Question: how to get z but (z^6)^(1/6)

c := proc (n) options operator, arrow; z^n/factorial(n) end proc

limit(c(n)^(1/n), n = infinity),

limit(c(n)^(1/n), n = 6)


eval(limit((z^n/factorial(n))^(1/n), n = 6))=(1/60)*12^(2/3)*5^(5/6)*(z^6)^(1/6)
 


evalf(limit((z^n/factorial(n))^(1/n), n = 6))=.3340241884*(z^6)^(1/6)
 

how to get z but (z^6)^(1/6)

 

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