(1-c)*(c*z*p*a-z*p*a-q*c)};

> eliminate(sys, {a,b,c, p, q, u, v, z});

> simplify(%, size);

I also tries to substitute in the system the four parameters I already found but still I can't find a solution.

What am I doing wrong? Or the problem is that it is too complicated?

Thank you for your attention,

Elena

We know that sum can return an symbolic summation, for example,

But sometime the relation of parameters in series cannot be defined easily. And it seems that sum cannot correctly determine the symbolic summation of this kind of series:

Maybe it's due to the value of _C(infinite) is undefined. Does anyone have good idea to compute the symbolic summation of this series?

I'd appreciate any help on this topic. Thank a lot.

sum_cannot_return_symbolic_summation.mw

Dear all,

I tried to display an animation which can zoom as the time goes.

But it seems that if I display several animations in one plot window, it will display the animation with the maximum view size from these animations, not separately display these animations with their view size.

There are two examples:

Case1,

a1 := animate(plot, [x^2, x = -1 .. t, view = [-1 .. 1, 0 .. 1]], t = -1 .. 1);

a2 := animate(plot, [x, x = -1 .. t, view = [-1 .. 1, -1 .. 1]], t = -1 .. 1);

display(a1, a2);

Case2,

animate(plot, [x^2, x = -1 .. 1, view = [t .. 1, 0 .. 1]], t = 0 .. -1)

Is it possible to zoom the animation with time? What parameter should I set?

The related maple file is attached.

zoom_animation_with_time.mw

When I enter the following code from the help file:

textplot3d([[1,2,3,"antelope", 'font'=["times","roman",20]], [3,2,1,"tiger"]], 'axes'='boxed', 'view'=[0..4, 0..4, 0..4]);

I receive the error message:

Plotting error, invalid FONT specification

I am trying to reduce the font size to fit many closely spaced strings in the plot.

Can anyone help.  I am running maple 16 on  Windows 7 machine.

Dear all, 

I'm trying to extract the coefficients from the equation below, the fat expressions in the equation. I don't have any trouble seperating the sine or cosine functions. But the constants are a problem. Since t is the only variable in the function i tried, coeff(R, t, 0). This does not work apparantly. Any suggestions? 

R:=(1/12)*C2^3*cos(2*t) - (1/48)*C2^3*cos(4*t) - C2^3*sin(t) + C2^3*sin(3*t)-C2^2*C4*cos(t) + C2^2*C4*cos(3*t) - (1/8)*C2^2*C4*sin(2*t) + (1/16)*C2^2*C4*sin(4*t) + (1/16)*C2*C4^2*cos(4*t) - C2*C4^2*sin(t) - C2*C4^2*sin(3*t) - C4^3*cos(t) - C4^3*cos(3*t) - (1/24)*C4^3*sin(2*t) - (1/48)*C4^3*sin(4*t) - (1/16)*C2^3 - (1/16)*C2*C4^2 - (1/2)*C2*cos(2*t) + C2*sin(t) + C4*cos(t) + (1/2)*C4*sin(2*t) + (1/2)*C2

It says at

http://www.maplesoft.com/products/maple/new_features/maple18/Language_Programming.aspx#random

"When generating matrices and vectors of floats and integers, these flavors are very fast. "

But when I compare the new

time[real](Generate(('Matrix')(float, 300, 300)))

and

time[real](RandomMatrix(300, 300))

I find RandomMatrix over 300 times faster. Am I doing something wrong, or is RandomMatrix still the fastest way to generate random numbers?

Hello everyone,

i'm trying to simulate a diffusion problem. It contains two connected regions in which a species is diffusing at different speeds. In one region (zeta) one boundary is set to be constant whereas in the other region (c) there is some oscillation at the boundary.The code i try to use is as follows:

sys1 := [diff(c(x, t), t) = gDiffusion*10^5*diff(c(x, t), x$2), diff(zeta(x, t), t) = KDiffusion*10^6*diff(zeta(x, t), x$2)]

pds := pdsolve(sys1, IBC, numeric, time = t, range = 0 .. 3000, spacestep = 3)

However the main problem are my boundary conditions:

IBC := {c(0, t) = 0, c(x > 0, 0) = 0, zeta(0, t) = .4, zeta(x > 0, 0) = .4, (D[1](c))(3000, t) = sin((1/100)*t), (D[1](zeta))(0, t) = 0}

Like this it principally works (however it is apparently ill-posed).

Now what i do like is that the two equations are coupled at x=2000 with the condition that c(2000,t)=zeta(2000,t). This however i dont seem to be able to implement.

I appreciate your comments

Goon

Hello, everyone.

There are two variables: n1 and n2, how to define n1+n2=1 (not n1:=1-n2).

Thanks!!

I have a Maple program that fits a nonlinear function with 9 parameters to a dataset that contains multiple records; each record gets fitted separately. The records are ordered by a certain experimental variable (an angle of a target). The initial parameters for each fit are the solutions of the previous fit; in this case I get relatively good initial estimates and not too much trouble fitting. I use Statistics:-NonLinearFit to do the actual fitting.

Since this is a bit time consuming and I need to do this a fair amount of times, I'd like to see if I can't speed his up by employing parallel programming.

One way to speed up a fit is to compute the sum of residuals in parallel; is there a way to do this in Maple?

Another way would be to run several fits at the same time. The problem I have with that in this case is that I use the results of the previous fit as starting values for the next fit. I might be able to increase the stride of this scheme; i.e. for 4 processes, use the result of fit 1 as starting point for fit 5; fit 2 for fit 6 etc. But before I embark on this non-trivial change; can Statistics:-NonLinearFit even be used in this way (i.e. is it thread safe)?? My fitting function is an actual function (as opposed to a procedure with local variables) so I don't think the function itself would cause trouble.

I could also contemplate the Grid package; except that I am concerned about the overhead moving the data over to each node (although it would all sit on one machine with 4 processors).

I realize that I may have to do some experimentation by myself, but if there is any experience out there I'd like to know about it...

Mac Dude

Everytime I re-run a workfile, I get several extra editing lines inbetween my own command lines. Have I missed something in my settings?

Best regards
Emilijan Vuletici

Basically I have to find omega by solving determinant of the following matrix:

M := Matrix(4, 4, {(1, 1) = 0, (1, 2) = -1, (1, 3) = 0, (1, 4) = 1, (2, 1) = -EI*beta^3, (2, 2) = -m*omega^2, (2, 3) = EI*beta^3, (2, 4) = -m*omega^2, (3, 1) = EI*sin(147*beta)*beta+k_r*cos(147*beta)+I*c_r*omega*cos(147*beta), (3, 2) = EI*cos(147*beta)*beta-k_r*sin(147*beta)-I*c_r*omega*sin(147*beta), (3, 3) = -EI*sinh(147*beta)*beta+k_r*cosh(147*beta)+I*c_r*omega*cosh(147*beta), (3, 4) = -EI*cosh(147*beta)*beta+k_r*sinh(147*beta)+I*c_r*omega*sinh(147*beta), (4, 1) = -EI*cos(147*beta)*beta^3+sin(147*beta)*k_h, (4, 2) = EI*sin(147*beta)*beta^3+cos(147*beta)*k_h, (4, 3) = EI*cosh(147*beta)*beta^3+sinh(147*beta)*k_h, (4, 4) = EI*sinh(147*beta)*beta^3+cosh(147*beta)*k_h}):

The remaining values are:

beta=((5000/10^12)*(omega^2))^(1/4),k_r=3.33*10^10,k_h=1.62*10^9,c_r=3.14*10^9,m=350000,L=147,EI=10^12:

What is the proper way to deal with this problem numerically. Or maybe it is even possible to get a reasonable analytical expression?

Maple evaluates

Int(ln(1+x)/(1+x^2),x=0..1);

as

1/2*I*dilog(1/2+1/2*I)-1/2*I*dilog(1/2-1/2*I)+1/4*Pi*ln(2)-Catalan

It would be nice if Maple could simplify this to 1/8*Pi*ln(2). If you evalf the integral and use "identify" then Maple does return 1/8*Pi*ln(2).

MMa directly returns 1/8*Pi*ln(2), which seems preferable.

Hello everyone.

I have a vector field in 2d-cartesian coordinates which I would like to convert to a "normal" function, that is f(x, y) where when you put x and y in, you get the magnitude of the vector at that point.

Example vector field:

This one is very hard to handle by hand which is why I want to use Maple for it.

I tried VectorCalculus[Norm] but it gave me this: