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Question: taylor( (2 * pi * n) ^ (1/(2n), n = infinity, 2)

Question:taylor( (2 * pi * n) ^ (1/(2n), n = infinity, 2)

Vitreg2 0 Maple
taylor
January 10 2019
0

The command

taylor( (2 * pi * n) ^ (1/(2n), n = 2)

return   1+((1/2)*ln(2*Pi)+(1/2)*ln(n))/n+O(1/n^2)

I think, this is incorrect, in my oppinion must be:

1+((1/2)*ln(2*Pi)+(1/2)*ln(n))/n+O(ln(n)^2/n^2)

Is this error in maple?

 
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