Let f:Rⁿ  -> R^m a linear function i need help about a proc about matrix of the linear map Df(x),

our input will be n,m and f

such that,f:R²->R³ ,f(x,y,z)->(x+y,y+2z,x+y+z) and i wish resulting output with derivative matrix with respect to the standard bases in R² and R³

Though Maple provides routines to express integers or floating in different
integer bases the output looks not as nice as I want to have it.

And for example it does not work as expected using the 'simple ways' (while
for hex there is no simple way for floats):

  Digits:=16; # for all the following

  x:=frac(evalf(Pi)):
  x:= x* SFloat(1,-14);
              ...

This post gives equation of stability region of a Runge-Kutta ODE solver (Dormand-Prince45) as implicit domain equation and ODE-IVP.

Contents are:

• Runge-Kutta solver is implemented
• Solver is applied to test equation and growth factor is obtained
• Stability regions are defined by separating hyperplane (GF=growth factor=1)
• Stability regions are plotted by bruteforce approach (implicitplot)
• Boundary of stability regions...

Hi,

i try to use your code (i mean other way )   that give to me but it doesnot work. it give x[c] and y[r] at label.

i have maple 14 .

could you please help what is the problem?

last answer is wrtten by

It can be done with the labels option (see ?plot/options

^Hi,

I have a problem with plot using maple. I want to plot x_c agaist y_r 

However, i have no idea how to make at label that   y_r  . In other word, i want to make r under y and ignore dash (-) that between y and r

and the same idea for x_c.

could you please help me in this plot label problem?

0 = 0, -(1/16)*cos(l1)*cos(l2)*cos(l3)*cos(l4)*(-Pi*x3+4*cos(Pi*t)) = 0, -(1/16)*cos(l1)*cos(l2)*cos(l3)*cos(l4)*(-Pi*x2+4*sin(Pi*t)) = 0, (1/16)*cos(l1)*cos(l2)*cos(l3)*cos(l4) = 0, 0 = 0, -(1/8)*cos(l1)*cos(l3)*cos(l4)*(-Pi*x3+4*cos(Pi*t)) = 0, -(1/8)*cos(l1)*cos(l2)*cos(l4)*(-Pi*x2+4*sin(Pi*t)) = 0, (1/8)*cos(l1)*cos(l2)*cos(l3) = 0

After I ran solve({eq1, eq2, eq3, eq4, eq5, eq6, eq7, eq8}, {l1, l2, l3, l4, t, x1, x2, x3}, AllSolutions); I got...

Hello.

I was thinking about how I have used Maple for making animations. Thinking about it, I remembered an animation that I made to motivate the students of a calculus course. With this animation, I was searching to show the students the power of Maple.

I would like to see other animations for getting new and interesting ideas to show the students.

If you want to upload some animations, we could do a funny post with many animations.

Visualizing_the_SVD_.mw

Hola ev1:

I like to shorten the size of the command, through setoptions3d function. But it seems that it does not interact with ApplyLinearTransformPlot function.
How to get to label the vectors?

Gracias

> restart;

> with(plots);

BridgeHeight := 40;

BridgeFromCenter := 20;

BridgeToEdge := 35;

BridgeWidth := BridgeToEdge+BridgeFromCenter;

BridgeFromTheWater := 15;

BridgeLines := 10;

SpaceBetweenLines := 2*BridgeToEdge/BridgeLines;

LineStart := BridgeWidth;

CountLines := 0;

LineWidth := BridgeWidth;

while BridgeLines > CountLines do

CountLines := CountLines+1;

If i have the line:

S:=Sum( 1/16^k))*(4/(8*k+1)-2/ (8*k+4)-1/ (8*k+5)-1/ (8*k+6)), k=0..m);

and i want to establish the first m for which |Pi-Sm|<= 10^(-8)

when putting it into a while loop i get the error message that it cannot determine whether the expression is true or false:

while (Pi-S <= 10^(-8)) do

od;

etc,

what am i doing wrong here?

with(Optimization); nx := Maximize(abs(.5539395590*x^2+1.130864333*x+.9891410756-exp(x)), {-1. <= x, x <= 1.})

give [0.443368608590448687e-1, [x = 1.]]

but I know that it is not the maximum because:

abs(.5539395590*.56^2+1.130864333*.56+.9891410756-exp(.56))=0.045468048

with(Optimization); nx := maximize(abs((29.83428688*x-57.16914857)/(x-2.196093020)-exp(x)), x = 5.0 .. 6.0, location)

if we plot this function we see that the solution exists.

with(Optimization); nx := maximize(abs(.5547114632*x^2+1.130478381*x+.9883691714-exp(x)), x = -1 .. 1, location)

nx := 0.4568872387e-1, {[{x = 1.002012310}, 0.4568872387e-1]}

but 1.002 isn't in -1..1

I have a set of functions and parameters, I am computing Jacobian to those functions. I get a matrix rectangular in dimensions. So, determine Jacobian of sub-matrices(formed by removing one column for each sub-matrix) and equating them to zero.

> T := Matrix([[0], [4*t], [0]]); X := Matrix([[x1], [x2], [x3]]); R := Matrix([[1, 0, 0], [0, cos(pi*t), -sin(pi*t)], [0, sin(pi*t), cos(pi*t)]]);

> c1 := x1^2+x2^2-1/4-(1/4)*sin(l1); c2 := x3-sin(l2); c3 := t-1/2-(1/2)*sin(l3);>

In the help, a structure block diagram is given under the DynamicSystems[SystemConnect] command for the explaination of the use for the general connection,

that's intuitive and gives clear connections among every structure block,

so, I wonder whether there is a method to build that diagram or similar fig using the GraphTheory package,

that will be amazing,

is there a method? I want to know how to get it.