convert Arg[I*Sinh[1 + I]]to Pi - ArcTan[Cot[Abs[Tanh[1 - I]]]]

Question:convert Arg[I*Sinh[1 + I]]to Pi - ArcTan[Cot[Abs[Tanh[1 - I]]]]

Posted: Euclid 698 Product: Maple

January 10 2010

arg(I*sinh(1+I))

arctan(cot(abs(tanh(1-I))))

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