Question: (0=a) as a constant

I found in the Advanced Engineering Mathematics we have the statement: qq3 := map(int,qq2,x)+(0=a); 1 - ln(2 y(x) + 1) = ln(x) + a 2 which integrates the expression qq2 and then adds a constant. What does (0=a) mean and why does it differ from just adding a? Whenever I try and use it I get this: > int1 := (2*x^2+4)*sin(x): > ans1b := map(int, int1, x)+(0 = c); -(2/3*x^3 + 4 x)*cos(x) = c - (2/3*x^3 + 4 x)* cos(x) What's goin on?
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