I have the equation: 4Unit(m)=3Unit(m)+p/(1000Unit(kg/m^3)*9.86Unit(m*s^-2)) I would like p to give med a result in Unit(bar). However, no matter which solve I use it gives me the answer: Error, (in Units:-Standard:-+) the units `m` and `m^2*s^2/kg` have incompatible dimensions I have tried every solve in the menu. if I make the equation myself I get: P=(4Unit(m)-3Unit(m))*(1000Unit(kg/m^3)*9.86Unit(m*s^-2)) And the answer: 9860Unit(Pa) Howcome maple 13 cannot do this for me?

Hi everyone,

I am having some trouble separting terms in a pretty gnarly PDE.  I have a fairly complicated 2+1 PDE with auxillary conditions that I am trying to solve with a formal separation of variables approach.  I have a PDE that looks like this:

Hello everybody,

I look for modeling an inverted pendulum in 2D. ( I would like to see the beam linking masses moving).

I have already calculated the equations of the motion. I know with MatLAB and Simulink a thing similar is possible but I would like to keep on using it Maple.

Is a such modeling is possible with Maple?

Many thanks,

Ternox

In this post I'll take a closer look at the ways in which Maple code can be thread unsafe. If you have not already seen my post on Thread Safety, consider reading that post first. As a brief review, a procedure is thread safe if it works correctly when run in parallel.

The most obvious way in which procedures can be thread unsafe is if they share data without synchronizing access (using a Mutex, for example). So how can two threads share data?

I uploaded to my file section a file called "Kill and Imprison Order""

Thanks to your help, this program works. I can specify an arbitrary order, such as [4,6,1,15] of players who kill or imprison other players. The program will then eliminate other players given player 4 gets to kill and imprison first, then player 6, and so on. However, I now need to test this in a for-loop over ALL permutations, or over a selected subset of the set of all permutations, of all the players.  Is that possible in Maple?

How do I delete files I have uploaded in my file section?

Is it possible to convert Pa*m^2 to Newton? (5) 13200. m Pa > convert(13200.*m^2*Pa, 'Units', 'N'); %; Error, (in Units:-Standard:-convert) unrecognized conversion > I don't know how to convert this to Newton (In maple), and I know that it is possible in the real world. Any help available? I know how to do it if I don't use maple or input my own units

help! How to make Maple cancel the common expressions in both
denominator and numerator?

As you could see, there is a g^(2/3) which is a common factor...

http://yfrog.com/0rexpression2j

I really want it to be removed.

Thanks a lot!

 

we have the following:

  CM := MultiSeries:-series((c[1]*e+c[2]*e^2+c[3]*e^3+c[4]*e^4+O(e^5))^m, e)

we have the following:

CM := MultiSeries:-series((c[1]*e+c[2]*e^2+c[3]*e^3+c[4]*e^4+O(e^5))^m, e)

CM := c[1]^m*e^m+c[2]*m*c[1]^m*e^(1+m)/c[1]+(1/2)*m*(2*c[3]*c[1]+c[2]^2*m-c[2]^2)*c[1]^m*e^(2+m)/c[1]^2+(1/6)*m*(6*c[4]*c[1]^2+6*c[3]*c[2]*c[1]*m-6*c[3]*c[2]*c[1]+c[2]^3*m^2-3*c[2]^3*m+2*c[2]^3)*c[1]^m*e^(3+m)/c[1]^3+O(e^(4+m))

Hi all,

 

I am helping a friend.

Please see the two expressions that we would like to convert from Maple into Matlab:

http://yfrog.com/jdexpression3j

 

In the first one, why doesn't Maple first calculate g1^(2/3) and g2^(2/3) as common expressions, then use them to calculate the whole expression?

The (0.1e1/0.3e1) stuff looks very bad.

 

In the second one, we just couldn't get Maple to cancel the common factor g1^(2/3) in both numerator and denominator before doing the conversion to Matlab.

Initial conditions,     x(0)=2, D(x(0))= -2

D= differential

D2x +5Dx +4x = delta( t - 2 )
 

 

I want to check my answer in maple but i cant get it to work.

 

This is the answer i gt by hand

 

x = H( t - 2 ) ( ( e ^ - 4 ( t - 2 ) + e ^ - ( t - 2) ) / 3 ) - 4 / 3 e ^ - 4 ( t - 2 ) + 10 / 3 e ^ - ( t - 2 )

 

I have this code and to test if it works in TextField1 next to the label "MATRIZ A" I enter

I'd like Maple to see that the derivative of p1 with respect to X includes p1 and p2

> p1 := exp(a*x)/(exp(a*x)+exp(b*x)+1);

> p2 := exp(b*x)/(exp(a*x)+exp(b*x)+1);
> m := eval(diff(p1, x));
> n := expand(m);
I see that algsubs won't work along the lines of

   algsubs(exp(a*x)/(exp(a*x)+exp(b*x)+1)=p1,n)

because the substitution is not a polynomial.

any other way to do this?