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Question: A question about making a really large answer into a short one

Question:A question about making a really large answer into a short one

The function 110 Maple
integration
November 08 2021
1

Hello everyone!

I made an integration and it gave me a really long answer. The answer of the book is the same, as you can see, i "smartplotted" the two answers, and they are the same. But how do i get the nice short answer? I tried a lot of different things, but nothing gave me that short answer. 

I would really like to be able to get nice short answers, while it will really clean things up. 

Thank you!

Greetings,

The Function

> 

int((v^2-1)*(v^3-3*v+6)^5, v)

(1/18)*v^18-v^16+2*v^15+(15/2)*v^14-30*v^13+180*v^11-(585/2)*v^10-300*v^9+1539*v^8-1350*v^7-(4239/2)*v^6+5994*v^5-4050*v^4-3888*v^3+9720*v^2-7776*v

 (1)
> 

NULL
> 

"f(v):=1/18 v^18-v^16+2 v^15+15/2 v^14-30 v^13+180 v^11-585/2 v^10-300 v^9+1539 v^8-1350 v^7-4239/2 v^6+5994 v^5-4050 v^4-3888 v^3+9720 v^2-7776 v"

proc (v) options operator, arrow, function_assign; (1/18)*v^18-v^16+2*v^15+(15/2)*v^14-30*v^13+180*v^11-(585/2)*v^10-300*v^9+1539*v^8-1350*v^7-(4239/2)*v^6+5994*v^5-4050*v^4-3888*v^3+9720*v^2-7776*v end proc

 (2)
> 

"f1(v):=1/(18)*(v^(3)-3 v+6)^(6)"

proc (v) options operator, arrow, function_assign; (1/18)*(v^3-3*v+6)^6 end proc

 (3)
> 

smartplot(f(v), f1(v))

 
> 

(1/18)*v^18-v^16+2*v^15+(15/2)*v^14-30*v^13+180*v^11-(585/2)*v^10-300*v^9+1539*v^8-1350*v^7-(4239/2)*v^6+5994*v^5-4050*v^4-3888*v^3+9720*v^2-7776*v

(1/18)*v^18-v^16+2*v^15+(15/2)*v^14-30*v^13+180*v^11-(585/2)*v^10-300*v^9+1539*v^8-1350*v^7-(4239/2)*v^6+5994*v^5-4050*v^4-3888*v^3+9720*v^2-7776*v

 (4)
> 

(1/18)*(v^3-3*v+6)^6

(1/18)*(v^3-3*v+6)^6

 (5)
> 

``
> 

``

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