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Question: evalf[d] and Digits

Question:evalf[d] and Digits

vv 11972 Maple
digits evalf
November 14 2017
1

A fact that seems to be not documented. Probably it should be obvious.

 

Digits := d0
evalf[d](expr);

 

The toplevel float sub-expressions in expr  are computed with Digits=d0 but in procedures Digits is set to d.
Notice that the actual float parameters of the toplevel procedures are evalf-ed with Digits=d0.

 

> 

restart;
> 

g:=proc() convert(1/3., string) end:
h:=proc() 1/3. end:
> 

Digits:=3;
evalf[10]([
  1/3. = h(),
  convert(1/3.,string) = g(),  
  fsolve(3*x=1) = add([1/3]),
  fsolve(x/3=1/9.) # 1/9. being at top level is evalf-ed with Digits=3
])

3

  

[.333 = .3333333333, ".333" = ".3333333333", .3333333333 = .3333333333, .3330000000]

 (1)
> 

 

> 

k:=proc(x) convert(x,string) end:
> 

kernelopts(floatPi);

true

 (2)
> 

4.+Pi;

7.14

 (3)
> 

evalf(k(1/3.+Pi));
# floatPi seems to be ignored inside actual parameters

".333+Pi"

 (4)
> 

evalf(k(4+evalf(Pi)));

"7.14"

 (5)
> 

evalf(k(4+Pi));
# 4 not being float (or "infected" by a float) is not evalf-ed

"4+Pi"

 (6)
> 

 

> 

### (this is documented)
> 

`evalf/h` := proc() 7.777 end:
> 

evalf(h(1/3));

.333

 (7)
> 

evalf('h'(1/3));

7.777

 (8)
> 

 

 

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(edited)
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