Question: Verify sum and integral

Hi all,

 

I am totally stuck in the question:

I can do it for seperate cases, but how to do it, with somekind of sequence

 

Integral for x= 0 to infinity of [2 sin(x/2)/x] ^ 2n 

this has to be equal to:

2n* pi (sum of [(-1)^j * (n-j)^(2n-1)] / [j! * (2n-j)!]

I showed it for j=0 and n=1

But how to do it for n =1,2,3 and 4

 

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