Question: Solve this: Write down the series 1-x-x²-x³+ ... in sigma notation

A general term for this series is+-xr, having a positive sign when r is even and a negative sign when r is odd.

​​​​Now because (-1) is positive when r is even and negative when r is odd, the general term can be written as (-1)rxr

Hence;

1-x+x2-x3+...=£or=0(-1)r(x)r

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