Having Maple 12 I try to use concurrent gfun version 3.52 and have problems
to run an example (from a lecture):

libname:= "D:\\_Work\\Maple_Work\\z_Packages\\gfun", libname; # my setting

with(gfun) : gfun:-version();
with(NumGfun) :
                                 3.52

Hi

I have a little problem, I tried to find out the Temperature of the Electrons in a Plasma,

the cross section name is sigma and I'm working with noble gases and there Threshold energies.

In the end I wand to find out  T_e but there comes only "Warning, solutions may have been lost"

Can anyone help me please?

Thank you very much

greetings from munich

  restart; interface(version); Digits:=14;

    Classic Worksheet Interface, Maple 12.02, Windows, Dec 10 2008 Build ID 377066

  f:= x -> (x+1)^(x+1);
  simplify(int(f(x),x)): 
  F:=unapply(%,x);
                                        (x + 1)

Hi

I want to solve this

2010.pdf 

Can anyone help me convert this outdated maple code into something current? Particularity I need help finding the equivalent command to "stats:-empirical" as I can't even find documentation for it.

with(stats): with(linalg): with(StringTools):

P1:=matrix([[.6,.3,.1],[.4,.5,.1],[.3,.4,.3]]);

j:=1:  res:="S":

for i to 50 do  

    j:=random[empirical[op(convert(row(P1,j),list))]](): 

I appreciate that maple can solve equations so quickly, but i would like to solve the equation myself and only use the basic features of maple so that I can practice the theory. For example:

for the differential equation y'' + 3y' + 2y = 0 

I would like to assume y = ce^rt then plug it in and get something like

c*(r^2*e^rt + 3r*e^rt + 2e^rt) = 0

maple runs into problems regarding:

-whether the parameters are functions or constants

Different...

Download problemexample.mw

Hello Maple wizards,

After reading the mapleprimes post http://www.mapleprimes.com/posts/36097-Add-Map-And-Seq on the hidden complexities of using thread-safe versions of add (Threads:-Add), I have been struggling to correct a problem similar to the "escaped k" problem described by Joel Riel...

I have a family of functions characterized by

f:=x^2+b*x+b*3;

I plotted some of them:

graph1:=x->subs(b=0,f):
graph2:=x->subs(b=2,f):
graph3:=x->subs(b=4,f):
plot([graph1(x),graph2(x),graph3(x)],x=-10..3,y=-5..15);

And now I want to draw a line through all maxima into the same diagram. The maxima have the coordinates (-1/2*b | -1/4*b^2+3*b). I managed to create a pointplot:

Hi friends,

I am running an application which consumes big memory (~2GB); and in the middle of calculation I got this error:

Kernel connection lost... and the message is:

Execution stopped: Memory allocation failed! Please see ?alloc for more details...

Please let me know how I can increase memory alocation capacity of maple (version: Maple 13)

Currently, using Explore results in a new worksheet which contains all the sliders and output components.

And there is code, which makes it all "work", that gets hidden in that new worksheet. But It's very awkward to copy those Components back to the original worksheet, because of the disassociation with the working code.

If, instead of having dependent code be hidden in that new worksheet in collapsed Document blocks, all the working code were instead inlined...

Hi guys,

I am new to Maple, so forgive my ignorance!

I need to define the implicit function R:=exp[(L/2)-(m/2R)] for use. When I attempt this the normal way, I get a 'recursive argument' error. How can I get round this?

Jimmy

I tried to carry out an advanced plotting task and I am not even sure, if Maple is able to do that.

In a Cartesian coordinate system with axis x=1..100 and y=0..1, I wanted to plot three graphs at once and have the parameters n, p and rho to be interactive.

Here are the graphs:

(1) y=1-exp(-rho*x);  #depending on x and rho

(2) y=-(1-p)^n+(p/(1-p)+1)^n*(1-p)^n+(1-p)^(n-1)*((exp(rho)*(-1+p)-p)*((exp(rho)*(-1+p)-p)/(exp(rho)*(-1+p)))^(n-1)-exp(rho...

with the following input:

with(VectorCalculus);

X := r -> sqrt(2/Pi)*alpha*exp(-alpha^2*(r.r));

a_0:=a*<1/(2*sqrt(3) , 1/2>;

r:=<x,y>;

K:=<k_1, k_2>;

assume(alpha::real);

assume(alpha>0);
assume(k_1>0);

assume(k_2>0);

assume(k_1::real);

assume(k_2::real);

eq1:=int( X(r-a_0) , x=-infinity .. infinity);

Why is the ouput :