# Question:Warning: Warning, solutions may have been lost

## Question:Warning: Warning, solutions may have been lost

Maple

i have a problem in resolving this 5 equations eqn1 := (product(1-tau(i), i = 1 .. 4).delta.Delta.tau(0))*(1+(1/16)*(sum((16-j+1)/(g(0))(j), j = 1 .. 16))+(1-product(1-tau(i), i = 1 .. 4).delta.Delta).(1+(1/16)*(sum((16-j+1)/(g(0))(j), j = 1 .. 16)))+(1-product(1-tau(i), i = 1 .. 4).delta.Delta)^2.(1+(1/32)*(sum((32-j+1)/(g(0))(j), j = 1 .. 32)))+(1-product(1-tau(i), i = 1 .. 4).delta.Delta)^3.(1+(1/32)*(sum((32-j+1)/(g(0))(j), j = 1 .. 32)))+(1-product(1-tau(i), i = 1 .. 4).delta.Delta)^4.(1+(1/32)*(sum((32-j+1)/(g(0))(j), j = 1 .. 32))))/(1-(1-product(1-tau(i), i = 1 .. 4).delta.Delta)^3) = 1 eqn2 := (product(1-tau(i), i = 2 .. 4).(1-tau(0)).delta.Delta.tau(1))*(1+(1/8)*(sum((8-j+1)/(g(1))(j), j = 1 .. 8))+(1-product(1-tau(i), i = 2 .. 4).(1-tau(0)).delta.Delta).(1+(1/8)*(sum((8-j+1)/(g(1))(j), j = 1 .. 8)))+(1-product(1-tau(i), i = 2 .. 4).(1-tau(0)).delta.Delta)^2.(1+(1/16)*(sum((16-j+1)/(g(1))(j), j = 1 .. 16)))+(1-product(1-tau(i), i = 2 .. 4).(1-tau(0)).delta.Delta)^3.(1+(1/16)*(sum((16-j+1)/(g(1))(j), j = 1 .. 16)))+(1-product(1-tau(i), i = 2 .. 4).(1-tau(0)).delta.Delta)^4.(1+(1/16)*(sum((16-j+1)/(g(1))(j), j = 1 .. 16))))/(1-(1-product(1-tau(i), i = 2 .. 4).(1-tau(0)).delta.Delta)^3) = 1 eqn3 := ((1-tau(0)).(1-tau(1)).(1-tau(3)).(1-tau(4)).delta.Delta.tau(2))*(1+(1/4)*(sum((8-j+1)/(g(2))(j), j = 1 .. 4))+(1-(1-tau(0)).(1-tau(1)).(1-tau(3)).(1-tau(4)).delta.Delta).(1+(1/4)*(sum((4-j+1)/(g(2))(j), j = 1 .. 4)))+(1-(1-tau(0)).(1-tau(1)).(1-tau(3)).(1-tau(4)).delta.Delta)^2.(1+(1/8)*(sum((8-j+1)/(g(2))(j), j = 1 .. 8)))+(1-(1-tau(0)).(1-tau(1)).(1-tau(3)).(1-tau(4)).delta.Delta)^3.(1+(1/8)*(sum((8-j+1)/(g(2))(j), j = 1 .. 8)))+(1-(1-tau(0)).(1-tau(1)).(1-tau(3)).(1-tau(4)).delta.Delta)^4.(1+(1/8)*(sum((8-j+1)/(g(2))(j), j = 1 .. 8))))/(1-(1-f(2)*delta.Delta)^3) = 1 eqn4 := ((1-tau(0)).(1-tau(1)).(1-tau(2)).(1-tau(4)).delta.Delta.tau(3))*(1+(1/2)*(sum((2-j+1)/(g(3))(j), j = 1 .. 2))+(1-(1-tau(0)).(1-tau(1)).(1-tau(2)).(1-tau(4)).delta.Delta).(1+(1/2)*(sum((2-j+1)/(g(3))(j), j = 1 .. 2)))+(1-(1-tau(0)).(1-tau(1)).(1-tau(2)).(1-tau(4)).delta.Delta)^2.(1+(1/4)*(sum((4-j+1)/(g(3))(j), j = 1 .. 4)))+(1-(1-tau(0)).(1-tau(1)).(1-tau(2)).(1-tau(4)).delta.Delta)^3.(1+(1/4)*(sum((4-j+1)/(g(3))(j), j = 1 .. 4)))+(1-(1-tau(0)).(1-tau(1)).(1-tau(2)).(1-tau(4)).delta.Delta)^4.(1+(1/8)*(sum((8-j+1)/(g(3))(j), j = 1 .. 8))))/(1-(1-(1-tau(0)).(1-tau(1)).(1-tau(2)).(1-tau(4)).delta.Delta)^3) = 1 eqn5 := (f(4).delta.Delta.tau(4))*(1+(1*1)*(sum((1-j+1)/(g(4))(j), j = 1 .. 1))+(1-f(4)*delta.Delta).(1+(1*1)*(sum((1-j+1)/(g(4))(j), j = 1 .. 1)))+(1-f(4)*delta.Delta)^2.(1+(1/2)*(sum((2-j+1)/(g(4))(j), j = 1 .. 2)))+(1-f(4)*delta*Delta)^3.(1+(1/2)*(sum((2-j+1)/(g(4))(j), j = 1 .. 2)))+(1-f(4)*delta.Delta)^4.(1+(1/4)*(sum((4-j+1)/(g(4))(j), j = 1 .. 4))))/(1-(1-f(4)*delta.Delta)^3) = 1 then i tape : solve({eqn1, eqn2, eqn3, eqn4, eqn5}, {tau(0), tau(1), tau(2), tau(3), tau(4)}) i'm sorry for the long post , i'm blocked in this warning six days can any one help me please thanks a lot

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