Question: Coordinates of a point (4)

Let A(-2, -1, 3), B(0, 1, 4) be two point and

(d): x = -t-2, y = t+1, z = -t-1 be a line.

Find coordinates point M lies on (d) so that area of the triangle ABM equal to 3*sqrt(5).

This is my code

restart; with(LinearAlgebra):

A:=: B:=: M:=:

u:=A-B: v:=A-M:

T:=CrossProduct(u,v):

sol:=solve(1/2*Norm(T,2)=3*sqrt(5),{t});

for i from 1 to 2 do print('M'[i]=(subs(op(sol[i]), M[1]), subs(op(sol[i]), M[2]),subs(op(sol[i]), M[3]))) end do;

 

or

restart; with(LinearAlgebra):

A:=: B:=: M:=:

u:=A-B: v:=A-M:

T:=CrossProduct(u,v):

sol:=solve(1/2*Norm(T,2)=3*sqrt(5),{t});

for i from 1 to 2 do `M`[i]:=subs(sol[i],[-t-2, t+1, -t-1]) end do;

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