How i can generate P_r matrix when P_r = -x and x₀=-1 , x₁=-2/3 , x₂=-1/3 , and x₃=0 with the help loop?

Hi everybody:

I have one equation:

EQ := V^3-R*T*V^2/P-(B^2+P*B*R*T*sqrt(T)/(P-A))*V-A*B/(P*sqrt(T)) = 0;
how can I obtain these derivatives:

macros can be made to work like subs, you just need to know a few tricks to get it to work the same way.  macros just works in a slightly different manner and we can make it useful.

The difference is with subs, one has to keep specifying the substitution with each equation you want subbed, whereas macro will already have it defined.  As an example:

a := v^2*z^3 - 34/(5*x^2*sin(y*v^2)) + 36*v^2 - b*v^2 + 3^(v^2 - cos(v^2 + g))
                            

If we want to substitute h for v^2, then we would normally do this using subs

subs(v^2=h,a)
                          

however, we can also use macro

macro(v^2=h)
                                    

now it doesn't just automatically substitute those values so we need to coax maple a little bit.  We can do that by converting the equation to a string and parsing it.

parse(convert(a,string))
                     

so as you see we arrive at the same result.  Now there is a caveat using macro, if you've already defined a variable in a macro, subs will not work using the same variable sustitution - you first need to reset the variable in the macro back to itself. 

subs(v^2=h,a)
                      #doesn't work since the variable is defined in a macro

macro(v^2=v^2) #reset the variable in the macro

subs(v^2=h,a)
                         # now it works

we could also define a little procedure to simplify our typing, to have the macro variable work on our equation.

mvs:=proc(a) #macro variable substitution
  parse(convert(a,string));
end proc:

macro(v^2=h)
mvs(a)
            

now if we had some other existing equation before defining the macro
aa:=exp(v^2-sin(theta))+v^2*cos(theta)-1/x^sin(v^2-g)
                                   

we just have to simply apply our proc on the equation to apply the variable substitution
mvs(aa)
              

I just noticed with chagrin that one of my favorite menu commands, Edit -> Remove output -> From worksheet, is missing from Maple 2019's Standard GUI. Is there a keyboard command or toolbar item to replace it?

How can I plot Y in terms of X (Y is the vertical axis and X is the horizontal axis) in below equation with Maple?

X^3-24.478115*X^2/Y-(0.2038793409e-2+19.08455282*Y/(Y-97.539))*X-.2550630228/Y = 0

X:=0..50

Y:=0..1

How we can get matrix M with the help of loop?

Hello

Im solving a problem. When i use solve command maple dont give me whole of amswers it just give solve the obvious problem that is zero. what i should do to it give all of the answers not just zero?

Hi guys,

I'm very new to Maple and I'm trying to get  a 'diagonalisable' matrix set up.

It will help for me to attach what I currntly have for this to make sense:

What I currently have is a way of setting up a 5x5 matrix where it inserts a value at every instance where i=j, i=j+3 and i=j+6.

Currently I can only make this work for value from 1 to x and, for this to work, I basically need to make up a matrix that goes from -x to x

i.e currently I have x = 1 though 5 (5x5) and I need to set it up for x= -5 through 5 (11x11)

Every time I try and get the negative elements and 0 in there it tells me that I can't do it.

Is there any way to do this is Maple and am I going the wrong way about it?

Thanks very much for your time!

I'm using Maple on a compute server (via Putty from my computer which has windows system). It is an only-text mode server so it is a black screen and text and no menu bar to choose file and then save by clicking etc. You only can write commands and press Enter.

The IT section suggested to use writeto("filename.txt"), but I can't see any file on my drive, I used writeto("\drvename\filename.txt"), but still nothing.

Thanks to @acer , @Joe Riel and the IT section. The problem now is solved. It was about the way that I was writing the directory path. I had to add something before the "drivename" in my case. Plus that it is a Unix path, so I should use / not \.

Please check the value of T[1] ?

Hello, i am experiencing some problems when trying to open the maple 2018 software*
I have tried unistalling and download it again.
I have tried to search for sollution but there is very ittle intel
When i open Maple 2018 it just lingeres on the start up (pic below) and just disappears after 10 seconds

Can someone please help i have a very important examination upcoming

how we can get matrix of p[2],p[0] and p[1] when p[2]=1,p[0]=1 and  p[1]=-x and x[0]=-1,x[1]=-2/3 ,x[3]=0 when the general matrices of p are given below.....and answer should be p[2]=p[0]= identity matrix and p[1]= only diagonal values are 1,2/3,1/3,0..

Diff.(u(x,t), t$alpha) = 1/2. x^2. Diff(u(x,t),x$2), 0 <x <1, t >0, alpha =1.5  or  1.75

Bcs: u(0,t) = 0, u(1,t) = 1 + sinh t,

Ics: u(x,0) = x, u_t(x,0) = x^2 

restart;
F0:=proc(sigma__xx,N)
local  x,y,Fx,Fy,:
assume (w,real,w>0):assume (h,real,h>0):

for n from 0 by 2 to N do Fx:=integrate(sigma__xx*cos(w*Zeta*h),Zeta=0..infinity):
end do;
for n from 1 by 2 to N do Fx:=integrate(sigma__xx*sin(w*Zeta*h),Zeta=0..infinity):
end do;
return [Fx]:
end proc;

sigma__xx := -(sqrt(Zeta^2*h^2+h^2)^(-n+2)*cos(n*arctan(h, Zeta*h))*n^2+sqrt(Zeta^2*h^2+h^2)^(-n+2)*cos(n*arctan(h, Zeta*h))*n-2*sqrt(Zeta^2*h^2+h^2)^(-n+2)*cos(n*arctan(h, Zeta*h)))*Zeta^2*h^2/(Zeta^2*h^2+h^2)^2+(sqrt(Zeta^2*h^2+h^2)^(-n+2)*cos(n*arctan(h, Zeta*h))*n^2-3*sqrt(Zeta^2*h^2+h^2)^(-n+2)*cos(n*arctan(h, Zeta*h))*n;

F0(sigma__xx,N);

In Maple we can assign single named variables to values.  I was just wondering if it would be worthwhile if Maple could be set up to work with a multivariable assignment.  Not sure if my wording is understandable but hopefully someone can understand my point, or deter me from even thinking that way. 

Would it ever help in calculations in Maple if we were to make an assignment something like this :

v²:= a² + b²

or

a * b := 3*x + 5*y²

Haven't looked into it too hard, I'd like to know if there might be a situation where this type of assignment would be helpful.  I mean, does it make sense to do this kind of thing.  I wonder if there is a situation where this type of thing is useful, or maybe it's just impossible to work right anyway.  Maybe it's already been tried?  Thoughts?