Factoring summations with equivalent index

Question:Factoring summations with equivalent index

Posted: jscottelder 45 Product: Maple

September 27 2012

Given the following expression:

sum(cadj[i]*vfinal[i], i = c .. d)-(sum(cadj[i]*vinit[i], i = c .. d));

sum(cadj[i]*vfinal[i], i = c .. d)-(sum(cadj[i]*vinit[i], i = c .. d))

(1)

Why can't Maple simplify (1) to (2)?

sum(cadj[i]*(vfinal[i]-vinit[i]), i = c .. d);

sum(cadj[i]*(vfinal[i]-vinit[i]), i = c .. d)

(2)

Is there a "trick" or sequence to get the tool to make this observation?

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