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Question: LegendreQ(1,x)

Question:LegendreQ(1,x)

SandorSzabo 607 Maple
convert
December 12 2008
0

By Maple

convert(LegendreQ(1,x),hypergeom)

hypergeom([1, 3/2], [5/2], 1/x^2)/(3*x^2)

LegendreQ(1,0.)

-1.000000000-3.141592654*10^(-15)*I

The 2F1 form suggests for me that in x=0 LegendreQ is infinite or at least undetermined. So what is the truth?

I work with LegendreQ(1,x) where x is real.

Thanks,

                      Sandor

 
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